Stack pointer (R13/SP) in ARM Architecture - Interactive Code Practice

Practice - 5 Tasks

1fill in blank

easy

Complete the code to show the register used as the stack pointer in ARM architecture.

ARM Architecture

The stack pointer register in ARM is called [1].

Drag options to blanks, or click blank then click option'

AR14

BR12

CR13

DR15

Attempts:

3 left

💡 Hint

Common Mistakes

Confusing the stack pointer with the link register (R14).

Using the program counter (R15) as the stack pointer.

In ARM architecture, the stack pointer is stored in register R13, often referred to as SP.

2fill in blank

medium

Complete the code to describe the stack pointer's role in function calls.

ARM Architecture

During a function call, the stack pointer [1] to allocate space for local variables and return addresses.

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Adecrements

Bresets

Cremains unchanged

Dincrements

Attempts:

3 left

💡 Hint

Common Mistakes

Assuming the stack pointer increments to allocate space.

Thinking the stack pointer resets during every function call.

The stack pointer usually moves down (decrements) to allocate space on the stack for local data during function calls.

3fill in blank

hard

Fix the error in the statement about the stack pointer usage.

ARM Architecture

The stack pointer ([1]) is used to store the return address during a function call.

Drag options to blanks, or click blank then click option'

AR13

BR14

CR15

DR12

Attempts:

3 left

💡 Hint

Common Mistakes

Confusing the stack pointer with the link register.

Thinking the stack pointer holds the return address.

The stack pointer (R13) points to the top of the stack, but the return address is stored in the link register (R14), not the stack pointer.

4fill in blank

hard

Fill both blanks to complete the dictionary comprehension describing stack pointer behavior.

ARM Architecture

stack_changes = {op: [1] for op in operations if op [2] 'push'}

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A'decrement'

B'increment'

C'=='

D'!='

Attempts:

3 left

💡 Hint

Common Mistakes

Using 'increment' instead of 'decrement' for push.

Using '!=' instead of '==' in the condition.

When the operation is 'push', the stack pointer decrements to allocate space on the stack.

5fill in blank

hard

Fill all three blanks to complete the dictionary comprehension about stack pointer operations.

ARM Architecture

stack_ops = [1]: [2] for [3] in commands if [3] in ['push', 'pop']}

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A'push'

B'pop'

Ccmd

D'push' if cmd == 'push' else 'pop'

Attempts:

3 left

💡 Hint

Common Mistakes

Using the wrong variable name in the loop.

Mixing up keys and values in the dictionary.

This comprehension maps 'push' commands to 'pop' and iterates over command variable 'cmd'.

Practice

1. What is the primary role of the stack pointer (R13/SP) in ARM processors?

easy

A. It tracks the top of the stack during program execution.

B. It stores the current instruction being executed.

C. It holds the address of the program's entry point.

D. It manages the processor's clock speed.

Solution

1. Step 1: Understand the stack pointer's function

   The stack pointer (R13/SP) is a special register that points to the top of the stack in memory.

2. Step 2: Identify its role in program execution

   It helps manage data pushed onto or popped from the stack, such as function calls and local variables.

3. Final Answer:

   It tracks the top of the stack during program execution. -> Option A

4. Quick Check:

   Stack pointer = top of stack tracker [OK]

Hint: Stack pointer always points to the current top of the stack [OK]

Common Mistakes:

• Confusing stack pointer with program counter
• Thinking it stores instructions
• Assuming it controls processor speed

2. Which of the following is the register number for the stack pointer register in ARM assembly?

easy

A. R14

B. R13

C. SP

D. PC

Solution

1. Step 1: Recall ARM register naming

   In ARM architecture, R13 is the register used as the stack pointer.

2. Step 2: Match register names to functions

   R14 is the link register, PC is the program counter, and SP is an alias for R13.

