The stack pointer (R13 or SP) keeps track of the top of the stack in memory. It helps the processor know where to add or remove data during function calls and interrupts.
Stack pointer (R13/SP) in ARM Architecture
Register R13 is reserved as the Stack Pointer (SP). Common instructions involving SP: PUSH {registers} ; Decrement SP and store registers on stack POP {registers} ; Load registers from stack and increment SP Example: SUB SP, SP, #4 ; Make space on stack (push) STR R0, [SP] ; Store R0 at top of stack LDR R1, [SP] ; Load from top of stack into R1 ADD SP, SP, #4 ; Remove space from stack (pop)
R13 is a special register dedicated as the stack pointer in ARM architecture.
Stack grows downward in memory, so pushing data decreases SP, popping increases SP.
PUSH {R0}
; Stack pointer (SP) decreases by 4 bytes
; R0 value stored at new SP addressPOP {R1}
; Value at SP loaded into R1
; SP increases by 4 bytesSUB SP, SP, #8 ; Reserve 8 bytes on stack for local variables
ADD SP, SP, #8 ; Release 8 bytes from stack after use
This program loads two values into registers R0 and R1, pushes them onto the stack using the stack pointer (SP), clears the registers, then pops the values back from the stack. It demonstrates how SP moves down when pushing and up when popping.
; Simple ARM assembly example showing stack pointer usage
AREA StackPointerExample, CODE, READONLY
ENTRY
MOV R0, #10 ; Load 10 into R0
MOV R1, #20 ; Load 20 into R1
; Push R0 and R1 onto stack
PUSH {R0, R1} ; SP decreases by 8 bytes
; Clear R0 and R1 to show values come from stack
MOV R0, #0
MOV R1, #0
; Pop values back into R0 and R1
POP {R0, R1} ; SP increases by 8 bytes
; End program (infinite loop)
B .
ENDTime complexity: Stack pointer operations like PUSH and POP run in constant time O(1).
Space complexity: Uses stack memory; careful management prevents overflow.
Common mistake: Forgetting that stack grows downward, so pushing decreases SP.
Use stack pointer operations to save and restore registers during function calls and interrupts.
The stack pointer (R13/SP) tracks the top of the stack in ARM processors.
Stack grows downward; pushing data decreases SP, popping increases SP.
Use PUSH and POP instructions to save and restore register values safely.
Practice
Solution
Step 1: Understand the stack pointer's function
The stack pointer (R13/SP) is a special register that points to the top of the stack in memory.Step 2: Identify its role in program execution
It helps manage data pushed onto or popped from the stack, such as function calls and local variables.Final Answer:
It tracks the top of the stack during program execution. -> Option AQuick Check:
Stack pointer = top of stack tracker [OK]
- Confusing stack pointer with program counter
- Thinking it stores instructions
- Assuming it controls processor speed
Solution
Step 1: Recall ARM register naming
In ARM architecture, R13 is the register used as the stack pointer.Step 2: Match register names to functions
R14 is the link register, PC is the program counter, and SP is an alias for R13.Final Answer:
R13 -> Option BQuick Check:
Stack pointer register = R13 [OK]
- Confusing R13 with R14 (link register)
- Thinking SP is the register number
- Confusing it with PC (R15)
SUB SP, SP, #4 STR R0, [SP] ADD SP, SP, #4
What does this code do to the stack pointer?
Solution
Step 1: Analyze the SUB instruction
SUB SP, SP, #4 decreases SP by 4, moving the stack pointer down to allocate space.Step 2: Understand STR and ADD instructions
STR R0, [SP] stores the value of R0 at the new top of the stack. ADD SP, SP, #4 restores SP back up by 4.Final Answer:
Moves SP down by 4, stores R0, then moves SP back up by 4 -> Option AQuick Check:
SUB decreases SP, ADD restores SP [OK]
- Mixing up SUB and ADD effects on SP
- Assuming SP does not change
- Thinking this causes an error
ADD SP, SP, #8 LDR R1, [SP, #-4]
What is the problem with this code?
Solution
Step 1: Examine ADD SP, SP, #8
This moves SP up by 8, effectively popping 8 bytes off the stack.Step 2: Analyze LDR with negative offset
LDR R1, [SP, #-4] tries to load from SP minus 4 bytes, but since SP moved up, this address may not point to the intended data.Step 3: Identify the problem
Moving SP up before loading causes the load to access an incorrect or invalid memory location.Final Answer:
SP is moved up before loading, causing incorrect address access. -> Option DQuick Check:
SP must point correctly before LDR [OK]
- Assuming negative offsets are invalid
- Ignoring SP movement effect on address
- Believing immediate #8 is illegal
Solution
Step 1: Allocate stack space for 4 registers
SUB SP, SP, #16 reserves 16 bytes (4 registers x 4 bytes each) by moving SP down.Step 2: Store registers in ascending order
STR instructions store R0 at [SP], R1 at [SP+4], R2 at [SP+8], and R3 at [SP+12], matching stack layout.Step 3: Restore registers after function call
LDMIA SP!, {R0-R3} loads multiple registers and increments SP, restoring original SP value.Final Answer:
The sequence using SUB SP, SP, #16, ordered STRs, and LDMIA SP!, {R0-R3} -> Option CQuick Check:
SUB allocates, STR stores, LDMIA restores [OK]
- Using ADD instead of SUB to allocate stack space
- Incorrect offsets for storing registers
- Reversing order of stored registers
- Using wrong load multiple instruction
Ready to prove it?
Pass the test and this pattern moves unknown
