Writing first Java program - Cheat Sheet & Quick Revision

Recall & Review

beginner

What is the basic structure of a Java program?

A Java program has a class with a <code>main</code> method inside. The <code>main</code> method is where the program starts running.

beginner

What does System.out.println() do in Java?

It prints text or values to the screen and moves to the next line, so you can see output from your program.

beginner

Why do we need the public static void main(String[] args) method?

This method is the entry point of any Java program. The computer looks for it to start running your code.

beginner

What is a class in Java?

A class is like a blueprint or a container that holds code. Every Java program needs at least one class.

beginner

How do you save and run a Java program?

Save the file with a .java extension and the same name as the class. Then use javac to compile and java to run it.

What keyword starts the main method in a Java program?

A public

B start

C begin

D main

The main method starts with the keyword public to make it accessible.

Which method prints text to the console in Java?

A System.out.print()

B print()

C System.out.println()

D console.log()

System.out.println() prints text and moves to a new line.

What file extension should a Java source file have?

A .exe

B .java

C .class

D .txt

Java source files must be saved with the .java extension.

What is the name of the method where Java starts running your program?

A main()

B run()

C start()

D init()

Java looks for the main() method to begin execution.

Which command compiles a Java program?

A runjava

B java

C compile

D javac

Use javac to compile Java source code into bytecode.

Explain the role of the main method in a Java program.

Think about where the computer looks first to run your code.

Describe the steps to write, save, compile, and run a simple Java program.

Consider the full process from typing code to seeing output.

Practice

1. What is the purpose of the main method in a Java program?

easy

A. It is the starting point where the program begins execution.

B. It defines a new class in Java.

C. It is used to declare variables.

D. It imports external libraries.

Solution

1. Step 1: Understand the role of the main method

   The main method is special because Java looks for it to start running the program.

2. Step 2: Identify the program entry point

   Without the main method, the program has no defined starting point to execute code.

3. Final Answer:

   It is the starting point where the program begins execution. -> Option A

4. Quick Check:

   Main method = program start [OK]

Hint: Remember: Java runs code starting from main method [OK]

Common Mistakes:

• Thinking main defines a class
• Confusing main with variable declaration
• Assuming main imports libraries

2. Which of the following is the correct syntax to print "Hello, World!" with a newline in Java?

easy

A. System.out.print("Hello, World!");

B. print("Hello, World!");

C. System.out.println("Hello, World!");

D. echo "Hello, World!";

Solution

1. Step 1: Identify the correct print method in Java

   Java uses System.out.println() to print text with a new line.

2. Step 2: Check each option for syntax correctness

   System.out.print("Hello, World!"); uses print which prints without a new line, but is valid. System.out.println("Hello, World!"); uses println which prints with a new line and is the common way. print("Hello, World!"); and D are not valid Java syntax.

3. Final Answer:

   System.out.println("Hello, World!"); -> Option C

4. Quick Check:

   Print line = System.out.println() [OK]

Hint: Use System.out.println() to print with a new line [OK]

Common Mistakes:

• Using print without System.out
• Using non-Java print commands
• Missing quotes around text

3. What will be the output of the following Java program?

public class Hello {
    public static void main(String[] args) {
        System.out.println("Welcome to Java!");
    }
}

medium

A. Syntax Error

B. Hello

C. Welcome to Java!\n

D. Welcome to Java!

Solution

1. Step 1: Read the print statement inside main

   The program prints the exact string "Welcome to Java!" using System.out.println.

2. Step 2: Understand println adds a new line but does not show \n literally

   The output shows the text and moves to the next line, but the new line is not visible as characters.

3. Final Answer:

   Welcome to Java! -> Option D

4. Quick Check:

   Print output = Welcome to Java! [OK]

Hint: System.out.println prints text exactly as given [OK]

Common Mistakes:

• Confusing output with class name
• Expecting \n characters in output
• Assuming syntax error without reason

4. Identify the error in the following Java program:

public class Test {
    public static void main(String[] args) {
        System.out.println("Hello Java")
    }
}

medium

A. Class name should be lowercase.

B. Missing semicolon after the print statement.

C. main method should not have String[] args.

D. System.out.println should be System.print.

Solution

1. Step 1: Check syntax of print statement

   The print statement is missing a semicolon at the end, which is required in Java.

2. Step 2: Verify other parts for correctness

   Class name capitalization is allowed, main method signature is correct, and System.out.println is the right method.

3. Final Answer:

   Missing semicolon after the print statement. -> Option B

4. Quick Check:

   Semicolon missing = syntax error [OK]

Hint: Always end statements with a semicolon in Java [OK]

Common Mistakes:

• Omitting semicolon at line end
• Changing class name case unnecessarily
• Incorrect main method signature

5. You want to create a Java program that prints "Good Morning!". Which of the following is the correct file name and class name combination to run the program successfully?

hard

A. File name: GoodMorning.java, Class name: GoodMorning

B. File name: goodmorning.java, Class name: GoodMorning

C. File name: GoodMorning.java, Class name: goodmorning

D. File name: GoodMorning.txt, Class name: GoodMorning

Solution

1. Step 1: Understand Java file and class naming rules

   The file name must exactly match the public class name including case, with .java extension.

2. Step 2: Check each option for matching names and extension

   File name: GoodMorning.java, Class name: GoodMorning matches file and class names exactly with correct extension. Options B and C have case mismatches. File name: GoodMorning.txt, Class name: GoodMorning has wrong file extension.

3. Final Answer:

   File name: GoodMorning.java, Class name: GoodMorning -> Option A

4. Quick Check:

   File name = Class name + .java [OK]

Hint: Match file name exactly with class name and use .java extension [OK]

Common Mistakes:

• Mismatching class and file names
• Using wrong file extension
• Ignoring case sensitivity