Counter-based while loop in Java - Interactive Code Practice

Practice - 5 Tasks

1fill in blank

easy

Complete the code to initialize the counter variable.

Java

int count = [1];

Drag options to blanks, or click blank then click option'

A-1

B1

C0

D10

Attempts:

3 left

💡 Hint

Common Mistakes

Starting the counter at 1 instead of 0.

Using a negative number as the starting value.

The counter variable should start at 0 to count from the beginning.

2fill in blank

medium

Complete the code to write the while loop condition to run 5 times.

Java

while (count [1] 5) {
    System.out.println(count);
    count++;
}

Drag options to blanks, or click blank then click option'

A>=

B<

C>

D==

Attempts:

3 left

💡 Hint

Common Mistakes

Using greater than instead of less than.

Using equality which runs only once.

The loop should run while count is less than 5 to execute 5 times (0 to 4).

3fill in blank

hard

Fix the error in the loop increment statement.

Java

while (count < 5) {
    System.out.println(count);
    count[1];
}

Drag options to blanks, or click blank then click option'

A++

B+

C--

D+=

Attempts:

3 left

💡 Hint

Common Mistakes

Using '+' without assignment.

Using '--' which decreases the counter.

The increment operator '++' increases count by 1 each loop.

4fill in blank

hard

Fill both blanks to create a loop that counts down from 5 to 1.

Java

int count = [1];
while (count [2] 0) {
    System.out.println(count);
    count--;
}

Drag options to blanks, or click blank then click option'

A5

B0

C>

D<

Attempts:

3 left

💡 Hint

Common Mistakes

Starting count at 0 instead of 5.

Using '<' which would cause an infinite loop.

Start count at 5 and loop while count is greater than 0 to count down.

5fill in blank

hard

Fill all three blanks to create a loop that prints even numbers from 2 to 10.

Java

int count = [1];
while (count [2] 10) {
    System.out.println(count);
    count [3] 2;
}

Drag options to blanks, or click blank then click option'

A2

B<=

C+=

D1

Attempts:

3 left

💡 Hint

Common Mistakes

Starting at 1 instead of 2.

Using '<' which excludes 10.

Using '+' without assignment.

Start at 2, loop while count is less or equal to 10, and add 2 each time to print even numbers.

Practice

1. What is the main purpose of using a counter in a while loop in Java?

easy

A. To create an infinite loop

B. To store the result of the loop

C. To control how many times the loop runs

D. To skip loop iterations

Solution

1. Step 1: Understand the role of a counter

   A counter is a variable that keeps track of how many times the loop has run.

2. Step 2: Identify the purpose in a while loop

   The counter helps stop the loop after a fixed number of runs, preventing infinite loops.

3. Final Answer:

   To control how many times the loop runs -> Option C

4. Quick Check:

   Counter controls loop count = A [OK]

Hint: Counter limits loop repetitions to fixed times [OK]

Common Mistakes:

• Thinking counter stores results
• Assuming counter creates infinite loops
• Believing counter skips iterations

2. Which of the following is the correct way to initialize a counter variable for a while loop in Java?

easy

A. while (count = 0) {}

B. int count = 0;

C. int count == 0;

D. count := 0;

Solution

1. Step 1: Check Java variable initialization syntax

   Java uses int count = 0; to declare and initialize an integer variable.

2. Step 2: Identify incorrect options

   while (count = 0) {} uses assignment in while condition incorrectly, C uses double equals in declaration, D uses wrong assignment operator.

3. Final Answer:

   int count = 0; -> Option B

4. Quick Check:

   Correct Java int initialization = A [OK]

Hint: Use single equals (=) to assign variables in Java [OK]

Common Mistakes:

• Using == instead of = for assignment
• Trying to assign inside while condition
• Using := which is not Java syntax

3. What will be the output of this Java code?

int count = 1;
while (count <= 3) {
    System.out.print(count + " ");
    count++;
}

medium

A. 1 2 3

B. 0 1 2 3

C. 1 2 3 4

D. 3 2 1

Solution

1. Step 1: Analyze the loop start and condition

   The counter starts at 1 and runs while count is less than or equal to 3.

2. Step 2: Trace the output during each iteration

   It prints 1, then increments to 2, prints 2, increments to 3, prints 3, then increments to 4 and stops.

3. Final Answer:

   1 2 3 -> Option A

4. Quick Check:

   Prints 1 to 3 with spaces = B [OK]

Hint: Count from 1 to 3 prints 1 2 3 [OK]

Common Mistakes:

• Starting count at 0 instead of 1
• Printing after increment causing extra number
• Reversing the order of output

4. Identify the error in this Java code snippet:

int count = 1;
while (count < 5) {
    System.out.println(count);
}

medium

A. Counter variable is not incremented inside the loop

B. Loop condition should be count <= 5

C. Incorrect print statement syntax

D. Missing semicolon after while condition

Solution

1. Step 1: Check loop body for counter update

   The code does not increase count inside the loop, so count stays 1 forever.

2. Step 2: Understand effect of missing increment

   Without increment, the loop never ends, causing an infinite loop.

3. Final Answer:

   Counter variable is not incremented inside the loop -> Option A

4. Quick Check:

   Missing count++ causes infinite loop = D [OK]

Hint: Always update counter inside while loop [OK]

Common Mistakes:

• Forgetting to increment counter
• Changing loop condition incorrectly
• Assuming print syntax is wrong

5. You want to print all even numbers from 2 to 10 using a counter-based while loop in Java. Which code correctly does this?

hard

A. int count = 2;
while (count < 10) {
System.out.print(count + " " );
count += 2;
}

B. int count = 0;
while (count < 10) {
count += 2;
System.out.print(count + " " );
}

C. int count = 2;
while (count < 10) {
System.out.print(count + " " );
count++;
}

D. int count = 1;
while (count <= 10) {
if (count % 2 == 0) {
System.out.print(count + " " );
}
count++;
}

Solution

1. Step 1: Understand the goal to print even numbers 2 to 10

   We need to print 2,4,6,8,10 using a while loop and a counter.

2. Step 2: Analyze each option

   int count = 2; while (count < 10) { System.out.print(count + " " ); count += 2; } increments by 2 starting at 2, prints 2,4,6,8 misses 10. int count = 1; while (count <= 10) { if (count % 2 == 0) { System.out.print(count + " " ); } count++; } starts at 1, checks if even, prints if yes, increments by 1, correct. int count = 0; while (count < 10) { count += 2; System.out.print(count + " " ); } starts at 0, increments before print, prints 2,4,6,8 misses 10. int count = 2; while (count < 10) { System.out.print(count + " " ); count++; } increments by 1 but stops before 10, so misses 10.

3. Step 3: Choose the best option

   int count = 1; while (count <= 10) { if (count % 2 == 0) { System.out.print(count + " " ); } count++; } uses a counter-based loop with condition and checks evenness inside, which is a common pattern.

4. Final Answer:

   int count = 1; while (count <= 10) { if (count % 2 == 0) { System.out.print(count + " " ); } count++; } -> Option D

5. Quick Check:

   Check even inside loop and increment count = C [OK]

Hint: Check even inside loop, increment by 1 for all numbers [OK]

Common Mistakes:

• Incrementing by 1 but missing last number
• Starting count at 0 and printing before increment
• Not checking even condition inside loop