Applying loads (forces, pressures) in Solidworks - Cell-by-Cell Formula Trace

Sample Data

This table shows two types of loads applied in SolidWorks: a force of 1000 N in the X direction and a pressure of 500 Pa applied over an area of 2 m².

Cell	Value
A1	Load Type
B1	Magnitude
C1	Direction
D1	Area
A2	Force
B2	1000
C2	X
D2
A3	Pressure
B3	500
C3	Normal
D3	2

Formula Trace

Total Load = Force + (Pressure × Area)

Step 1: Force

Step 2: Pressure × Area

Step 3: Total Load = 1000 N + 1000 N

Cell Reference Map

    A        B        C        D
1 |Load Type|Magnitude|Direction|Area   |
2 |Force    |1000     |X        |       |
3 |Pressure |500      |Normal   |2      |

References:
- Force magnitude in B2
- Pressure magnitude in B3
- Area in D3

The formula uses the force magnitude from cell B2, pressure magnitude from B3, and area from D3 to calculate total load.

Result

    A        B        C        D        E
1 |Load Type|Magnitude|Direction|Area     |Total Load|
2 |Force    |1000     |X        |         |          |
3 |Pressure |500      |Normal   |2        |          |
4 |         |         |         |         |2000 N    |

The total load of 2000 Newtons is shown in cell E4, representing the sum of the force and the pressure force applied.

Sheet Trace Quiz - 3 Questions

What is the value of the force load used in the calculation?

A 2 N

B 500 N

C 1000 N

D 2000 N

Key Result

Total Load equals sum of direct force and pressure multiplied by area.

Practice

1.

What is the main purpose of applying loads in SolidWorks simulations?

easy

A. To simulate how forces affect the design's strength and behavior

B. To change the color of the model

C. To create new parts automatically

D. To export the design to other software

Solution

1. Step 1: Understand the role of loads in simulation

   Loads represent forces or pressures applied to a model to test its response.

2. Step 2: Identify the purpose of applying loads

   Applying loads helps predict stress, deformation, and failure points in the design.

3. Final Answer:

   To simulate how forces affect the design's strength and behavior -> Option A

4. Quick Check:

   Loads test design behavior = A [OK]

Hint: Loads simulate forces on design to check strength [OK]

Common Mistakes:

• Thinking loads change model appearance
• Confusing loads with part creation
• Assuming loads export data

2.

Which of the following is the correct way to apply a Force load in SolidWorks Simulation?

easy

A. Draw a sketch and convert it to a force

B. Select the entire model and click 'Apply Pressure'

C. Use the 'Mesh' tool to add force values

D. Select the face, then specify magnitude and direction of the force

Solution

1. Step 1: Identify how to apply a force load

   In SolidWorks, you select the face or edge where the force acts.

2. Step 2: Specify force details

   You enter the force magnitude and direction after selecting the location.

3. Final Answer:

   Select the face, then specify magnitude and direction of the force -> Option D

4. Quick Check:

   Force load = select face + magnitude/direction [OK]

Hint: Force load needs face selection and magnitude input [OK]

Common Mistakes:

• Applying pressure instead of force
• Selecting whole model instead of face
• Using mesh tool incorrectly

3.

Given a cantilever beam fixed at one end, if a downward force of 100 N is applied at the free end, what is the expected effect on the beam?

medium

A. The beam will bend downward causing stress near the fixed end

B. The beam will compress uniformly along its length

C. The beam will expand and lengthen

D. The beam will rotate without bending

Solution

1. Step 1: Understand cantilever beam behavior under load

   A force at the free end causes bending with maximum stress at the fixed end.

2. Step 2: Analyze the effect of downward force

   The beam bends downward, creating tension and compression zones, especially near the fixed support.

3. Final Answer:

   The beam will bend downward causing stress near the fixed end -> Option A

4. Quick Check:

   Cantilever + end force = bending stress at fixed end [OK]

Hint: Force at free end bends cantilever near fixed end [OK]

Common Mistakes:

• Assuming uniform compression
• Thinking beam lengthens
• Ignoring bending and only rotation

4.

In a SolidWorks simulation, a user applies a pressure load but the simulation shows zero deformation. What is the most likely error?

medium

A. The pressure magnitude was set too high

B. The pressure was applied to a fixed face with no degrees of freedom

C. The mesh size was too small

D. The material was set to plastic

Solution

1. Step 1: Identify why zero deformation occurs

   If the load is on a fixed face, the model cannot move or deform there.

2. Step 2: Understand fixed constraints effect

   Fixed constraints prevent movement, so pressure on that face causes no deformation.

3. Final Answer:

   The pressure was applied to a fixed face with no degrees of freedom -> Option B

4. Quick Check:

   Pressure on fixed face = zero deformation [OK]

Hint: Check if load is on fixed (immovable) face [OK]

Common Mistakes:

• Assuming high pressure causes zero deformation
• Thinking mesh size causes no deformation
• Confusing material type with deformation

5.

You want to simulate the effect of wind pressure on a car door in SolidWorks. Which combination of load types and locations is best?

hard

A. Apply a force load at the door handle only

B. Apply a torque load on the door hinges

C. Apply a uniform pressure load on the outer surface of the door

D. Apply a pressure load inside the door cavity

Solution

1. Step 1: Identify the nature of wind load

   Wind applies pressure distributed over the outer surface of the door.

2. Step 2: Choose appropriate load type and location

   A uniform pressure load on the door's outer surface best simulates wind effect.

3. Final Answer:

   Apply a uniform pressure load on the outer surface of the door -> Option C

4. Quick Check:

   Wind = uniform pressure on outer surface [OK]

Hint: Wind acts as pressure on outer surface, not force at one point [OK]

Common Mistakes:

• Applying force only at handle
• Using torque on hinges for wind
• Applying pressure inside door cavity