Repeat loop with break in R Programming - Time & Space Complexity
We want to understand how long a repeat loop with a break runs as the input size changes.
Specifically, how many times does the loop repeat before it stops?
Analyze the time complexity of the following code snippet.
i <- 1
repeat {
if (i > n) {
break
}
print(i)
i <- i + 1
}
This code counts from 1 up to n, printing each number, then stops.
Identify the loops, recursion, array traversals that repeat.
- Primary operation: The repeat loop that prints numbers.
- How many times: It runs once for each number from 1 to n, so n times.
As n gets bigger, the loop runs more times, directly matching n.
| Input Size (n) | Approx. Operations |
|---|---|
| 10 | About 10 repeats |
| 100 | About 100 repeats |
| 1000 | About 1000 repeats |
Pattern observation: The number of repeats grows evenly as n grows.
Time Complexity: O(n)
This means the time to finish grows directly with the size of n.
[X] Wrong: "The repeat loop always runs forever because it has no set end."
[OK] Correct: The break condition stops the loop once i passes n, so it does end after n repeats.
Understanding how loops with breaks behave helps you explain how code runs step-by-step and how long it takes.
"What if the break condition checked for i > n^2 instead? How would the time complexity change?"
Practice
What does the repeat loop do in R?
Choose the best description.
Solution
Step 1: Understand the repeat loop behavior and compare options
Therepeatloop in R runs indefinitely until abreakis encountered. Only "It runs code repeatedly until abreakstatement stops it." correctly describes that the loop runs repeatedly untilbreakstops it.Final Answer:
It runs code repeatedly until abreakstatement stops it. -> Option BQuick Check:
repeat loop = runs until break [OK]
- Thinking repeat loops run a fixed number of times
- Confusing repeat with for or while loops
- Assuming repeat loops stop automatically without break
Which of the following is the correct syntax to start a repeat loop in R?
?Solution
Step 1: Recall the syntax of repeat loops in R and check options
The correct syntax isrepeat { ... }without parentheses or other symbols. Only repeat { } matches the correct syntax exactly.Final Answer:
repeat { } -> Option AQuick Check:
repeat loop syntax = repeat { } [OK]
- Adding parentheses after repeat
- Using square brackets instead of braces
- Using keywords like do with repeat
What will be the output of this R code?
i <- 1
repeat {
if (i > 3) break
print(i)
i <- i + 1
}Solution
Step 1: Trace the loop iterations
i starts at 1. Loop checks if i > 3, breaks if true. Otherwise, prints i and increments i by 1. When i becomes 4, condition i > 3 is true, so break stops the loop. Values printed are 1, 2, and 3 before break.Final Answer:
[1] 1 [1] 2 [1] 3 -> Option DQuick Check:
Prints 1 to 3 then breaks [OK]
- Expecting it to print 4
- Thinking it runs infinitely
- Forgetting to increment i
Find the error in this R code using repeat and break:
count <- 1
repeat {
print(count)
if (count == 5)
break
}Solution
Step 1: Check loop variable changes and behavior
The variablecountis printed but never increased, so it stays 1 forever. Sincecountnever reaches 5,breakis never triggered, causing an infinite loop.Final Answer:
The variablecountis never incremented, causing an infinite loop. -> Option AQuick Check:
Missing increment causes infinite loop [OK]
- Forgetting to increment the loop counter
- Misplacing the break statement
- Incorrect loop syntax assumptions
Write a repeat loop in R that prints numbers from 10 down to 1 and then stops.
Which code snippet correctly does this?
?Solution
Step 1: Understand the counting direction and check options
We want to print from 10 down to 1, then stop. So i starts at 10 and decreases by 1 each loop. i <- 10 repeat { print(i) i <- i - 1 if (i < 0) break } prints i, then decrements i, and breaks when i < 0, so it prints 10 down to 0 inclusive, but since break is after decrement, it stops after printing 0. To print 10 down to 1, break should be when i < 1. i <- 10 repeat { print(i) if (i == 1) break i <- i - 1 } prints i, breaks when i == 1, then decrements i, so it prints 10 down to 1 correctly and stops. Therefore, i <- 10 repeat { print(i) if (i == 1) break i <- i - 1 } is the correct code snippet.Final Answer:
i <- 10 repeat { print(i) if (i == 1) break i <- i - 1 } -> Option CQuick Check:
Counts down 10 to 1 then breaks [OK]
- Breaking before printing 1, missing last number
- Incrementing instead of decrementing
- Wrong break condition causing infinite loop
Ready to prove it?
Pass the test and this pattern moves unknown
