Writing first Java program - Practice Problems & Coding Challenges

Challenge - 5 Problems

❓ Predict Output

intermediate

What is the output of this Java program?

Look at this Java program. What will it print when run?

Java

public class HelloWorld {
    public static void main(String[] args) {
        System.out.println("Hello, Java!");
    }
}

A Hello, Java!

B hello, java!

C Hello Java

D Compilation error

💡 Hint

Check the exact text inside the quotes and capitalization.

The program prints exactly what is inside the quotes in System.out.println, including capitalization and punctuation.

🧠 Conceptual

intermediate

What is the role of the main method in a Java program?

In Java, what does the main method do?

A It stores all the variables used in the program.

B It automatically saves the program to a file.

C It is the starting point where the program begins execution.

D It defines the layout of the user interface.

💡 Hint

Think about what happens when you run a Java program.

The main method is where Java starts running the program. Without it, the program won't run.

🔧 Debug

advanced

What error does this Java program produce?

Look at this Java code. What error will it cause when compiled?

Java

public class Test {
    public static void main(String[] args) {
        System.out.println("Hello World");
    }
}

A Syntax error: missing curly brace

B No error, prints Hello World

C Runtime error: NullPointerException

D Syntax error: missing semicolon

💡 Hint

Check the end of the System.out.println line.

Java statements must end with a semicolon. This line is missing it, causing a syntax error.

📝 Syntax

advanced

Which option correctly declares the main method in Java?

Choose the correct way to write the main method header in Java.

A static public void main(String args)

B public static void main(String[] args)

C public void static main(String args[])

D void public static main(String[] args)

💡 Hint

Remember the order and types in the method signature.

The correct order is public static void main(String[] args). Other orders or missing brackets cause errors.

🚀 Application

expert

How many lines will this Java program print?

Consider this Java program. How many lines will it print when run?

Java

public class CountLines {
    public static void main(String[] args) {
        for (int i = 0; i < 3; i++) {
            System.out.println("Line " + i);
        }
    }
}

A 3

B 4

C 0

D 1

💡 Hint

Count how many times the loop runs.

The loop runs from i=0 to i=2, printing one line each time, so 3 lines total.

Practice

1. What is the purpose of the main method in a Java program?

easy

A. It is the starting point where the program begins execution.

B. It defines a new class in Java.

C. It is used to declare variables.

D. It imports external libraries.

Solution

1. Step 1: Understand the role of the main method

   The main method is special because Java looks for it to start running the program.

2. Step 2: Identify the program entry point

   Without the main method, the program has no defined starting point to execute code.

3. Final Answer:

   It is the starting point where the program begins execution. -> Option A

4. Quick Check:

   Main method = program start [OK]

Hint: Remember: Java runs code starting from main method [OK]

Common Mistakes:

• Thinking main defines a class
• Confusing main with variable declaration
• Assuming main imports libraries

2. Which of the following is the correct syntax to print "Hello, World!" with a newline in Java?

easy

A. System.out.print("Hello, World!");

B. print("Hello, World!");

C. System.out.println("Hello, World!");

D. echo "Hello, World!";

Solution

1. Step 1: Identify the correct print method in Java

   Java uses System.out.println() to print text with a new line.

2. Step 2: Check each option for syntax correctness

   System.out.print("Hello, World!"); uses print which prints without a new line, but is valid. System.out.println("Hello, World!"); uses println which prints with a new line and is the common way. print("Hello, World!"); and D are not valid Java syntax.

3. Final Answer:

   System.out.println("Hello, World!"); -> Option C

4. Quick Check:

   Print line = System.out.println() [OK]

Hint: Use System.out.println() to print with a new line [OK]

Common Mistakes:

• Using print without System.out
• Using non-Java print commands
• Missing quotes around text

3. What will be the output of the following Java program?

public class Hello {
    public static void main(String[] args) {
        System.out.println("Welcome to Java!");
    }
}

medium

A. Syntax Error

B. Hello

C. Welcome to Java!\n

D. Welcome to Java!

Solution

1. Step 1: Read the print statement inside main

   The program prints the exact string "Welcome to Java!" using System.out.println.

2. Step 2: Understand println adds a new line but does not show \n literally

   The output shows the text and moves to the next line, but the new line is not visible as characters.

3. Final Answer:

   Welcome to Java! -> Option D

4. Quick Check:

   Print output = Welcome to Java! [OK]

Hint: System.out.println prints text exactly as given [OK]

Common Mistakes:

• Confusing output with class name
• Expecting \n characters in output
• Assuming syntax error without reason

4. Identify the error in the following Java program:

public class Test {
    public static void main(String[] args) {
        System.out.println("Hello Java")
    }
}

medium

A. Class name should be lowercase.

B. Missing semicolon after the print statement.

C. main method should not have String[] args.

D. System.out.println should be System.print.

Solution

1. Step 1: Check syntax of print statement

   The print statement is missing a semicolon at the end, which is required in Java.

2. Step 2: Verify other parts for correctness

   Class name capitalization is allowed, main method signature is correct, and System.out.println is the right method.

3. Final Answer:

   Missing semicolon after the print statement. -> Option B

4. Quick Check:

   Semicolon missing = syntax error [OK]

Hint: Always end statements with a semicolon in Java [OK]

Common Mistakes:

• Omitting semicolon at line end
• Changing class name case unnecessarily
• Incorrect main method signature

5. You want to create a Java program that prints "Good Morning!". Which of the following is the correct file name and class name combination to run the program successfully?

hard

A. File name: GoodMorning.java, Class name: GoodMorning

B. File name: goodmorning.java, Class name: GoodMorning

C. File name: GoodMorning.java, Class name: goodmorning

D. File name: GoodMorning.txt, Class name: GoodMorning

Solution

1. Step 1: Understand Java file and class naming rules

   The file name must exactly match the public class name including case, with .java extension.

2. Step 2: Check each option for matching names and extension

   File name: GoodMorning.java, Class name: GoodMorning matches file and class names exactly with correct extension. Options B and C have case mismatches. File name: GoodMorning.txt, Class name: GoodMorning has wrong file extension.

3. Final Answer:

   File name: GoodMorning.java, Class name: GoodMorning -> Option A

4. Quick Check:

   File name = Class name + .java [OK]

Hint: Match file name exactly with class name and use .java extension [OK]

Common Mistakes:

• Mismatching class and file names
• Using wrong file extension
• Ignoring case sensitivity