Nested conditional statements help you make decisions inside other decisions. This lets your program check many things step by step.
When you want to check if a person is old enough and also if they have a ticket before entering a movie.
When you need to decide what to wear based on weather and time of day.
When you want to check if a number is positive, and if it is even or odd.
When you want to give different discounts based on customer type and purchase amount.
Syntax
Javascript
if (condition1) {
if (condition2) {
// code if both condition1 and condition2 are true
} else {
// code if condition1 is true but condition2 is false
}
} else {
// code if condition1 is false
}
You can put one if statement inside another to check multiple things.
Use curly braces { } to group the code inside each condition.
Examples
Check if someone is 18 or older, then check if they have a ticket.
Javascript
if (age >= 18) {
if (hasTicket) {
console.log('Allowed to enter');
} else {
console.log('No ticket');
}
} else {
console.log('Too young');
}
Check if score is passing, then check if it is excellent.
This program decides what to do based on temperature and rain. If it's warm and not raining, go for a walk. If it's warm but raining, take an umbrella. Otherwise, stay inside.
Javascript
const temperature = 30;
const isRaining = false;
if (temperature > 20) {
if (!isRaining) {
console.log('Go for a walk');
} else {
console.log('Take an umbrella');
}
} else {
console.log('Stay inside');
}
OutputSuccess
Important Notes
Indent your code inside each if or else block to keep it clear.
Too many nested conditions can be hard to read; consider other ways if it gets complicated.
Summary
Nested conditionals let you check one thing inside another.
Use them to make decisions that depend on multiple checks.
Keep your code clean and easy to read by using proper indentation.
Practice
(1/5)
1. What does a nested conditional statement mean in JavaScript? if (condition1) { if (condition2) { /* code */ } }
easy
A. A loop inside a condition
B. A condition inside another condition
C. Two conditions checked at the same time
D. A function inside a condition
Solution
Step 1: Understand the structure of nested conditionals
Nested conditionals mean one if statement is placed inside another if statement's block.
Step 2: Identify the meaning of the code snippet
The code checks condition1 first, and only if true, it checks condition2 inside it.
2. Which of the following is the correct syntax for nested if statements in JavaScript?
easy
A. if (a > 0) { if (b > 0) { console.log('Both positive'); } }
B. if (a > 0) if (b > 0) console.log('Both positive'); }
C. if (a > 0) { if (b > 0) console.log('Both positive'); } else }
D. if a > 0 { if b > 0 { console.log('Both positive'); } }
Solution
Step 1: Check proper use of braces and parentheses
if (a > 0) { if (b > 0) { console.log('Both positive'); } } uses parentheses for conditions and braces to group code blocks correctly.
Step 2: Verify syntax correctness
The other options have missing or misplaced braces or parentheses causing syntax errors.
Final Answer:
if (a > 0) { if (b > 0) { console.log('Both positive'); } } -> Option A
Quick Check:
Correct nested if syntax = if (a > 0) { if (b > 0) { console.log('Both positive'); } } [OK]
Hint: Match each if with parentheses and braces [OK]
Common Mistakes:
Missing braces for inner if block
Omitting parentheses around conditions
Extra or misplaced braces
3. What will be the output of this code?
let x = 5; if (x > 0) { if (x < 10) { console.log('A'); } else { console.log('B'); } } else { console.log('C'); }
medium
A. No output
B. B
C. C
D. A
Solution
Step 1: Evaluate the outer if condition
x = 5, which is greater than 0, so the outer if block runs.
Step 2: Evaluate the inner if condition
Inside, x < 10 is true (5 < 10), so it prints 'A'.
Final Answer:
A -> Option D
Quick Check:
5 > 0 and 5 < 10 prints 'A' [OK]
Hint: Check outer condition first, then inner [OK]
Common Mistakes:
Ignoring inner else block
Confusing output with 'B' or 'C'
Assuming no output if conditions are true
4. Find the error in this nested conditional code:
let num = 10; if (num > 5) { if num < 15 { console.log('Inside range'); } }
medium
A. Using console.log incorrectly
B. Missing braces for outer if block
C. Missing parentheses around inner if condition
D. No error, code is correct
Solution
Step 1: Check syntax of inner if statement
Inner if is written as if num < 15 { missing parentheses around condition.
Step 2: Confirm correct syntax for if statements
JavaScript requires parentheses around conditions: if (num < 15) {.
Final Answer:
Missing parentheses around inner if condition -> Option C
Quick Check:
if conditions need parentheses [OK]
Hint: Always put parentheses around if conditions [OK]
Common Mistakes:
Forgetting parentheses in if conditions
Assuming braces are optional
Thinking console.log causes error
5. You want to write a nested conditional that prints: - 'Small positive' if a number is > 0 and < 10 - 'Large positive' if a number is >= 10 - 'Non-positive' otherwise Which code correctly implements this?
hard
A. if (num > 0) { if (num < 10) { console.log('Small positive'); } else { console.log('Large positive'); } } else { console.log('Non-positive'); }
B. if (num > 0 && num < 10) { console.log('Small positive'); } else if (num >= 10) { console.log('Large positive'); } else { console.log('Non-positive'); }
C. if (num > 0) { if (num <= 10) { console.log('Small positive'); } else { console.log('Large positive'); } } else { console.log('Non-positive'); }
D. if (num >= 0) { if (num < 10) { console.log('Small positive'); } else { console.log('Large positive'); } } else { console.log('Non-positive'); }
Solution
Step 1: Check conditions for small positive numbers
if (num > 0) { if (num < 10) { console.log('Small positive'); } else { console.log('Large positive'); } } else { console.log('Non-positive'); } checks if num > 0, then inside if num < 10 to print 'Small positive'.
Step 2: Check conditions for large positive and non-positive
Else inside outer if prints 'Large positive' for num >= 10, else prints 'Non-positive'.
Step 3: Verify other options
The option with combined conditions (&& and else if) is logically correct but does not use nested if statements. The option with outer condition num >= 0 incorrectly classifies 0 as 'Small positive'. The option with inner condition num <= 10 incorrectly classifies 10 as 'Small positive'.
Final Answer:
if (num > 0) { if (num < 10) { console.log('Small positive'); } else { console.log('Large positive'); } } else { console.log('Non-positive'); } -> Option A
Quick Check:
Nested if with correct ranges = if (num > 0) { if (num < 10) { console.log('Small positive'); } else { console.log('Large positive'); } } else { console.log('Non-positive'); } [OK]
Hint: Check each condition range carefully in nested ifs [OK]
Common Mistakes:
Using <= instead of < for small positive
Including zero as positive
Not nesting conditions properly
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