Continue statement in Javascript - Mini Project: Build & Apply

Using the Continue Statement in JavaScript Loops

📖 Scenario: You are working on a simple program that processes a list of numbers. Sometimes, you want to skip certain numbers based on a condition and continue with the rest.

🎯 Goal: Build a JavaScript program that uses the continue statement inside a for loop to skip even numbers and print only odd numbers from a list.

📋 What You'll Learn

Create an array called numbers with the values [1, 2, 3, 4, 5, 6, 7, 8, 9, 10].

Create a variable called skipEven and set it to true.

Use a for loop to go through each number in numbers.

Inside the loop, use an if statement to check if skipEven is true and the current number is even.

If the number is even and skipEven is true, use the continue statement to skip printing that number.

Print only the numbers that are not skipped.

💡 Why This Matters

🌍 Real World

Skipping certain items in a list is common when filtering data, such as ignoring invalid entries or focusing on specific values.

💼 Career

Understanding how to control loops with continue helps in writing efficient code for data processing, web development, and automation tasks.

1

Create the numbers array

Create an array called numbers with these exact values: [1, 2, 3, 4, 5, 6, 7, 8, 9, 10].

Javascript

// Create the array called numbers with the values 1 to 10
// Your code here

Need a hint?

Use const numbers = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]; to create the array.

2

Add the skipEven variable

Create a variable called skipEven and set it to true.

Javascript

const numbers = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10];
// Create the variable skipEven and set it to true
// Your code here

Need a hint?

Use const skipEven = true; to create the variable.

3

Use a for loop with continue to skip even numbers

Use a for loop with the variable i to go through numbers. Inside the loop, use an if statement to check if skipEven is true and numbers[i] is even. If so, use continue to skip to the next number.

Javascript

const numbers = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10];
const skipEven = true;
// Use a for loop with i to go through numbers
// Inside the loop, if skipEven is true and numbers[i] is even, use continue
// Your code here

Need a hint?

Use for (let i = 0; i < numbers.length; i++) to loop. Use if (skipEven && numbers[i] % 2 === 0) to check even numbers and continue; to skip them.

4

Print the numbers that are not skipped

Print each number inside the loop that is not skipped by the continue statement using console.log(numbers[i]).

Javascript

const numbers = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10];
const skipEven = true;
for (let i = 0; i < numbers.length; i++) {
    if (skipEven && numbers[i] % 2 === 0) {
        continue;
    }
    // Print the current number
    // Your code here
}

Need a hint?

Use console.log(numbers[i]) to print the numbers that are not skipped.