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DSA C++programming~10 mins

Radix Sort Algorithm in DSA C++ - Interactive Practice

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Practice - 5 Tasks
Answer the questions below
1fill in blank
easy

Complete the code to get the maximum value in the array for Radix Sort.

DSA C++
int getMax(int arr[], int n) {
    int max = arr[0];
    for (int i = 1; i < n; i++) {
        if (arr[i] [1] max) {
            max = arr[i];
        }
    }
    return max;
}
Drag options to blanks, or click blank then click option'
A>
B<
C==
D<=
Attempts:
3 left
💡 Hint
Common Mistakes
Using '<' instead of '>' causes the max to never update correctly.
2fill in blank
medium

Complete the code to count the occurrences of digits for the current place value in Counting Sort used by Radix Sort.

DSA C++
void countSort(int arr[], int n, int exp) {
    int output[n];
    int count[10] = {0};

    for (int i = 0; i < n; i++) {
        count[(arr[i] / [1]) % 10]++;
    }
    // rest of the code...
}
Drag options to blanks, or click blank then click option'
Aexp
Barr[i]
Cn
D10
Attempts:
3 left
💡 Hint
Common Mistakes
Using 10 instead of exp will always count the units digit only.
3fill in blank
hard

Fix the error in the loop that builds the output array in Counting Sort for Radix Sort.

DSA C++
for (int i = n - 1; i >= 0; i--) {
    output[count[(arr[i] / exp) % 10] [1]] = arr[i];
    count[(arr[i] / exp) % 10]--;
}
Drag options to blanks, or click blank then click option'
A+
B-
C*
D/
Attempts:
3 left
💡 Hint
Common Mistakes
Using '+' will cause index overflow and incorrect placement.
4fill in blank
hard

Fill both blanks to copy the output array back to the original array after Counting Sort step.

DSA C++
for (int i = 0; i [1] n; i++) {
    arr[i] = [2][i];
}
Drag options to blanks, or click blank then click option'
A<
B<=
Coutput
Dcount
Attempts:
3 left
💡 Hint
Common Mistakes
Using '<=' causes out-of-bounds error.
Copying from count instead of output causes wrong data.
5fill in blank
hard

Fill all three blanks to complete the main Radix Sort loop that calls Counting Sort for each digit place.

DSA C++
void radixSort(int arr[], int n) {
    int m = getMax(arr, n);

    for (int exp = 1; exp [1] m; exp = exp [2] 10) {
        countSort(arr, n, [3]);
    }
}
Drag options to blanks, or click blank then click option'
A>
B*
Cexp
D<=
Attempts:
3 left
💡 Hint
Common Mistakes
Using '>' instead of '<=' causes the loop to never run.
Passing m instead of exp to countSort causes wrong sorting.

Practice

(1/5)
1. What is the main idea behind the Radix Sort algorithm?
easy
A. Sort numbers digit by digit starting from the least significant digit
B. Compare each element with every other element and swap if needed
C. Divide the array into halves and sort each half recursively
D. Use a pivot element to partition the array and sort partitions

Solution

  1. Step 1: Understand Radix Sort approach

    Radix Sort sorts numbers by processing individual digits starting from the least significant digit (rightmost) to the most significant digit (leftmost).
  2. Step 2: Compare with other sorting methods

    Other options describe Bubble Sort, Merge Sort, and Quick Sort, which are different algorithms.
  3. Final Answer:

    Sort numbers digit by digit starting from the least significant digit -> Option A
  4. Quick Check:

    Radix Sort = Digit by digit sorting [OK]
Hint: Radix Sort processes digits from right to left [OK]
Common Mistakes:
  • Confusing Radix Sort with comparison-based sorts
  • Thinking it sorts from most significant digit first
  • Assuming it uses swapping of elements
2. Which of the following is the correct way to extract the digit at position pos (starting from 0 for least significant digit) from an integer num in C++?
easy
A. (num / (10 * pos)) % 10
B. ((num / (int)pow(10, pos)) % 10)
C. (num % (10 * pos)) / 10
D. (num % pow(10, pos)) / 10

Solution

  1. Step 1: Understand digit extraction formula

    To get the digit at position pos, divide num by 10^pos and then take modulo 10.
  2. Step 2: Check each option

    ((num / (int)pow(10, pos)) % 10 correctly uses pow(10, pos) for exponentiation and modulo 10 to get the digit.
  3. Final Answer:

    ((num / (int)pow(10, pos)) % 10) -> Option B
  4. Quick Check:

