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ARM Architectureknowledge~5 mins

Data processing instructions (ADD, SUB, MOV, CMP) in ARM Architecture - Cheat Sheet & Quick Revision

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Recall & Review
beginner
What does the ADD instruction do in ARM architecture?
The ADD instruction adds two values together and stores the result in a register. It is used to perform simple arithmetic addition.
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beginner
Explain the function of the SUB instruction.
The SUB instruction subtracts one value from another and stores the result in a register. It is used for arithmetic subtraction.
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beginner
What is the purpose of the MOV instruction?
MOV copies a value from one register or an immediate value into another register. It is used to transfer data without changing it.
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intermediate
How does the CMP instruction work?
CMP compares two values by subtracting one from the other but does not store the result. Instead, it updates condition flags used for decision making.
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intermediate
Why are condition flags important in ARM data processing instructions?
Condition flags indicate the result of operations like zero, negative, or carry. They help the processor decide what to do next, such as branching or continuing execution.
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What does the ADD instruction do in ARM?
AAdds two values and stores the result
BSubtracts two values
CMoves data between registers
DCompares two values
Which instruction copies a value from one register to another?
ASUB
BCMP
CMOV
DADD
What does the CMP instruction do?
AAdds two values
BCompares two values and updates flags
CMoves data
DSubtracts and stores the result
Which instruction subtracts one value from another and stores the result?
ASUB
BMOV
CCMP
DADD
Why are condition flags important after instructions like CMP?
AThey add values
BThey store the result
CThey move data
DThey help decide the next action
Describe the purpose and basic operation of the ADD, SUB, MOV, and CMP instructions in ARM architecture.
Think about how each instruction handles data and what it changes or updates.
You got /4 concepts.
    Explain how condition flags are used in ARM data processing instructions and why they matter.
    Consider what happens after a comparison or arithmetic operation.
    You got /4 concepts.

      Practice

      (1/5)
      1. What does the ADD instruction do in ARM architecture?
      easy
      A. Compares two register values without changing them
      B. Subtracts one register value from another
      C. Copies a value into a register
      D. Adds values from two registers and stores the result in a register

      Solution

      1. Step 1: Understand the purpose of ADD

        The ADD instruction performs addition of two values stored in registers.
      2. Step 2: Identify the result storage

        The result of the addition is stored back into a register.
      3. Final Answer:

        Adds values from two registers and stores the result in a register -> Option D
      4. Quick Check:

        ADD means addition operation [OK]
      Hint: ADD always means adding two numbers and saving result [OK]
      Common Mistakes:
      • Confusing ADD with MOV which copies values
      • Thinking ADD compares values like CMP
      • Assuming ADD subtracts values
      2. Which of the following is the correct syntax to move the value 5 into register R1 in ARM assembly?
      easy
      A. SUB R1, #5
      B. MOV R1, #5
      C. ADD R1, #5
      D. CMP R1, #5

      Solution

      1. Step 1: Identify the instruction for copying values

        MOV is used to copy a value into a register.
      2. Step 2: Check the syntax for immediate value

        The immediate value 5 is written as #5, so MOV R1, #5 copies 5 into R1.
      3. Final Answer:

        MOV R1, #5 -> Option B
      4. Quick Check:

        MOV copies value to register [OK]
      Hint: MOV copies values; # means immediate number [OK]
      Common Mistakes:
      • Using ADD or SUB instead of MOV to copy values
      • Forgetting # before immediate values
      • Using CMP which only compares values
      3. Given the instructions:
      MOV R0, #10
      SUB R0, R0, #3

      What is the value in register R0 after execution?
      medium
      A. 7
      B. 13
      C. 3
      D. 10

      Solution

      1. Step 1: Execute MOV instruction

        MOV R0, #10 sets register R0 to 10.
      2. Step 2: Execute SUB instruction

        SUB R0, R0, #3 subtracts 3 from R0 (10 - 3 = 7) and stores result in R0.
      3. Final Answer:

        7 -> Option A
      4. Quick Check:

        10 minus 3 equals 7 [OK]
      Hint: SUB subtracts immediate from register value [OK]
      Common Mistakes:
      • Adding instead of subtracting
      • Not updating R0 after SUB
      • Confusing immediate and register operands
      4. Identify the error in the following ARM assembly code:
      MOV R2, #8
      CMP R2, #8
      ADD R3, R2
      medium
      A. MOV instruction cannot use immediate values
      B. CMP instruction syntax is incorrect
      C. ADD instruction missing second operand
      D. No error, code is correct

      Solution

      1. Step 1: Check MOV and CMP instructions

        MOV R2, #8 and CMP R2, #8 are correct syntax for moving and comparing immediate values.
      2. Step 2: Analyze ADD instruction

        ADD requires three operands: destination, first source, second source. Here, ADD R3, R2 misses the third operand.
      3. Final Answer:

        ADD instruction missing second operand -> Option C
      4. Quick Check:

        ADD needs 3 operands [OK]
      Hint: ADD needs destination and two sources [OK]
      Common Mistakes:
      • Assuming CMP syntax is wrong
      • Thinking MOV can't use immediate values
      • Ignoring missing operand in ADD
      5. You want to check if the value in register R4 is equal to 15 and then move 1 into R5 if true, else move 0. Which sequence correctly uses ARM instructions?
      hard
      A. CMP R4, #15
      BEQ label_true
      MOV R5, #0
      B label_end
      label_true: MOV R5, #1
      label_end:
      B. MOV R5, #1
      CMP R4, #15
      BEQ label_true
      MOV R5, #0
      label_true:
      C. CMP R4, #15
      MOV R5, #1
      BEQ label_true
      MOV R5, #0
      label_true:
      D. MOV R5, #0
      CMP R4, #15
      MOV R5, #1
      BEQ label_true
      label_true:

      Solution

      1. Step 1: Compare R4 with 15

        CMP R4, #15 sets flags based on comparison.
      2. Step 2: Use BEQ to branch if equal

        BEQ label_true jumps to label_true if R4 equals 15.
      3. Step 3: Move 0 if not equal, else move 1

        If not equal, MOV R5, #0 executes; branch skips to label_end. At label_true, MOV R5, #1 sets R5 to 1.
      4. Final Answer:

        Sequence in option A correctly implements the logic -> Option A
      5. Quick Check:

        CMP + BEQ + conditional MOV sequence [OK]
      Hint: Use CMP then BEQ to branch, MOV sets values [OK]
      Common Mistakes:
      • Moving values before comparison
      • Not branching correctly on equality
      • Incorrect order of instructions
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