Trace width for current capacity in PCB Design - Interactive Code Practice

Practice - 5 Tasks

1fill in blank

easy

Complete the formula to calculate the trace width based on current capacity.

PCB Design

trace_width = current [1] k

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A*

B+

C-

D/

Attempts:

3 left

💡 Hint

Common Mistakes

Using addition or division instead of multiplication.

The trace width is proportional to the current multiplied by a constant factor k.

2fill in blank

medium

Complete the DAX measure to calculate total current capacity from a table named 'Traces'.

PCB Design

TotalCurrent = SUM(Traces[[1]])

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AResistance

BWidth

CCurrent

DLength

Attempts:

3 left

💡 Hint

Common Mistakes

Summing width or resistance instead of current.

The measure sums the 'Current' column to get total current capacity.

3fill in blank

hard

Fix the error in this SQL query to select trace widths greater than 10 mils.

PCB Design

SELECT * FROM Traces WHERE Width [1] 10

Drag options to blanks, or click blank then click option'

A>

B<

C=

D<=

Attempts:

3 left

💡 Hint

Common Mistakes

Using '=' or '<' which do not filter correctly.

The query filters traces with width greater than 10 mils using the '>' operator.

4fill in blank

hard

Fill both blanks to create a dictionary comprehension that maps trace names to widths for traces with current {{BLANK_1}} 5 and width {{BLANK_2}} 10.

PCB Design

{trace['name']: trace['width'] for trace in traces if trace['current'] [1] 5 and trace['width'] [2] 10}

Drag options to blanks, or click blank then click option'

A>

B<

C>=

D<=

Attempts:

3 left

💡 Hint

Common Mistakes

Using wrong comparison operators that reverse the filter logic.

The comprehension filters traces with current greater than 5 and width less than 10.

5fill in blank

hard

Fill all three blanks to create a DAX measure that calculates average trace width for traces with current {{BLANK_1}} 3, width {{BLANK_2}} 20, and length {{BLANK_3}} 50.

PCB Design

AvgWidth = AVERAGEX(FILTER(Traces, Traces[Current] [1] 3 && Traces[Width] [2] 20 && Traces[Length] [3] 50), Traces[Width])

Drag options to blanks, or click blank then click option'

A>

B<

C<=

D>=

Attempts:

3 left

💡 Hint

Common Mistakes

Mixing up comparison operators or using wrong logical conditions.

The measure filters traces with current greater or equal to 3, width less than 20, and length greater than 50, then averages their widths.