Trace width for current capacity in PCB Design - Cell-by-Cell Formula Trace

Sample Data

This data shows current in Amps, allowed temperature rise in Celsius, copper thickness in ounces, and the trace width in mm to be calculated for PCB design.

Cell	Value
A1	Current (Amps)
B1	Temperature Rise (°C)
C1	Copper Thickness (oz)
D1	Trace Width (mm)
A2	5
B2	10
C2	1
D2
A3	10
B3	20
C3	2
D3

Formula Trace

D2 = 0.024 * (A2 ^ 0.44) * (B2 ^ 0.725) / C2

Step 1: A2 ^ 0.44

Step 2: B2 ^ 0.725

Step 3: 0.024 * 2.095 * 5.316

Step 4: 0.2673 / C2

Step 5: D2 = 0.2673

Cell Reference Map

   A      B       C       D
1 Current TempRise Copper  TraceWidth
2  5      10      1       ->
3 10      20      2       

Arrows show D2 depends on A2, B2, C2

Trace width in D2 is calculated using current in A2, temperature rise in B2, and copper thickness in C2.

Result

   A      B       C       D
1 Current TempRise Copper  TraceWidth
2  5      10      1       0.2673
3 10      20      2       

D2 shows the calculated trace width in mm for the given parameters.

The calculated trace width for the first row is about 0.2673 mm, showing how wide the PCB trace should be to safely carry 5 Amps with 10°C temperature rise and 1 oz copper.

Sheet Trace Quiz - 3 Questions

What is the result of raising the current 5 Amps to the power 0.44?

A 2.095

B 5.316

C 0.2673

D 0.024

Key Result

Trace width = constant * (Current ^ 0.44) * (TemperatureRise ^ 0.725) / CopperThickness

Practice

1. What is the main reason to choose the correct trace width in PCB design?

easy

A. To increase the signal speed on the trace

B. To make the PCB look visually appealing

C. To reduce the cost of copper used in the PCB

D. To ensure the trace can safely carry the required current without overheating

Solution

1. Step 1: Understand trace width purpose

   Trace width determines how much current a PCB trace can carry safely without overheating.

2. Step 2: Identify the main safety concern

   Overheating can damage the PCB and cause failure, so correct width prevents this.

3. Final Answer:

   To ensure the trace can safely carry the required current without overheating -> Option D

4. Quick Check:

   Trace width controls current safely [OK]

Hint: Trace width prevents overheating by carrying current safely [OK]

Common Mistakes:

• Thinking trace width is for aesthetics
• Assuming trace width reduces cost only
• Believing trace width affects signal speed directly

2. Which of the following is the correct way to express trace width in a PCB design specification?

easy

A. TraceWidth = 10mm + Current * 0.5

B. TraceWidth = 10 mils

C. traceWidth = '10mil'

D. Trace_Width = 10mil

Solution

1. Step 1: Recognize standard units for trace width

   Trace width is commonly specified in mils (thousandths of an inch) or mm, with a space before the unit.

2. Step 2: Identify correct syntax for specification

   TraceWidth = 10 mils uses a numeric value followed by a space and unit 'mils', which is clear and standard.

3. Final Answer:

   TraceWidth = 10 mils -> Option B

4. Quick Check:

   Standard unit with space = correct [OK]

Hint: Use numeric value plus unit with space (e.g., 10 mils) [OK]

Common Mistakes:

• Using quotes around units incorrectly
• Combining units without space
• Using non-standard unit names

3. Given a PCB trace carrying 3A current with a temperature rise limit of 10°C, which trace width is closest to the recommended value using IPC-2152 guidelines?

Options are based on typical IPC-2152 charts for external layers.

medium

A. 30 mils

B. 15 mils

C. 50 mils

D. 70 mils

Solution

1. Step 1: Refer to IPC-2152 chart for 3A current and 10°C rise

   According to IPC-2152, a 3A current with 10°C rise typically requires about 25-35 mils trace width on external layers.

2. Step 2: Match closest option

   Among given options, 30 mils fits best within the recommended range.

3. Final Answer:

   30 mils -> Option A

4. Quick Check:

   3A current needs ~30 mils width [OK]

Hint: Use IPC-2152 chart ranges for current and temp rise [OK]

Common Mistakes:

• Choosing too narrow trace causing overheating
• Picking overly wide trace wasting PCB space
• Ignoring temperature rise in calculation

4. A designer used the formula TraceWidth = Current * 10 to calculate trace width in mils. The trace carries 2A current. The calculated width is 20 mils. However, the trace overheats during testing. What is the likely error?

medium

A. The formula does not consider temperature rise and copper thickness

B. The current value should be squared in the formula

C. Trace width should be in mm, not mils

D. The formula should multiply current by 5, not 10

Solution

1. Step 1: Analyze the formula used

   The formula is a simple linear multiplication ignoring key factors like temperature rise and copper thickness.

2. Step 2: Understand why overheating occurs

   Without considering temperature rise and copper thickness, the trace width may be underestimated, causing overheating.

3. Final Answer:

   The formula does not consider temperature rise and copper thickness -> Option A

4. Quick Check:

   Missing temp rise and copper thickness causes errors [OK]

Hint: Always include temperature rise and copper thickness in calculations [OK]

Common Mistakes:

• Using oversimplified formulas
• Ignoring units consistency
• Assuming linear scaling is enough

5. You need to design a PCB trace for a 5A current on an internal layer with a maximum temperature rise of 20°C. Using IPC-2152 guidelines, which approach is best to determine the correct trace width?

hard

A. Use the external layer chart and double the width value

B. Use a fixed 50 mil width for all internal traces carrying above 4A

C. Use the internal layer chart and adjust for copper thickness and temperature rise

D. Calculate width by dividing current by temperature rise

Solution

1. Step 1: Identify correct IPC-2152 chart for internal layers

   Internal layers have different heat dissipation, so use the internal layer chart for accurate width.

2. Step 2: Adjust for copper thickness and temperature rise

   Consider copper thickness and max temperature rise to find precise trace width for 5A current.

3. Final Answer:

   Use the internal layer chart and adjust for copper thickness and temperature rise -> Option C

4. Quick Check:

   Internal layer needs specific chart and adjustments [OK]

Hint: Use internal layer IPC-2152 chart with copper and temp adjustments [OK]

Common Mistakes:

• Using external layer data for internal traces
• Applying fixed widths without calculation
• Ignoring copper thickness effect