    Digit extraction = (num / 10^pos) % 10 [OK]
Hint: Divide by 10^pos then mod 10 to get digit [OK]
Common Mistakes:
  • Using multiplication instead of exponentiation
  • Incorrect order of operations
  • Using modulo before division
3. What will be the output of the following C++ code snippet using Radix Sort on array arr = {170, 45, 75, 90, 802, 24, 2, 66}?
void countingSort(int arr[], int n, int exp) {
    int output[n];
    int count[10] = {0};
    for (int i = 0; i < n; i++)
        count[(arr[i] / exp) % 10]++;
    for (int i = 1; i < 10; i++)
        count[i] += count[i - 1];
    for (int i = n - 1; i >= 0; i--) {
        output[count[(arr[i] / exp) % 10] - 1] = arr[i];
        count[(arr[i] / exp) % 10]--;
    }
    for (int i = 0; i < n; i++)
        arr[i] = output[i];
}

void radixSort(int arr[], int n) {
    int maxVal = *max_element(arr, arr + n);
    for (int exp = 1; maxVal / exp > 0; exp *= 10)
        countingSort(arr, n, exp);
}

int main() {
    int arr[] = {170, 45, 75, 90, 802, 24, 2, 66};
    int n = sizeof(arr) / sizeof(arr[0]);
    radixSort(arr, n);
    for (int i = 0; i < n; i++)
        cout << arr[i] << " ";
    return 0;
}
medium
A. 24 2 45 66 75 90 170 802
B. 802 170 90 75 66 45 24 2
C. 2 24 45 66 75 90 170 802
D. 2 24 45 75 66 90 170 802

Solution

  1. Step 1: Understand Radix Sort steps on given array

    Radix Sort sorts by digits: first units, then tens, then hundreds. After full sorting, array becomes sorted ascending.
  2. Step 2: Trace final sorted array

    Sorted array is: 2 24 45 66 75 90 170 802.
  3. Final Answer:

    2 24 45 66 75 90 170 802 -> Option C
  4. Quick Check:

    Radix Sort final output = sorted array ascending [OK]
Hint: Radix Sort outputs fully sorted array ascending [OK]
Common Mistakes:
  • Confusing intermediate steps with final output
  • Misordering numbers with same digits
  • Ignoring stable sorting in countingSort
4. Identify the bug in the following Radix Sort counting sort implementation and select the correct fix:
void countingSort(int arr[], int n, int exp) {
    int output[n];
    int count[10] = {0};
    for (int i = 0; i < n; i++)
        count[(arr[i] / exp) % 10]++;
    for (int i = 1; i < 10; i++)
        count[i] += count[i - 1];
    for (int i = 0; i < n; i++) {
        output[count[(arr[i] / exp) % 10] - 1] = arr[i];
        count[(arr[i] / exp) % 10]--;
    }
    for (int i = 0; i < n; i++)
        arr[i] = output[i];
}
medium
A. Change the last for loop to iterate from n-1 down to 0 for stable sorting
B. Initialize count array with -1 instead of 0
C. Remove the cumulative sum loop for count array
D. Replace output array with a vector for dynamic sizing

Solution

  1. Step 1: Identify stable sorting requirement in counting sort

    Counting sort must process elements from right to left to maintain stability.
  2. Step 2: Check the for loop direction

    Current loop goes from 0 to n-1, which breaks stability. Changing it to n-1 down to 0 fixes this.
  3. Final Answer:

    Change the last for loop to iterate from n-1 down to 0 for stable sorting -> Option A
  4. Quick Check:

    Stable counting sort = reverse iteration [OK]
Hint: Counting sort must iterate backward for stability [OK]
Common Mistakes:
  • Iterating forward breaks stable sorting
  • Misunderstanding count array initialization
  • Ignoring cumulative sum step
5. Given an array of strings representing numbers with leading zeros, e.g., {"002", "010", "001", "100"}, how can you adapt Radix Sort to correctly sort them as numbers?
hard
A. Use counting sort only on the first character of each string
B. Sort strings lexicographically using Radix Sort on characters
C. Ignore leading zeros and sort strings as-is with Radix Sort
D. Convert strings to integers first, then apply Radix Sort on integers

Solution

  1. Step 1: Understand sorting numeric strings with leading zeros

    Sorting strings lexicographically will not sort numbers correctly if leading zeros exist.
  2. Step 2: Convert strings to integers for numeric sorting

    Convert strings to integers to remove leading zeros, then apply Radix Sort on integers for correct numeric order.
  3. Final Answer:

    Convert strings to integers first, then apply Radix Sort on integers -> Option D
  4. Quick Check:

    Numeric string sorting = convert to int then Radix Sort [OK]
Hint: Convert strings to int before Radix Sort for numeric order [OK]
Common Mistakes:
  • Sorting strings lexicographically causes wrong order
  • Ignoring leading zeros impact
  • Using only first character for sorting
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