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Selenium Pythontesting~20 mins

Checking element state (displayed, enabled, selected) in Selenium Python - Practice Problems & Coding Challenges

Choose your learning style10 modes available
Challenge - 5 Problems
🎖️
Element State Master
Get all challenges correct to earn this badge!
Test your skills under time pressure!
❓ Predict Output
intermediate
2:00remaining
Check if a button is enabled using Selenium
What will be the output of this code snippet when the button is enabled on the page?
Selenium Python
from selenium import webdriver
from selenium.webdriver.common.by import By

# Assume driver is already initialized and page loaded
button = driver.find_element(By.ID, 'submit-btn')
print(button.is_enabled())
ARaises NoSuchElementException
BTrue
CNone
DFalse
Attempts:
2 left
💡 Hint
The is_enabled() method returns True if the element is enabled and can be interacted with.
❓ assertion
intermediate
2:00remaining
Assert that a checkbox is selected
Which assertion correctly verifies that a checkbox with id 'agree' is selected?
Selenium Python
checkbox = driver.find_element(By.ID, 'agree')
Aassert checkbox.is_enabled() == False
Bassert checkbox.is_displayed() == True
Cassert checkbox.get_attribute('checked') == 'false'
Dassert checkbox.is_selected() == True
Attempts:
2 left
💡 Hint
Use the method that checks if the element is selected.
🔧 Debug
advanced
2:00remaining
Identify the error in checking if an element is displayed
What error will this code raise when the element with id 'hidden-div' is not present on the page?
Selenium Python
element = driver.find_element(By.ID, 'hidden-div')
print(element.is_displayed())
ANoSuchElementException
BAttributeError
CTimeoutException
DStaleElementReferenceException
Attempts:
2 left
💡 Hint
Check what happens when find_element cannot find the element.
🧠 Conceptual
advanced
2:00remaining
Understanding difference between is_displayed() and is_enabled()
Which statement correctly describes the difference between is_displayed() and is_enabled() methods in Selenium?
Ais_displayed() checks if element is visible; is_enabled() checks if element can be interacted with
Bis_displayed() checks if element is enabled; is_enabled() checks if element is visible
CBoth methods check if element is visible on the page
DBoth methods check if element is enabled for interaction
Attempts:
2 left
💡 Hint
Think about visibility versus interactivity.
❓ framework
expert
3:00remaining
Best practice for waiting until a checkbox is selected
Which Selenium WebDriverWait usage correctly waits until a checkbox with id 'subscribe' is selected?
Selenium Python
from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.support import expected_conditions as EC
from selenium.webdriver.common.by import By

wait = WebDriverWait(driver, 10)
Await.until(EC.visibility_of_element_located((By.ID, 'subscribe')))
Bwait.until(EC.element_to_be_clickable((By.ID, 'subscribe')))
Cwait.until(EC.element_to_be_selected((By.ID, 'subscribe')))
Dwait.until(EC.presence_of_element_located((By.ID, 'subscribe')))
Attempts:
2 left
💡 Hint
Use the expected condition that waits for selection state.

Practice

(1/5)
1. Which Selenium method checks if a web element is visible on the page?
easy
A. is_enabled()
B. is_visible()
C. is_selected()
D. is_displayed()

Solution

  1. Step 1: Understand the purpose of is_displayed()

    This method returns True if the element is visible to the user on the page.
  2. Step 2: Compare with other methods

    is_enabled() checks if the element can be interacted with, is_selected() checks selection state, and is_visible() is not a valid Selenium method.
  3. Final Answer:

    is_displayed() -> Option D
  4. Quick Check:

    Visibility check = is_displayed() [OK]
Hint: Visible? Use is_displayed() method [OK]
Common Mistakes:
  • Confusing is_enabled() with visibility
  • Using is_selected() for visibility
  • Assuming is_visible() exists in Selenium
2. Which of the following is the correct syntax to check if a checkbox element is selected in Selenium Python?
easy
A. checkbox.is_selected()
B. checkbox.selected()
C. checkbox.isSelected()
D. checkbox.selected

