Understand how applying different loads like forces and pressures affects the stress and displacement in a mechanical part.
Applying loads (forces, pressures) in Solidworks - Dashboard Guide
| Load Case | Load Type | Magnitude (N or Pa) | Location | Resulting Max Stress (MPa) | Max Displacement (mm) |
|---|---|---|---|---|---|
| 1 | Force | 1000 N | Center | 50 | 2.5 |
| 2 | Force | 1500 N | End | 70 | 3.8 |
| 3 | Pressure | 5000 Pa | Surface | 30 | 1.2 |
| 4 | Pressure | 8000 Pa | Surface | 45 | 1.8 |
| 5 | Force | 2000 N | Center | 90 | 4.0 |
- KPI Card: Max Stress
Shows the highest max stress value from the load cases.
Formula: MAX([Resulting Max Stress (MPa)]) = 90 MPa - KPI Card: Max Displacement
Shows the highest displacement value.
Formula: MAX([Max Displacement (mm)]) = 4.0 mm - Bar Chart: Stress by Load Case
X-axis: Load Case
Y-axis: Resulting Max Stress (MPa)
Shows stress for each load case. - Bar Chart: Displacement by Load Case
X-axis: Load Case
Y-axis: Max Displacement (mm)
Shows displacement for each load case. - Table: Load Details
Shows Load Case, Load Type, Magnitude, and Location for reference.
+----------------------+----------------------+ | Max Stress (KPI) | Max Displacement (KPI)| +----------------------+----------------------+ | Stress by Load Case (Bar Chart) | | | +------------------------------------------+ | Displacement by Load Case (Bar Chart) | | | +------------------------------------------+ | Load Details (Table) | +------------------------------------------+
Filter by Load Type (Force or Pressure):
- When selecting Force, all charts and KPIs update to show only force load cases (1, 2, 5).
- When selecting Pressure, components update to show only pressure load cases (3, 4).
- Filter affects KPI cards, bar charts, and the load details table simultaneously.
If you add a filter for Load Type = Pressure, which components update and what is the new Max Stress KPI value?
- Updated components: Max Stress KPI, Max Displacement KPI, Stress by Load Case chart, Displacement by Load Case chart, Load Details table.
- New Max Stress KPI value: 45 MPa (from load case 4).
Practice
What is the main purpose of applying loads in SolidWorks simulations?
Solution
Step 1: Understand the role of loads in simulation
Loads represent forces or pressures applied to a model to test its response.Step 2: Identify the purpose of applying loads
Applying loads helps predict stress, deformation, and failure points in the design.Final Answer:
To simulate how forces affect the design's strength and behavior -> Option AQuick Check:
Loads test design behavior = A [OK]
- Thinking loads change model appearance
- Confusing loads with part creation
- Assuming loads export data
Which of the following is the correct way to apply a Force load in SolidWorks Simulation?
Solution
Step 1: Identify how to apply a force load
In SolidWorks, you select the face or edge where the force acts.Step 2: Specify force details
You enter the force magnitude and direction after selecting the location.Final Answer:
Select the face, then specify magnitude and direction of the force -> Option DQuick Check:
Force load = select face + magnitude/direction [OK]
- Applying pressure instead of force
- Selecting whole model instead of face
- Using mesh tool incorrectly
Given a cantilever beam fixed at one end, if a downward force of 100 N is applied at the free end, what is the expected effect on the beam?
Solution
Step 1: Understand cantilever beam behavior under load
A force at the free end causes bending with maximum stress at the fixed end.Step 2: Analyze the effect of downward force
The beam bends downward, creating tension and compression zones, especially near the fixed support.Final Answer:
The beam will bend downward causing stress near the fixed end -> Option AQuick Check:
Cantilever + end force = bending stress at fixed end [OK]
- Assuming uniform compression
- Thinking beam lengthens
- Ignoring bending and only rotation
In a SolidWorks simulation, a user applies a pressure load but the simulation shows zero deformation. What is the most likely error?
Solution
Step 1: Identify why zero deformation occurs
If the load is on a fixed face, the model cannot move or deform there.Step 2: Understand fixed constraints effect
Fixed constraints prevent movement, so pressure on that face causes no deformation.Final Answer:
The pressure was applied to a fixed face with no degrees of freedom -> Option BQuick Check:
Pressure on fixed face = zero deformation [OK]
- Assuming high pressure causes zero deformation
- Thinking mesh size causes no deformation
- Confusing material type with deformation
You want to simulate the effect of wind pressure on a car door in SolidWorks. Which combination of load types and locations is best?
Solution
Step 1: Identify the nature of wind load
Wind applies pressure distributed over the outer surface of the door.Step 2: Choose appropriate load type and location
A uniform pressure load on the door's outer surface best simulates wind effect.Final Answer:
Apply a uniform pressure load on the outer surface of the door -> Option CQuick Check:
Wind = uniform pressure on outer surface [OK]
- Applying force only at handle
- Using torque on hinges for wind
- Applying pressure inside door cavity
Ready to prove it?
Pass the test and this pattern moves unknown
