Program counter (R15/PC) in ARM Architecture

Introduction

The program counter (PC) keeps track of the address of the next instruction to run in a program. It helps the processor know where it is in the code.

When the processor needs to move to the next instruction in a program.

When performing jumps or branches to a different part of the code.

When handling interrupts or exceptions that change the flow of execution.

When debugging to see which instruction is currently being executed.

When writing assembly code that changes the flow of the program.

Core Concept

ARM Architecture

R15 or PC

R15 is the register number for the program counter in ARM architecture.

PC automatically updates to point to the next instruction during execution.

Key Points

This copies the current value of the program counter into register R0.

ARM Architecture

MOV R0, PC

This moves the program counter forward by 4 bytes, effectively skipping the next instruction.

ARM Architecture

ADD PC, PC, #4

This is a branch instruction that changes the PC to the address of 'label', altering program flow.

ARM Architecture

B label

Detailed Explanation

This ARM assembly program shows how the program counter (PC) can be used and changed. First, it copies the PC value into R0. Then it adds 8 to PC, which skips the next two instructions. The skipped instructions would have set R1 and R2, but they are not executed. Finally, it loops infinitely at the end.

ARM Architecture

    AREA Example, CODE, READONLY
    ENTRY
start
    MOV R0, PC      ; Copy current PC to R0
    ADD PC, PC, #8  ; Skip next two instructions
    MOV R1, #1      ; This instruction is skipped
    MOV R2, #2      ; This instruction is skipped
end
    B end           ; Infinite loop to end program
    END

Important Notes

The PC usually points to the current instruction plus 8 bytes ahead in ARM due to pipelining.

Changing the PC directly changes the flow of the program.

Be careful when modifying PC to avoid unexpected jumps or crashes.

Summary

The program counter (R15/PC) holds the address of the next instruction to execute.

It updates automatically but can be changed to jump to different code parts.

Understanding PC is key to controlling program flow in ARM assembly.

Practice

1. What is the primary role of the Program Counter (PC) in ARM architecture?

easy

A. It holds the address of the next instruction to execute.

B. It stores the result of arithmetic operations.

C. It manages input/output operations.

D. It controls the power management of the processor.

Solution

1. Step 1: Understand the function of PC

   The Program Counter (PC) is a special register that keeps track of the address of the next instruction to be executed in the program.

2. Step 2: Compare with other options

   Other options describe functions of different registers or components, not the PC.

3. Final Answer:

   It holds the address of the next instruction to execute. -> Option A

4. Quick Check:

   PC = Next instruction address [OK]

Hint: PC always points to the next instruction address [OK]

Common Mistakes:

• Confusing PC with general-purpose registers
• Thinking PC stores data instead of addresses
• Mixing PC role with I/O or power control

2. Which register number corresponds to the Program Counter (PC) in ARM processors?

easy

A. R14

B. R13

C. R15

D. R12

Solution

1. Step 1: Recall ARM register naming

   In ARM architecture, the Program Counter is known as register R15.

2. Step 2: Verify other register roles

   R14 is the Link Register, R13 is the Stack Pointer, and R12 is a general-purpose register.

3. Final Answer:

   R15 -> Option C

4. Quick Check:

   PC = R15 [OK]

Hint: PC is always R15 in ARM [OK]

Common Mistakes:

• Confusing PC with Link Register (R14)
• Mixing up Stack Pointer (R13) with PC
• Assuming PC is a general-purpose register

3. Consider this ARM assembly snippet:

ADD R0, R0, #4
MOV PC, R0

What happens when the MOV PC, R0 instruction executes?

medium

A. The program jumps to the address stored in R0.

B. The value in R0 is added to the PC without changing flow.

C. The PC is set to zero, causing a reset.

D. The instruction causes a syntax error.

Solution

1. Step 1: Understand MOV PC, R0

   Moving a value into PC changes the program flow to the address in R0, causing a jump.

2. Step 2: Analyze the ADD instruction

   ADD R0, R0, #4 increments R0 by 4, so PC will jump to this new address.

3. Final Answer:

   The program jumps to the address stored in R0. -> Option A

4. Quick Check:

   Setting PC = R0 causes jump [OK]

Hint: MOV to PC changes program flow to that address [OK]

Common Mistakes:

• Thinking MOV PC,R0 just copies value without jump
• Assuming PC increments automatically ignoring MOV
• Believing MOV PC,R0 causes error

4. Identify the error in this ARM assembly code snippet:

MOV PC, #1000

What is wrong with this instruction?

medium

A. The immediate value #1000 is too large for MOV instruction.

B. You cannot move an immediate value directly into PC.

C. PC cannot be used as a destination register.

D. MOV instruction requires two registers, not immediate values.

Solution

1. Step 1: Understand MOV limitations with PC

   In ARM, you cannot move an immediate value directly into PC; it must come from a register.

2. Step 2: Check other options

   PC can be destination, MOV can use immediate but not directly to PC, and #1000 size is not the main issue here.

3. Final Answer:

   You cannot move an immediate value directly into PC. -> Option B

4. Quick Check:

   Immediate to PC invalid [OK]

Hint: MOV immediate to PC is invalid; use register first [OK]

Common Mistakes:

• Trying to load PC directly with immediate values
• Confusing PC with general-purpose registers
• Assuming MOV always accepts immediate to any register

5. In ARM assembly, how can you implement a conditional jump to address stored in R4 only if R1 equals zero, using the Program Counter (PC)?

hard

A. Use JMP R4 if R1 equals zero.

B. Use BEQ R4 to jump if R1 is zero.

C. Use MOV PC, R4 unconditionally after checking R1.

D. Use CMP R1, #0 followed by MOVEQ PC, R4.

Solution

1. Step 1: Compare R1 with zero

   The CMP R1, #0 instruction sets condition flags based on R1's value.

2. Step 2: Use conditional move to PC

   MOVEQ PC, R4 moves R4 into PC only if the zero flag is set (R1 == 0), causing a conditional jump.

3. Final Answer:

   Use CMP R1, #0 followed by MOVEQ PC, R4. -> Option D

4. Quick Check:

   Conditional MOV to PC enables jump [OK]

Hint: Use CMP then conditional MOV to PC for jumps [OK]

Common Mistakes:

• Using BEQ with a register operand (invalid syntax)
• Unconditionally moving PC ignoring condition
• Using JMP which is not an ARM instruction