Solution

  1. Step 1: Recall Selenium Python method names

    In Selenium Python, the method to check selection is is_selected() with underscores and parentheses.
  2. Step 2: Identify incorrect syntax

    selected() and selected are invalid; isSelected() is Java style, not Python.
  3. Final Answer:

    checkbox.is_selected() -> Option A
  4. Quick Check:

    Check selected? Use is_selected() [OK]
Hint: Use is_selected() with parentheses for selection check [OK]
Common Mistakes:
  • Using Java method style isSelected() in Python
  • Omitting parentheses after method name
  • Using property 'selected' instead of method
3. Given the following code snippet, what will be the output if the button is visible but disabled?
button = driver.find_element(By.ID, 'submit')
print(button.is_displayed())
print(button.is_enabled())
medium
A. True\nFalse
B. False\nTrue
C. True\nTrue
D. False\nFalse

Solution

  1. Step 1: Understand is_displayed() output

    Since the button is visible, is_displayed() returns True.
  2. Step 2: Understand is_enabled() output

    The button is disabled, so is_enabled() returns False.
  3. Final Answer:

    True\nFalse -> Option A
  4. Quick Check:

    Visible = True, Enabled = False [OK]
Hint: Visible True, Enabled False if button disabled [OK]
Common Mistakes:
  • Assuming disabled means not visible
  • Mixing up is_displayed() and is_enabled() results
  • Expecting both to be True for visible button
4. You wrote this code to check if a checkbox is selected:
checkbox = driver.find_element(By.NAME, 'agree')
if checkbox.selected():
    print('Selected')
else:
    print('Not selected')
What is the error here?
medium
A. Print statements should be inside quotes
B. Missing parentheses after find_element
C. selected() is not a valid method; should use is_selected()
D. Checkbox element locator is incorrect

Solution

  1. Step 1: Check method name for selection

    The correct method to check selection in Selenium Python is is_selected(), not selected().
  2. Step 2: Verify other code parts

    Parentheses after find_element are correct, locator looks valid, and print statements are properly quoted.
  3. Final Answer:

    selected() is not a valid method; should use is_selected() -> Option C
  4. Quick Check:

    Use is_selected() method for checkbox state [OK]
Hint: Use is_selected(), not selected() method [OK]
Common Mistakes:
  • Using selected() instead of is_selected()
  • Confusing method names with Java syntax
  • Ignoring method parentheses
5. You want to write a test that clicks a button only if it is visible and enabled. Which code snippet correctly checks these conditions before clicking?
button = driver.find_element(By.ID, 'save')
hard
A. if button.is_displayed() or button.is_enabled(): button.click()
B. if button.is_displayed() and button.is_enabled(): button.click()
C. if button.is_selected() and button.is_enabled(): button.click()
D. if button.is_enabled(): button.click()

Solution

  1. Step 1: Identify conditions for clicking

    The button must be visible (is_displayed()) and enabled (is_enabled()) to be safely clicked.
  2. Step 2: Analyze each option

    if button.is_displayed() and button.is_enabled(): button.click() uses both conditions with 'and', which is correct. if button.is_selected() and button.is_enabled(): button.click() wrongly uses is_selected() which is for checkboxes/radios. if button.is_displayed() or button.is_enabled(): button.click() uses 'or' which may click if only one condition is true. if button.is_enabled(): button.click() checks only enabled, ignoring visibility.
  3. Final Answer:

    if button.is_displayed() and button.is_enabled():\n button.click() -> Option B
  4. Quick Check:

    Click only if visible AND enabled [OK]
Hint: Use and with is_displayed() and is_enabled() before click [OK]
Common Mistakes:
  • Using or instead of and for conditions
  • Checking is_selected() for buttons
  • Ignoring visibility check before clicking
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10 questions~5 mineasy hard