A counter-based while loop repeats a block of code while a counter variable meets a condition, usually increasing or decreasing the counter each time to eventually stop the loop.
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beginner
Why do we need a counter variable in a while loop?
The counter variable helps control how many times the loop runs. It changes each time the loop runs so the loop can stop when the counter reaches a limit.
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beginner
What happens if the counter is not updated inside a while loop?
If the counter is not updated, the loop condition may never become false, causing an infinite loop that runs forever.
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beginner
Example: What does this code print?
int i = 1;
while (i <= 3) {
System.out.println(i);
i++;
}
It prints:
1
2
3
The loop starts with i=1 and prints i, then increases i by 1 each time until i is greater than 3.
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beginner
How to avoid infinite loops in counter-based while loops?
Always update the counter inside the loop so the condition will eventually become false. Also, check the loop condition carefully before running the loop.
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What is the role of the counter in a counter-based while loop?
ATo store the output of the loop
BTo stop the program immediately
CTo control how many times the loop runs
DTo print messages inside the loop
✗ Incorrect
The counter controls the number of loop repetitions by changing each time the loop runs.
What happens if you forget to increase the counter inside a while loop?
AThe program will crash immediately
BThe loop will run forever (infinite loop)
CThe loop will run only once
DThe counter will automatically increase
✗ Incorrect
Without increasing the counter, the loop condition never becomes false, causing an infinite loop.
Which of these is a correct way to start a counter for a while loop that runs 5 times?
All these ways correctly use a counter to run the loop 5 times.
What will this code print?
int i = 3;
while (i > 0) {
System.out.println(i);
i--;
}
ANothing
B1 2 3
C0 1 2
D3 2 1
✗ Incorrect
The loop prints 3, then 2, then 1, decreasing i each time until i is 0.
Which part of a counter-based while loop changes each time the loop runs?
AThe counter variable
BThe loop condition
CThe program output
DThe loop keyword
✗ Incorrect
The counter variable is updated each time to eventually stop the loop.
Explain how a counter-based while loop works and why the counter must be updated inside the loop.
Think about how the loop knows when to stop.
You got /4 concepts.
Write a simple Java while loop that prints numbers from 1 to 5 using a counter.
Start with int i = 1; and use i <= 5 as condition.
You got /4 concepts.
Practice
(1/5)
1. What is the main purpose of using a counter in a while loop in Java?
easy
A. To create an infinite loop
B. To store the result of the loop
C. To control how many times the loop runs
D. To skip loop iterations
Solution
Step 1: Understand the role of a counter
A counter is a variable that keeps track of how many times the loop has run.
Step 2: Identify the purpose in a while loop
The counter helps stop the loop after a fixed number of runs, preventing infinite loops.
Final Answer:
To control how many times the loop runs -> Option C
Quick Check:
Counter controls loop count = A [OK]
Hint: Counter limits loop repetitions to fixed times [OK]
Common Mistakes:
Thinking counter stores results
Assuming counter creates infinite loops
Believing counter skips iterations
2. Which of the following is the correct way to initialize a counter variable for a while loop in Java?
easy
A. while (count = 0) {}
B. int count = 0;
C. int count == 0;
D. count := 0;
Solution
Step 1: Check Java variable initialization syntax
Java uses int count = 0; to declare and initialize an integer variable.
Step 2: Identify incorrect options
while (count = 0) {} uses assignment in while condition incorrectly, C uses double equals in declaration, D uses wrong assignment operator.
Final Answer:
int count = 0; -> Option B
Quick Check:
Correct Java int initialization = A [OK]
Hint: Use single equals (=) to assign variables in Java [OK]
Common Mistakes:
Using == instead of = for assignment
Trying to assign inside while condition
Using := which is not Java syntax
3. What will be the output of this Java code?
int count = 1;
while (count <= 3) {
System.out.print(count + " ");
count++;
}
medium
A. 1 2 3
B. 0 1 2 3
C. 1 2 3 4
D. 3 2 1
Solution
Step 1: Analyze the loop start and condition
The counter starts at 1 and runs while count is less than or equal to 3.
Step 2: Trace the output during each iteration
It prints 1, then increments to 2, prints 2, increments to 3, prints 3, then increments to 4 and stops.
Final Answer:
1 2 3 -> Option A
Quick Check:
Prints 1 to 3 with spaces = B [OK]
Hint: Count from 1 to 3 prints 1 2 3 [OK]
Common Mistakes:
Starting count at 0 instead of 1
Printing after increment causing extra number
Reversing the order of output
4. Identify the error in this Java code snippet:
int count = 1;
while (count < 5) {
System.out.println(count);
}
medium
A. Counter variable is not incremented inside the loop
B. Loop condition should be count <= 5
C. Incorrect print statement syntax
D. Missing semicolon after while condition
Solution
Step 1: Check loop body for counter update
The code does not increase count inside the loop, so count stays 1 forever.
Step 2: Understand effect of missing increment
Without increment, the loop never ends, causing an infinite loop.
Final Answer:
Counter variable is not incremented inside the loop -> Option A
Quick Check:
Missing count++ causes infinite loop = D [OK]
Hint: Always update counter inside while loop [OK]
Common Mistakes:
Forgetting to increment counter
Changing loop condition incorrectly
Assuming print syntax is wrong
5. You want to print all even numbers from 2 to 10 using a counter-based while loop in Java. Which code correctly does this?
hard
A. int count = 2;
while (count < 10) {
System.out.print(count + " " );
count += 2;
}
B. int count = 0;
while (count < 10) {
count += 2;
System.out.print(count + " " );
}
C. int count = 2;
while (count < 10) {
System.out.print(count + " " );
count++;
}
D. int count = 1;
while (count <= 10) {
if (count % 2 == 0) {
System.out.print(count + " " );
}
count++;
}
Solution
Step 1: Understand the goal to print even numbers 2 to 10
We need to print 2,4,6,8,10 using a while loop and a counter.
Step 2: Analyze each option
int count = 2;
while (count < 10) {
System.out.print(count + " " );
count += 2;
} increments by 2 starting at 2, prints 2,4,6,8 misses 10. int count = 1;
while (count <= 10) {
if (count % 2 == 0) {
System.out.print(count + " " );
}
count++;
} starts at 1, checks if even, prints if yes, increments by 1, correct. int count = 0;
while (count < 10) {
count += 2;
System.out.print(count + " " );
} starts at 0, increments before print, prints 2,4,6,8 misses 10. int count = 2;
while (count < 10) {
System.out.print(count + " " );
count++;
} increments by 1 but stops before 10, so misses 10.
Step 3: Choose the best option
int count = 1;
while (count <= 10) {
if (count % 2 == 0) {
System.out.print(count + " " );
}
count++;
} uses a counter-based loop with condition and checks evenness inside, which is a common pattern.
Final Answer:
int count = 1;
while (count <= 10) {
if (count % 2 == 0) {
System.out.print(count + " " );
}
count++;
} -> Option D
Quick Check:
Check even inside loop and increment count = C [OK]
Hint: Check even inside loop, increment by 1 for all numbers [OK]
Common Mistakes:
Incrementing by 1 but missing last number
Starting count at 0 and printing before increment
Not checking even condition inside loop
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