Checking element state (displayed, enabled, selected) in Selenium Python - Interactive Code Practice

Practice - 5 Tasks

1fill in blank

easy

Complete the code to check if the element is visible on the page.

Selenium Python

element = driver.find_element(By.ID, "submit-btn")
if element.[1]():
    print("Button is visible")

Drag options to blanks, or click blank then click option'

Ais_selected

Bis_enabled

Cis_displayed

Dclick

Attempts:

3 left

💡 Hint

Common Mistakes

Using is_enabled() instead of is_displayed()

Trying to call click() instead of checking state

The is_displayed() method checks if the element is visible on the page.

2fill in blank

medium

Complete the code to check if the checkbox is selected.

Selenium Python

checkbox = driver.find_element(By.NAME, "agree")
if checkbox.[1]():
    print("Checkbox is checked")

Drag options to blanks, or click blank then click option'

Ais_displayed

Bsubmit

Cis_enabled

Dis_selected

Attempts:

3 left

💡 Hint

Common Mistakes

Using is_displayed() which checks visibility

Using is_enabled() which checks if element can be interacted with

The is_selected() method returns True if the checkbox or radio button is selected.

3fill in blank

hard

Fix the error in the code to check if the button is enabled.

Selenium Python

button = driver.find_element(By.CLASS_NAME, "btn-primary")
if button.[1]():
    print("Button is clickable")

Drag options to blanks, or click blank then click option'

Ais_selected

Bis_enabled

Cis_displayed

Dclickable

Attempts:

3 left

💡 Hint

Common Mistakes

Using is_displayed() which only checks visibility

Using a non-existent method 'clickable'

The correct method to check if a button is enabled (clickable) is is_enabled().

4fill in blank

hard

Fill both blanks to create a dictionary of element states for a checkbox.

Selenium Python

checkbox = driver.find_element(By.ID, "subscribe")
states = {
    "visible": checkbox.[1](),
    "enabled": checkbox.[2]()
}

Drag options to blanks, or click blank then click option'

Ais_displayed

Bis_selected

Cis_enabled

Dclick

Attempts:

3 left

💡 Hint

Common Mistakes

Using is_selected() for visibility

Using click() which is an action, not a state check

Use is_displayed() to check visibility and is_enabled() to check if the element can be interacted with.

5fill in blank

hard

Fill all three blanks to create a test that checks if a radio button is visible, enabled, and selected.

Selenium Python

radio = driver.find_element(By.CSS_SELECTOR, "input[type='radio']")
if radio.[1]() and radio.[2]() and radio.[3]():
    print("Radio button is ready and selected")

Drag options to blanks, or click blank then click option'

Ais_displayed

Bis_enabled

Cis_selected

Dclick

Attempts:

3 left

💡 Hint

Common Mistakes

Using click() instead of a state check

Mixing up enabled and selected methods

Check visibility with is_displayed(), enabled state with is_enabled(), and selection with is_selected().

Practice

1. Which Selenium method checks if a web element is visible on the page?

easy

A. is_enabled()

B. is_visible()

C. is_selected()

D. is_displayed()

Solution

1. Step 1: Understand the purpose of is_displayed()

   This method returns True if the element is visible to the user on the page.

2. Step 2: Compare with other methods

   is_enabled() checks if the element can be interacted with, is_selected() checks selection state, and is_visible() is not a valid Selenium method.

3. Final Answer:

   is_displayed() -> Option D

4. Quick Check:

   Visibility check = is_displayed() [OK]

Hint: Visible? Use is_displayed() method [OK]

Common Mistakes:

• Confusing is_enabled() with visibility
• Using is_selected() for visibility
• Assuming is_visible() exists in Selenium

2. Which of the following is the correct syntax to check if a checkbox element is selected in Selenium Python?

easy

A. checkbox.is_selected()

B. checkbox.selected()

C. checkbox.isSelected()

D. checkbox.selected

Solution

1. Step 1: Recall Selenium Python method names

   In Selenium Python, the method to check selection is is_selected() with underscores and parentheses.

2. Step 2: Identify incorrect syntax

   selected() and selected are invalid; isSelected() is Java style, not Python.

3. Final Answer:

   checkbox.is_selected() -> Option A

4. Quick Check:

   Check selected? Use is_selected() [OK]

Hint: Use is_selected() with parentheses for selection check [OK]

Common Mistakes:

• Using Java method style isSelected() in Python
• Omitting parentheses after method name
• Using property 'selected' instead of method

3. Given the following code snippet, what will be the output if the button is visible but disabled?

button = driver.find_element(By.ID, 'submit')
print(button.is_displayed())
print(button.is_enabled())

medium

A. True\nFalse

B. False\nTrue

C. True\nTrue

D. False\nFalse

Solution

1. Step 1: Understand is_displayed() output

   Since the button is visible, is_displayed() returns True.

2. Step 2: Understand is_enabled() output

   The button is disabled, so is_enabled() returns False.

3. Final Answer:

   True\nFalse -> Option A

4. Quick Check:

   Visible = True, Enabled = False [OK]

Hint: Visible True, Enabled False if button disabled [OK]

Common Mistakes:

• Assuming disabled means not visible
• Mixing up is_displayed() and is_enabled() results
• Expecting both to be True for visible button

4. You wrote this code to check if a checkbox is selected:

checkbox = driver.find_element(By.NAME, 'agree')
if checkbox.selected():
    print('Selected')
else:
    print('Not selected')

What is the error here?

medium

A. Print statements should be inside quotes

B. Missing parentheses after find_element

C. selected() is not a valid method; should use is_selected()

D. Checkbox element locator is incorrect

Solution

1. Step 1: Check method name for selection

   The correct method to check selection in Selenium Python is is_selected(), not selected().

2. Step 2: Verify other code parts

   Parentheses after find_element are correct, locator looks valid, and print statements are properly quoted.

3. Final Answer:

   selected() is not a valid method; should use is_selected() -> Option C

4. Quick Check:

   Use is_selected() method for checkbox state [OK]

Hint: Use is_selected(), not selected() method [OK]

Common Mistakes:

• Using selected() instead of is_selected()
• Confusing method names with Java syntax
• Ignoring method parentheses

5. You want to write a test that clicks a button only if it is visible and enabled. Which code snippet correctly checks these conditions before clicking?

button = driver.find_element(By.ID, 'save')

hard

A. if button.is_displayed() or button.is_enabled():
button.click()

B. if button.is_displayed() and button.is_enabled():
button.click()

C. if button.is_selected() and button.is_enabled():
button.click()

D. if button.is_enabled():
button.click()

Solution

1. Step 1: Identify conditions for clicking

   The button must be visible (is_displayed()) and enabled (is_enabled()) to be safely clicked.

2. Step 2: Analyze each option

   if button.is_displayed() and button.is_enabled(): button.click() uses both conditions with 'and', which is correct. if button.is_selected() and button.is_enabled(): button.click() wrongly uses is_selected() which is for checkboxes/radios. if button.is_displayed() or button.is_enabled(): button.click() uses 'or' which may click if only one condition is true. if button.is_enabled(): button.click() checks only enabled, ignoring visibility.

3. Final Answer:

   if button.is_displayed() and button.is_enabled():\n button.click() -> Option B

4. Quick Check:

   Click only if visible AND enabled [OK]

Hint: Use and with is_displayed() and is_enabled() before click [OK]

Common Mistakes:

• Using or instead of and for conditions
• Checking is_selected() for buttons
• Ignoring visibility check before clicking