A repeat loop runs code over and over until you tell it to stop. You use break to stop the loop when you want.
Repeat loop with break in R Programming
repeat {
# code to repeat
if (condition) {
break
}
}The repeat loop runs forever unless you use break inside it.
You check a condition inside the loop and use break to stop repeating.
count <- 1 repeat { print(count) if (count == 5) { break } count <- count + 1 }
repeat {
answer <- readline(prompt = "Type 'stop' to end: ")
if (answer == "stop") {
break
}
print(paste("You typed:", answer))
}This program counts from 1 to 3, printing each number, then stops the loop.
count <- 1 repeat { print(paste("Count is", count)) if (count >= 3) { break } count <- count + 1 }
Always make sure your repeat loop has a break condition, or it will run forever.
You can use break anywhere inside the loop to stop it immediately.
repeat loops run code repeatedly until break stops them.
Use break inside the loop to stop when a condition is met.
This is useful when you don't know how many times you need to repeat in advance.
Practice
What does the repeat loop do in R?
Choose the best description.
Solution
Step 1: Understand the repeat loop behavior and compare options
Therepeatloop in R runs indefinitely until abreakis encountered. Only "It runs code repeatedly until abreakstatement stops it." correctly describes that the loop runs repeatedly untilbreakstops it.Final Answer:
It runs code repeatedly until abreakstatement stops it. -> Option BQuick Check:
repeat loop = runs until break [OK]
- Thinking repeat loops run a fixed number of times
- Confusing repeat with for or while loops
- Assuming repeat loops stop automatically without break
Which of the following is the correct syntax to start a repeat loop in R?
?Solution
Step 1: Recall the syntax of repeat loops in R and check options
The correct syntax isrepeat { ... }without parentheses or other symbols. Only repeat { } matches the correct syntax exactly.Final Answer:
repeat { } -> Option AQuick Check:
repeat loop syntax = repeat { } [OK]
- Adding parentheses after repeat
- Using square brackets instead of braces
- Using keywords like do with repeat
What will be the output of this R code?
i <- 1
repeat {
if (i > 3) break
print(i)
i <- i + 1
}Solution
Step 1: Trace the loop iterations
i starts at 1. Loop checks if i > 3, breaks if true. Otherwise, prints i and increments i by 1. When i becomes 4, condition i > 3 is true, so break stops the loop. Values printed are 1, 2, and 3 before break.Final Answer:
[1] 1 [1] 2 [1] 3 -> Option DQuick Check:
Prints 1 to 3 then breaks [OK]
- Expecting it to print 4
- Thinking it runs infinitely
- Forgetting to increment i
Find the error in this R code using repeat and break:
count <- 1
repeat {
print(count)
if (count == 5)
break
}Solution
Step 1: Check loop variable changes and behavior
The variablecountis printed but never increased, so it stays 1 forever. Sincecountnever reaches 5,breakis never triggered, causing an infinite loop.Final Answer:
The variablecountis never incremented, causing an infinite loop. -> Option AQuick Check:
Missing increment causes infinite loop [OK]
- Forgetting to increment the loop counter
- Misplacing the break statement
- Incorrect loop syntax assumptions
Write a repeat loop in R that prints numbers from 10 down to 1 and then stops.
Which code snippet correctly does this?
?Solution
Step 1: Understand the counting direction and check options
We want to print from 10 down to 1, then stop. So i starts at 10 and decreases by 1 each loop. i <- 10 repeat { print(i) i <- i - 1 if (i < 0) break } prints i, then decrements i, and breaks when i < 0, so it prints 10 down to 0 inclusive, but since break is after decrement, it stops after printing 0. To print 10 down to 1, break should be when i < 1. i <- 10 repeat { print(i) if (i == 1) break i <- i - 1 } prints i, breaks when i == 1, then decrements i, so it prints 10 down to 1 correctly and stops. Therefore, i <- 10 repeat { print(i) if (i == 1) break i <- i - 1 } is the correct code snippet.Final Answer:
i <- 10 repeat { print(i) if (i == 1) break i <- i - 1 } -> Option CQuick Check:
Counts down 10 to 1 then breaks [OK]
- Breaking before printing 1, missing last number
- Incrementing instead of decrementing
- Wrong break condition causing infinite loop
Ready to prove it?
Pass the test and this pattern moves unknown