3. Final Answer:

   R13 -> Option B

4. Quick Check:

   Stack pointer register = R13 [OK]

Hint: Remember R13 is SP, R14 is LR, PC is R15 [OK]

Common Mistakes:

• Confusing R13 with R14 (link register)
• Thinking SP is the register number
• Confusing it with PC (R15)

3. Consider this ARM assembly snippet:

SUB SP, SP, #4
STR R0, [SP]
ADD SP, SP, #4

What does this code do to the stack pointer?

medium

A. Moves SP down by 4, stores R0, then moves SP back up by 4

B. Moves SP up by 4, stores R0, then moves SP down by 4

C. Stores R0 without changing SP

D. Causes a runtime error due to invalid SP manipulation

Solution

1. Step 1: Analyze the SUB instruction

   SUB SP, SP, #4 decreases SP by 4, moving the stack pointer down to allocate space.

2. Step 2: Understand STR and ADD instructions

   STR R0, [SP] stores the value of R0 at the new top of the stack. ADD SP, SP, #4 restores SP back up by 4.

3. Final Answer:

   Moves SP down by 4, stores R0, then moves SP back up by 4 -> Option A

4. Quick Check:

   SUB decreases SP, ADD restores SP [OK]

Hint: SUB decreases SP (push), ADD increases SP (pop) [OK]

Common Mistakes:

• Mixing up SUB and ADD effects on SP
• Assuming SP does not change
• Thinking this causes an error

4. In ARM assembly, a programmer writes:

ADD SP, SP, #8
LDR R1, [SP, #-4]

What is the problem with this code?

medium

A. There is no problem; code works as intended.

B. The immediate value #8 is invalid for ADD instruction.

C. LDR cannot use negative offsets in ARM assembly.

D. SP is moved up before loading, causing incorrect address access.

Solution

1. Step 1: Examine ADD SP, SP, #8

   This moves SP up by 8, effectively popping 8 bytes off the stack.

2. Step 2: Analyze LDR with negative offset

   LDR R1, [SP, #-4] tries to load from SP minus 4 bytes, but since SP moved up, this address may not point to the intended data.

3. Step 3: Identify the problem

   Moving SP up before loading causes the load to access an incorrect or invalid memory location.

4. Final Answer:

   SP is moved up before loading, causing incorrect address access. -> Option D

5. Quick Check:

   SP must point correctly before LDR [OK]

Hint: Adjust SP after loading, not before, to avoid wrong addresses [OK]

Common Mistakes:

• Assuming negative offsets are invalid
• Ignoring SP movement effect on address
• Believing immediate #8 is illegal

5. You want to save registers R0 to R3 on the stack before a function call and restore them after. Which ARM assembly sequence correctly uses the stack pointer (R13/SP) to do this?

hard

A. SUB SP, SP, #4
STR R0, [SP]
STR R1, [SP, #4]
STR R2, [SP, #8]
STR R3, [SP, #12]
...function call...
LDMIA SP!, {R0-R3}

B. ADD SP, SP, #16
STR R0, [SP]
STR R1, [SP, #4]
STR R2, [SP, #8]
STR R3, [SP, #12]
...function call...
LDMFD SP!, {R0-R3}

C. SUB SP, SP, #16
STR R0, [SP]
STR R1, [SP, #4]
STR R2, [SP, #8]
STR R3, [SP, #12]
...function call...
LDMIA SP!, {R0-R3}

D. SUB SP, SP, #16
STR R0, [SP, #12]
STR R1, [SP, #8]
STR R2, [SP, #4]
STR R3, [SP]
...function call...
LDMIA SP!, {R0-R3}

Solution

1. Step 1: Allocate stack space for 4 registers

   SUB SP, SP, #16 reserves 16 bytes (4 registers x 4 bytes each) by moving SP down.

2. Step 2: Store registers in ascending order

   STR instructions store R0 at [SP], R1 at [SP+4], R2 at [SP+8], and R3 at [SP+12], matching stack layout.

3. Step 3: Restore registers after function call

   LDMIA SP!, {R0-R3} loads multiple registers and increments SP, restoring original SP value.

4. Final Answer:

   The sequence using SUB SP, SP, #16, ordered STRs, and LDMIA SP!, {R0-R3} -> Option C

5. Quick Check:

   SUB allocates, STR stores, LDMIA restores [OK]

Hint: Subtract before storing, add after loading with LDMIA SP! [OK]

Common Mistakes:

• Using ADD instead of SUB to allocate stack space
• Incorrect offsets for storing registers
• Reversing order of stored registers
• Using wrong load multiple instruction