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Simulinkdata~10 mins

Step response analysis in Simulink - Step-by-Step Execution

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Concept Flow - Step response analysis
Start Simulation
↓
Apply Step Input
↓
System Responds
↓
Measure Output Over Time
↓
Plot Step Response
↓
Analyze Characteristics
↓
End
The process starts by applying a step input to the system, then measuring and plotting the output over time to analyze system behavior.
Execution Sample
Simulink
step(sys)
info = stepinfo(sys);
disp(info);
This code plots the step response of a system and calculates key response characteristics.
Execution Table
StepActionInputOutputResult
1Apply step inputStep from 0 to 1 at t=0System starts at 0Initial condition set
2System response beginsStep input = 1Output risesOutput increases towards steady state
3Output approaches steady stateStep input = 1Output near final valueSettling begins
4Output settlesStep input = 1Output stable at final valueSteady state reached
5Calculate step infoOutput dataRise time, Settling time, OvershootStep response characteristics computed
6Display resultsStep infoPrinted characteristicsAnalysis complete
💡 Step response fully analyzed after output settles and characteristics are computed
Variable Tracker
VariableStartAfter Step InputDuring ResponseAt Steady StateFinal
Input01111
Output00RisingNear 11
Time00+IncreasingStableEnd
Key Moments - 3 Insights
Why does the output not jump instantly to the step input value?
Because the system has dynamics like inertia or delay, the output changes gradually as shown in rows 2 and 3 of the execution table.
What does settling time mean in the step response?
Settling time is when the output stays within a small range around the final value, as shown in row 4 where output stabilizes.
Why do we calculate step response characteristics?
To understand system behavior like speed and stability, which helps in design and control, as shown in rows 5 and 6.
Visual Quiz - 3 Questions
Test your understanding
Look at the execution table, what is the output value at step 3?
AOutput is rising towards steady state
BOutput is zero
COutput is stable at final value
DOutput is decreasing
💡 Hint
Check the 'Output' column at step 3 in the execution table.
At which step does the output reach steady state according to the execution table?
AStep 2
BStep 3
CStep 4
DStep 5
💡 Hint
Look for when the output is described as stable at final value.
If the system had no delay, how would the output change at step 2?
AOutput would remain zero
BOutput would jump instantly to 1
COutput would rise slowly
DOutput would decrease
💡 Hint
Consider the 'Output' behavior at step 2 and how delay affects it.
Concept Snapshot
Step response analysis:
- Apply a step input to the system
- Measure output over time
- Plot output vs time
- Calculate characteristics: rise time, settling time, overshoot
- Use to understand system dynamics and stability
Full Transcript
Step response analysis involves applying a sudden change (step input) to a system and observing how the output changes over time. The system output starts at zero and rises gradually due to system dynamics until it reaches a steady value. Key characteristics like rise time and settling time are calculated to understand how quickly and stably the system responds. This process helps in designing and tuning control systems.

Practice

(1/5)
1. What does the step function in Simulink primarily show about a system?
easy
A. The system's output response to a sudden input change
B. The frequency response of the system
C. The system's steady-state error only
D. The system's input signal over time

Solution

  1. Step 1: Understand the purpose of the step function

    The step function simulates how a system reacts when a sudden input (step input) is applied.
  2. Step 2: Identify what the output represents

    The output shows how the system's output changes over time after the step input, revealing speed and stability.
  3. Final Answer:

    The system's output response to a sudden input change -> Option A
  4. Quick Check:

    Step response = output after sudden input [OK]
Hint: Step function shows output after sudden input change [OK]
Common Mistakes:
  • Confusing step response with frequency response
  • Thinking it shows only steady-state error
  • Assuming it plots input signal instead of output
2. Which of the following is the correct syntax to plot the step response of a transfer function sys in MATLAB?
easy
A. response.step(sys)
B. plotstep(sys)
C. sys.step()
D. step(sys)

Solution

  1. Step 1: Recall MATLAB step response syntax

    The standard MATLAB command to plot step response is step(sys), where sys is the system model.
  2. Step 2: Check other options for correctness

    Options B, C, and D are not valid MATLAB commands for step response plotting.
  3. Final Answer:

    step(sys) -> Option D
  4. Quick Check:

    Use step(sys) to plot response [OK]
Hint: Use step(sys) to plot step response in MATLAB [OK]
Common Mistakes:
  • Using incorrect function names like plotstep
  • Trying object method calls not supported
  • Confusing syntax with other toolboxes
3. Given the following MATLAB code, what is the approximate settling time of the system's step response?
sys = tf([1], [1 3 2]);
info = stepinfo(sys);
settling_time = info.SettlingTime;
medium
A. About 2 seconds
B. About 1 second
C. About 3 seconds
D. About 4 seconds

Solution

  1. Step 1: Analyze the transfer function

    The system has poles at -1 and -2, so it is stable and expected to settle quickly.
  2. Step 2: Use stepinfo to find settling time

    The stepinfo function calculates settling time, which for this system is approximately 2 seconds.
  3. Final Answer:

    About 2 seconds -> Option A
  4. Quick Check:

    Settling time from stepinfo ≈ 2 sec [OK]
Hint: Use stepinfo(sys).SettlingTime for settling time [OK]
Common Mistakes:
  • Confusing settling time with rise time
  • Ignoring system poles location
  • Assuming default values without calculation
4. Identify the error in the following MATLAB code for plotting step response:
sys = tf([1 2], [1 4 5]);
step(sys)
title('Step Response')
xlabel('Time')
ylabel('Output')
medium
A. Missing semicolon after tf definition
B. No error; code runs correctly
C. The transfer function numerator and denominator are reversed
D. Step function should be called as step_response(sys)

Solution

  1. Step 1: Check transfer function syntax

    The numerator and denominator vectors are correctly placed in tf([1 2], [1 4 5]).
  2. Step 2: Verify step function and plot commands

    The step(sys) command is correct, and titles and labels are properly set.
  3. Final Answer:

    No error; code runs correctly -> Option B
  4. Quick Check:

    Code syntax is correct and runs [OK]
Hint: Check tf and step syntax carefully [OK]
Common Mistakes:
  • Thinking numerator and denominator are swapped
  • Expecting semicolon is mandatory (optional)
  • Using incorrect step function names
5. You want to compare the step responses of two systems sys1 = tf([1], [1 2 1]) and sys2 = tf([2], [1 3 2]). Which MATLAB code snippet correctly plots both responses on the same graph for comparison?
hard
A. step(sys1); step(sys2);
B. plot(step(sys1), step(sys2));
C. step([sys1 sys2]);
D. step(sys1 + sys2);

Solution

  1. Step 1: Understand how to plot multiple step responses

    Using step([sys1 sys2]) plots both systems' step responses on the same figure for easy comparison.
  2. Step 2: Evaluate other options

    step(sys1); step(sys2); overwrites the first plot without hold on; plot(step(sys1), step(sys2)); is invalid syntax; step(sys1 + sys2); plots sum system, not comparison.
  3. Final Answer:

    step([sys1 sys2]) -> Option C
  4. Quick Check:

    Use step([sys1 sys2]) for combined plot [OK]
Hint: Use step([sys1 sys2]) to plot both responses together [OK]
Common Mistakes:
  • Trying to add systems instead of plotting separately
  • Using plot() on step outputs incorrectly
  • Forgetting hold on/off when plotting separately
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