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Javascriptprogramming~10 mins

Continue statement in Javascript - Interactive Code Practice

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Practice - 5 Tasks
Answer the questions below
1fill in blank
easy

Complete the code to skip the current loop iteration when the number is 3.

Javascript
for (let i = 1; i <= 5; i++) {
  if (i === 3) {
    [1];
  }
  console.log(i);
}
Drag options to blanks, or click blank then click option'
Abreak
Bcontinue
Creturn
Dstop
Attempts:
3 left
💡 Hint
Common Mistakes
Using 'break' instead of 'continue' stops the entire loop.
Using 'return' inside a loop without a function causes errors.
2fill in blank
medium

Complete the code to print only odd numbers from 1 to 5 using continue.

Javascript
for (let i = 1; i <= 5; i++) {
  if (i % 2 === 0) {
    [1];
  }
  console.log(i);
}
Drag options to blanks, or click blank then click option'
Astop
Bbreak
Ccontinue
Dskip
Attempts:
3 left
💡 Hint
Common Mistakes
Using 'break' stops the loop entirely.
Using 'skip' is not a valid JavaScript statement.
3fill in blank
hard

Fix the error in the loop to skip printing number 4.

Javascript
for (let num = 1; num <= 5; num++) {
  if (num === 4) {
    [1];
  }
  console.log(num);
}
Drag options to blanks, or click blank then click option'
Aexit
Bbreak
Creturn
Dcontinue
Attempts:
3 left
💡 Hint
Common Mistakes
Using 'break' stops the entire loop.
Using 'return' outside a function causes errors.
4fill in blank
hard

Fill both blanks to skip even numbers and print only odd numbers from 1 to 6.

Javascript
for (let i = 1; i <= 6; i++) {
  if (i [1] 2 === 0) {
    [2];
  }
  console.log(i);
}
Drag options to blanks, or click blank then click option'
A%
Bcontinue
C===
D!==
Attempts:
3 left
💡 Hint
Common Mistakes
Using '===' instead of '%' for checking even numbers.
Using 'break' instead of 'continue'.
5fill in blank
hard

Fill all three blanks to skip numbers divisible by 3 and print others from 1 to 9.

Javascript
for (let n = 1; n <= 9; n++) {
  if (n [1] 3 [2] 0) {
    [3];
  }
  console.log(n);
}
Drag options to blanks, or click blank then click option'
A%
Bcontinue
C===
D!==
Attempts:
3 left
💡 Hint
Common Mistakes
Using 'break' instead of 'continue'.
Using '!== 0' instead of '=== 0' to check divisibility.

Practice

(1/5)
1. What does the continue statement do inside a loop in JavaScript?
easy
A. It skips the rest of the current loop iteration and moves to the next iteration.
B. It stops the entire loop immediately.
C. It restarts the whole program from the beginning.
D. It pauses the loop until a condition is met.

Solution

  1. Step 1: Understand the role of continue in loops

    The continue statement skips the remaining code inside the current loop iteration.
  2. Step 2: Identify what happens after continue

    After skipping, the loop moves directly to the next iteration without stopping the whole loop.
  3. Final Answer:

    It skips the rest of the current loop iteration and moves to the next iteration. -> Option A
  4. Quick Check:

    continue skips current step [OK]
Hint: Remember: continue skips current step, break stops loop [OK]
Common Mistakes:
  • Confusing continue with break
  • Thinking continue stops the loop
  • Believing continue restarts the program
2. Which of the following is the correct syntax to use continue inside a for loop in JavaScript?
easy
A. continue[];
B. continue;
C. continue loop;
D. continue()

Solution

  1. Step 1: Recall the syntax of continue

    The continue statement is used alone followed by a semicolon.
  2. Step 2: Check each option for syntax correctness

    continue; uses continue; which is correct. Options A, B, and C use invalid syntax.
  3. Final Answer:

    continue; -> Option B
  4. Quick Check:

    Correct syntax is continue; [OK]
Hint: Use continue as a statement, no parentheses or brackets [OK]
Common Mistakes:
  • Adding parentheses after continue
  • Using continue with labels incorrectly
  • Adding brackets or other symbols
3. What will be the output of the following code?
for (let i = 1; i <= 5; i++) {
  if (i === 3) continue;
  console.log(i);
}
medium
A. 1 2 3 4 5
B. 3 4 5
C. 1 2 4 5
D. 1 2

Solution

  1. Step 1: Analyze the loop and condition

    The loop runs from 1 to 5. When i is 3, continue skips the console.log.
  2. Step 2: Determine which numbers are printed

    Numbers 1, 2, 4, and 5 are printed. Number 3 is skipped.
  3. Final Answer:

    1 2 4 5 -> Option C
  4. Quick Check:

    continue skips 3, prints others [OK]
Hint: Skip printing when continue runs, others print [OK]
Common Mistakes:
  • Including the skipped number in output
  • Confusing continue with break
  • Ignoring the condition inside the loop
4. Find the error in this code snippet:
for (let i = 0; i < 5; i++) {
  if (i = 2) continue;
  console.log(i);
}
medium
A. The assignment operator (=) is used instead of comparison (===) in the if condition.
B. continue cannot be used inside for loops.
C. console.log should be before the if statement.
D. The loop condition should be i <= 5.

Solution

  1. Step 1: Identify the if condition mistake

    The condition uses i = 2 which assigns 2 to i instead of comparing.
  2. Step 2: Understand the effect of assignment in if

    Assignment returns 2 (truthy), so continue runs every time, causing an infinite loop or skipping all logs.
  3. Final Answer:

    The assignment operator (=) is used instead of comparison (===) in the if condition. -> Option A
  4. Quick Check:

    Use === for comparison, not = [OK]
Hint: Use === for comparison inside if, not = [OK]
Common Mistakes:
  • Using = instead of === in conditions
  • Thinking continue is invalid in for loops
  • Misplacing console.log inside loop
5. You want to print all numbers from 1 to 10 except multiples of 3 using a for loop and continue. Which code correctly achieves this?
hard
A. for(let i=1; i<=10; i++) { if(i % 3 === 0) return; console.log(i); }
B. for(let i=1; i<=10; i++) { if(i % 3 !== 0) continue; console.log(i); }
C. for(let i=1; i<=10; i++) { if(i % 3 === 0) break; console.log(i); }
D. for(let i=1; i<=10; i++) { if(i % 3 === 0) continue; console.log(i); }

Solution

  1. Step 1: Understand the goal

    We want to skip printing numbers divisible by 3, so use continue when i % 3 === 0.
  2. Step 2: Check each option

    for(let i=1; i<=10; i++) { if(i % 3 === 0) continue; console.log(i); } correctly skips multiples of 3 and prints others. for(let i=1; i<=10; i++) { if(i % 3 !== 0) continue; console.log(i); } skips non-multiples, wrong. for(let i=1; i<=10; i++) { if(i % 3 === 0) break; console.log(i); } uses break, stops loop early. for(let i=1; i<=10; i++) { if(i % 3 === 0) return; console.log(i); } uses return, invalid in this context.
  3. Final Answer:

    for(let i=1; i<=10; i++) { if(i % 3 === 0) continue; console.log(i); } -> Option D
  4. Quick Check:

    continue skips multiples of 3, prints rest [OK]
Hint: Use continue to skip unwanted cases inside loop [OK]
Common Mistakes:
  • Using break instead of continue
  • Reversing the condition logic
  • Using return inside loops incorrectly
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