Continue statement in Javascript - Practice Problems & Coding Challenges

Challenge - 5 Problems

❓ Predict Output

intermediate

Output of loop with continue

What is the output of the following code?

Javascript

let result = '';
for (let i = 0; i < 5; i++) {
  if (i === 2) continue;
  result += i;
}
console.log(result);

A "01234"

B "024"

C "1234"

D "0134"

💡 Hint

The continue statement skips the current loop iteration when i equals 2.

The loop adds numbers 0 to 4 to the string except when i is 2, which is skipped by continue. So the output is "0134".

❓ Predict Output

intermediate

Continue in while loop output

What will be logged by this code?

Javascript

let count = 0;
let output = '';
while (count < 5) {
  count++;
  if (count === 3) continue;
  output += count;
}
console.log(output);

A "12345"

B "1245"

C "1234"

D "124"

💡 Hint

The continue skips adding when count is 3.

The loop increments count from 1 to 5. When count is 3, continue skips adding it to output. So output is '1' + '2' + '4' + '5' = '1245'.

❓ Predict Output

advanced

Continue with nested loops output

What is the output of this nested loop code?

Javascript

let result = '';
for (let i = 1; i <= 3; i++) {
  for (let j = 1; j <= 3; j++) {
    if (j === 2) continue;
    result += `${i}${j} `;
  }
}
console.log(result.trim());

A "11 13 21 23 31 33"

B "12 13 22 23 32 33"

C "11 12 13 21 22 23 31 32 33"

D "11 13 22 23 31 33"

💡 Hint

The continue skips inner loop when j equals 2.

For each i, j runs 1 to 3. When j is 2, continue skips adding. So pairs with j=2 are skipped. Result is '11 13 21 23 31 33'.

❓ Predict Output

advanced

Continue in forEach callback

What will this code output?

Javascript

const arr = [1, 2, 3, 4];
let sum = 0;
arr.forEach(num => {
  if (num === 3) continue;
  sum += num;
});
console.log(sum);

A 10

B 7

C SyntaxError

D TypeError

💡 Hint

continue cannot be used inside forEach callback.

The continue statement is invalid inside a forEach callback function and causes a SyntaxError.

🧠 Conceptual

expert

Effect of continue on loop variable

Consider this code snippet. What is the final value of i after the loop ends?

Javascript

let i = 0;
while (i < 5) {
  i++;
  if (i === 3) continue;
  i++;
}
console.log(i);

A 5

B 6

C 8

D 7

💡 Hint

Notice how continue skips the second increment when i is 3.

The loop increments i twice each iteration except when i is 3, where continue skips the second increment. The final i is 5.

Practice

1. What does the continue statement do inside a loop in JavaScript?

easy

A. It skips the rest of the current loop iteration and moves to the next iteration.

B. It stops the entire loop immediately.

C. It restarts the whole program from the beginning.

D. It pauses the loop until a condition is met.

Solution

1. Step 1: Understand the role of continue in loops

   The continue statement skips the remaining code inside the current loop iteration.

2. Step 2: Identify what happens after continue

   After skipping, the loop moves directly to the next iteration without stopping the whole loop.

3. Final Answer:

   It skips the rest of the current loop iteration and moves to the next iteration. -> Option A

4. Quick Check:

   continue skips current step [OK]

Hint: Remember: continue skips current step, break stops loop [OK]

Common Mistakes:

• Confusing continue with break
• Thinking continue stops the loop
• Believing continue restarts the program

2. Which of the following is the correct syntax to use continue inside a for loop in JavaScript?

easy

A. continue[];

B. continue;

C. continue loop;

D. continue()

Solution

1. Step 1: Recall the syntax of continue

   The continue statement is used alone followed by a semicolon.

2. Step 2: Check each option for syntax correctness

   continue; uses continue; which is correct. Options A, B, and C use invalid syntax.

3. Final Answer:

   continue; -> Option B

4. Quick Check:

   Correct syntax is continue; [OK]

Hint: Use continue as a statement, no parentheses or brackets [OK]

Common Mistakes:

• Adding parentheses after continue
• Using continue with labels incorrectly
• Adding brackets or other symbols

3. What will be the output of the following code?

for (let i = 1; i <= 5; i++) {
  if (i === 3) continue;
  console.log(i);
}

medium

A. 1 2 3 4 5

B. 3 4 5

C. 1 2 4 5

D. 1 2

Solution

1. Step 1: Analyze the loop and condition

   The loop runs from 1 to 5. When i is 3, continue skips the console.log.

2. Step 2: Determine which numbers are printed

   Numbers 1, 2, 4, and 5 are printed. Number 3 is skipped.

3. Final Answer:

   1 2 4 5 -> Option C

4. Quick Check:

   continue skips 3, prints others [OK]

Hint: Skip printing when continue runs, others print [OK]

Common Mistakes:

• Including the skipped number in output
• Confusing continue with break
• Ignoring the condition inside the loop

4. Find the error in this code snippet:

for (let i = 0; i < 5; i++) {
  if (i = 2) continue;
  console.log(i);
}

medium

A. The assignment operator (=) is used instead of comparison (===) in the if condition.

B. continue cannot be used inside for loops.

C. console.log should be before the if statement.

D. The loop condition should be i <= 5.

Solution

1. Step 1: Identify the if condition mistake

   The condition uses i = 2 which assigns 2 to i instead of comparing.

2. Step 2: Understand the effect of assignment in if

   Assignment returns 2 (truthy), so continue runs every time, causing an infinite loop or skipping all logs.

3. Final Answer:

   The assignment operator (=) is used instead of comparison (===) in the if condition. -> Option A

4. Quick Check:

   Use === for comparison, not = [OK]

Hint: Use === for comparison inside if, not = [OK]

Common Mistakes:

• Using = instead of === in conditions
• Thinking continue is invalid in for loops
• Misplacing console.log inside loop

5. You want to print all numbers from 1 to 10 except multiples of 3 using a for loop and continue. Which code correctly achieves this?

hard

A. for(let i=1; i<=10; i++) { if(i % 3 === 0) return; console.log(i); }

B. for(let i=1; i<=10; i++) { if(i % 3 !== 0) continue; console.log(i); }

C. for(let i=1; i<=10; i++) { if(i % 3 === 0) break; console.log(i); }

D. for(let i=1; i<=10; i++) { if(i % 3 === 0) continue; console.log(i); }

Solution

1. Step 1: Understand the goal

   We want to skip printing numbers divisible by 3, so use continue when i % 3 === 0.

2. Step 2: Check each option

   for(let i=1; i<=10; i++) { if(i % 3 === 0) continue; console.log(i); } correctly skips multiples of 3 and prints others. for(let i=1; i<=10; i++) { if(i % 3 !== 0) continue; console.log(i); } skips non-multiples, wrong. for(let i=1; i<=10; i++) { if(i % 3 === 0) break; console.log(i); } uses break, stops loop early. for(let i=1; i<=10; i++) { if(i % 3 === 0) return; console.log(i); } uses return, invalid in this context.

3. Final Answer:

   for(let i=1; i<=10; i++) { if(i % 3 === 0) continue; console.log(i); } -> Option D

4. Quick Check:

   continue skips multiples of 3, prints rest [OK]

Hint: Use continue to skip unwanted cases inside loop [OK]

Common Mistakes:

• Using break instead of continue
• Reversing the condition logic
• Using return inside loops incorrectly