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Step response analysis in Simulink - Interactive Code Practice

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Practice - 5 Tasks
Answer the questions below
1fill in blank
easy

Complete the code to create a step input signal in Simulink.

Simulink
stepSignal = [1]('Step');
Drag options to blanks, or click blank then click option'
Atimeseries
Bstep
Csignalbuilder
Dsim
Attempts:
3 left
💡 Hint
Common Mistakes
Using 'timeseries' incorrectly for step input creation.
Confusing simulation commands with signal creation.
2fill in blank
medium

Complete the code to simulate the model named 'myModel' for 10 seconds.

Simulink
simOut = sim('[1]', 'StopTime', '10');
Drag options to blanks, or click blank then click option'
AmyModel
BsimulinkModel
CstepResponse
DmodelSim
Attempts:
3 left
💡 Hint
Common Mistakes
Using variable names instead of the model name string.
Passing incorrect model names.
3fill in blank
hard

Fix the error in extracting the step response data from simulation output.

Simulink
stepData = simOut.[1].signals.values;
Drag options to blanks, or click blank then click option'
AstepResponse
Boutput
Clogsout
Dyout
Attempts:
3 left
💡 Hint
Common Mistakes
Using incorrect property names that do not exist in the simulation output.
Confusing logsout with yout.
4fill in blank
hard

Fill both blanks to plot the step response data with time on the x-axis and output on the y-axis.

Simulink
plot(simOut.tout, simOut.[1].signals.[2]);
Drag options to blanks, or click blank then click option'
Ayout
Bvalues
Ctime
Ddata
Attempts:
3 left
💡 Hint
Common Mistakes
Using time or data instead of values.
Mixing up the properties of the simulation output.
5fill in blank
hard

Fill all three blanks to create a dictionary of step response characteristics: rise time, settling time, and overshoot.

Simulink
stepInfo = struct('RiseTime', [1], 'SettlingTime', [2], 'Overshoot', [3]);
Drag options to blanks, or click blank then click option'
Astepinfo(stepData, simOut.tout).RiseTime
Bstepinfo(stepData, simOut.tout).SettlingTime
Cstepinfo(stepData, simOut.tout).Overshoot
Dstepinfo(stepData, simOut.tout).Peak
Attempts:
3 left
💡 Hint
Common Mistakes
Using incorrect property names like 'Peak' instead of 'Overshoot'.
Not passing both data and time to stepinfo.

Practice

(1/5)
1. What does the step function in Simulink primarily show about a system?
easy
A. The system's output response to a sudden input change
B. The frequency response of the system
C. The system's steady-state error only
D. The system's input signal over time

Solution

  1. Step 1: Understand the purpose of the step function

    The step function simulates how a system reacts when a sudden input (step input) is applied.
  2. Step 2: Identify what the output represents

    The output shows how the system's output changes over time after the step input, revealing speed and stability.
  3. Final Answer:

    The system's output response to a sudden input change -> Option A
  4. Quick Check:

    Step response = output after sudden input [OK]
Hint: Step function shows output after sudden input change [OK]
Common Mistakes:
  • Confusing step response with frequency response
  • Thinking it shows only steady-state error
  • Assuming it plots input signal instead of output
2. Which of the following is the correct syntax to plot the step response of a transfer function sys in MATLAB?
easy
A. response.step(sys)
B. plotstep(sys)
C. sys.step()
D. step(sys)

Solution

  1. Step 1: Recall MATLAB step response syntax

    The standard MATLAB command to plot step response is step(sys), where sys is the system model.
  2. Step 2: Check other options for correctness

    Options B, C, and D are not valid MATLAB commands for step response plotting.
  3. Final Answer:

    step(sys) -> Option D
  4. Quick Check:

    Use step(sys) to plot response [OK]
Hint: Use step(sys) to plot step response in MATLAB [OK]
Common Mistakes:
  • Using incorrect function names like plotstep
  • Trying object method calls not supported
  • Confusing syntax with other toolboxes
3. Given the following MATLAB code, what is the approximate settling time of the system's step response?
sys = tf([1], [1 3 2]);
info = stepinfo(sys);
settling_time = info.SettlingTime;
medium
A. About 2 seconds
B. About 1 second
C. About 3 seconds
D. About 4 seconds

Solution

  1. Step 1: Analyze the transfer function

    The system has poles at -1 and -2, so it is stable and expected to settle quickly.
  2. Step 2: Use stepinfo to find settling time

    The stepinfo function calculates settling time, which for this system is approximately 2 seconds.
  3. Final Answer:

    About 2 seconds -> Option A
  4. Quick Check:

    Settling time from stepinfo ≈ 2 sec [OK]
Hint: Use stepinfo(sys).SettlingTime for settling time [OK]
Common Mistakes:
  • Confusing settling time with rise time
  • Ignoring system poles location
  • Assuming default values without calculation
4. Identify the error in the following MATLAB code for plotting step response:
sys = tf([1 2], [1 4 5]);
step(sys)
title('Step Response')
xlabel('Time')
ylabel('Output')
medium
A. Missing semicolon after tf definition
B. No error; code runs correctly
C. The transfer function numerator and denominator are reversed
D. Step function should be called as step_response(sys)

Solution

  1. Step 1: Check transfer function syntax

    The numerator and denominator vectors are correctly placed in tf([1 2], [1 4 5]).
  2. Step 2: Verify step function and plot commands

    The step(sys) command is correct, and titles and labels are properly set.
  3. Final Answer:

    No error; code runs correctly -> Option B
  4. Quick Check:

    Code syntax is correct and runs [OK]
Hint: Check tf and step syntax carefully [OK]
Common Mistakes:
  • Thinking numerator and denominator are swapped
  • Expecting semicolon is mandatory (optional)
  • Using incorrect step function names
5. You want to compare the step responses of two systems sys1 = tf([1], [1 2 1]) and sys2 = tf([2], [1 3 2]). Which MATLAB code snippet correctly plots both responses on the same graph for comparison?
hard
A. step(sys1); step(sys2);
B. plot(step(sys1), step(sys2));
C. step([sys1 sys2]);
D. step(sys1 + sys2);

Solution

  1. Step 1: Understand how to plot multiple step responses

    Using step([sys1 sys2]) plots both systems' step responses on the same figure for easy comparison.
  2. Step 2: Evaluate other options

    step(sys1); step(sys2); overwrites the first plot without hold on; plot(step(sys1), step(sys2)); is invalid syntax; step(sys1 + sys2); plots sum system, not comparison.
  3. Final Answer:

    step([sys1 sys2]) -> Option C
  4. Quick Check:

    Use step([sys1 sys2]) for combined plot [OK]
Hint: Use step([sys1 sys2]) to plot both responses together [OK]
Common Mistakes:
  • Trying to add systems instead of plotting separately
  • Using plot() on step outputs incorrectly
  • Forgetting hold on/off when plotting separately
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