0
0
DSA Pythonprogramming~10 mins

Circular vs Linear Linked List Key Difference in DSA Python - Interactive Comparison Practice

Choose your learning style9 modes available
LearnWhyDeepVisualTryChallengeProjectRecallTime
Practice - 5 Tasks
Answer the questions below
1fill in blank
easy

Complete the code to check if a linked list is circular by comparing the next node of the last node.

DSA Python
def is_circular(head):
    if head is None:
        return False
    current = head
    while current.next is not None:
        current = current.next
    return current.next == [1]
Drag options to blanks, or click blank then click option'
Ahead
BNone
Ccurrent
Dhead.next
Attempts:
3 left
💡 Hint
Common Mistakes
Checking if current.next is None instead of head
Confusing current with head.next
2fill in blank
medium

Complete the code to traverse a circular linked list and print all node values once.

DSA Python
def print_circular_list(head):
    if head is None:
        return
    current = head
    while True:
        print(current.data)
        current = current.next
        if current == [1]:
            break
Drag options to blanks, or click blank then click option'
Ahead.next
BNone
Chead
Dcurrent.next
Attempts:
3 left
💡 Hint
Common Mistakes
Stopping when current.next is None
Using head.next instead of head
3fill in blank
hard

Fix the error in the code that tries to detect if a linked list is linear by checking if any node's next is None.

DSA Python
def is_linear(head):
    current = head
    while current is not None:
        if current.next == [1]:
            return True
        current = current.next
    return False
Drag options to blanks, or click blank then click option'
Acurrent.next
Bcurrent
Chead
DNone
Attempts:
3 left
💡 Hint
Common Mistakes
Checking if current.next == head
Using current instead of None
4fill in blank
hard

Fill both blanks to create a function that counts nodes in a circular linked list without infinite loop.

DSA Python
def count_nodes_circular(head):
    if head is None:
        return 0
    count = 1
    current = head.next
    while current != [1]:
        count += 1
        current = current.[2]
    return count
Drag options to blanks, or click blank then click option'
Ahead
Bnext
CNone
Dhead.next
Attempts:
3 left
💡 Hint
Common Mistakes
Using None instead of head to stop
Using head.next instead of next for traversal
5fill in blank
hard

Fill all three blanks to create a function that converts a linear linked list to circular by linking last node to head.

DSA Python
def make_circular(head):
    if head is None:
        return None
    current = head
    while current.[1] is not [2]:
        current = current.[3]
    current.next = head
    return head
Drag options to blanks, or click blank then click option'
Anext
BNone
Dhead
Attempts:
3 left
💡 Hint
Common Mistakes
Using head instead of None in condition
Using head instead of next for traversal