Repeat loop with break in R Programming - Interactive Code Practice

Practice - 5 Tasks

1fill in blank

easy

Complete the code to start an infinite repeat loop.

R Programming

repeat [1] { print("Hello") break }

Drag options to blanks, or click blank then click option'

A{

B(

C[

D<

Attempts:

3 left

💡 Hint

Common Mistakes

Using parentheses or square brackets instead of curly braces.

Forgetting to open the block with {.

In R, a repeat loop starts with the keyword 'repeat' followed by a block enclosed in curly braces { }.

2fill in blank

medium

Complete the code to break out of the repeat loop when x is greater than 5.

R Programming

x <- 1
repeat {
  if (x [1] 5) break
  print(x)
  x <- x + 1
}

Drag options to blanks, or click blank then click option'

A<=

B>

C==

D<

Attempts:

3 left

💡 Hint

Common Mistakes

Using <= or < which break too early.

Using == which breaks only when x equals 5.

The break should happen when x is greater than 5, so the condition is x > 5.

3fill in blank

hard

Fix the error in the repeat loop to correctly increment x and break when x equals 3.

R Programming

x <- 0
repeat {
  x <- x [1] 1
  if (x == 3) break
  print(x)
}

Drag options to blanks, or click blank then click option'

A+

B/

C*

D-

Attempts:

3 left

💡 Hint

Common Mistakes

Using subtraction or multiplication instead of addition.

Forgetting to increment x causing an infinite loop.

To increase x by 1 each time, use the + operator.

4fill in blank

hard

Fill both blanks to create a repeat loop that prints numbers 1 to 4 and breaks after.

R Programming

x <- 1
repeat {
  print(x)
  x <- x [1] 1
  if (x [2] 5) break
}

Drag options to blanks, or click blank then click option'

A+

B-

C>=

D<

Attempts:

3 left

💡 Hint

Common Mistakes

Using wrong operators for increment or condition.

Breaking too early or too late.

Increment x by 1 each time and break when x is greater or equal to 5.

5fill in blank

hard

Fill all three blanks to create a repeat loop that sums numbers from 1 to 5 and breaks after.

R Programming

sum <- 0
x <- 1
repeat {
  sum <- sum [1] x
  x <- x [2] 1
  if (x [3] 6) break
}
print(sum)

Drag options to blanks, or click blank then click option'

A+

C>=

D<

Attempts:

3 left

💡 Hint

Common Mistakes

Using wrong operators for addition or comparison.

Breaking too early or forgetting to increment.

Add x to sum, increment x by 1, and break when x is 6 or more.