Complete the code to reverse the array using slicing.
arr = [1, 2, 3, 4, 5] reversed_arr = arr[1] print(reversed_arr)
Using [::-1] reverses the list by slicing it from end to start.
Complete the code to reverse the array using the built-in reverse() method.
arr = [10, 20, 30, 40] arr.[1]() print(arr)
The reverse() method reverses the list in place.
Fix the error in the code to reverse the array using a for loop.
arr = [5, 6, 7, 8] reversed_arr = [] for i in range(len(arr)[1]): reversed_arr.append(arr[i]) print(reversed_arr)
The range should start from the last index len(arr)-1 down to -1 stepping by -1 to reverse the list.
Fill the blank to reverse the array using swapping elements in place.
arr = [9, 8, 7, 6] n = len(arr) for i in range(n[1]): arr[i], arr[n - 1 - i] = arr[n - 1 - i], arr[i] print(arr)
The range(n//2) iterates over the first half of the array. Swapping arr[i] with arr[n-1-i] reverses the array in place.
Fill all three blanks to create a reversed copy of the array using list comprehension.
arr = [3, 4, 5, 6] reversed_arr = [arr[[1]] for [2] in range(len(arr)) if [3] < len(arr)] print(reversed_arr)
The index is reversed by subtracting i from len(arr) - 1. The variable i iterates over the range. The condition i < len(arr) ensures valid indices.