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Goprogramming~5 mins

Output using fmt.Println in Go - Cheat Sheet & Quick Revision

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Recall & Review
beginner
What does fmt.Println do in Go?
It prints the given values to the console followed by a new line, making output easy to read.
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beginner
How do you print multiple values with fmt.Println?
You separate values by commas inside fmt.Println, and it prints them with spaces in between.
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beginner
What happens if you use fmt.Println without any arguments?
It prints just a new line, moving the cursor to the next line in the console.
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beginner
Write a simple Go code snippet using fmt.Println to print "Hello, friend!"
package main

import "fmt"

func main() {
    fmt.Println("Hello, friend!")
}
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beginner
Why is fmt.Println preferred for quick output in Go programs?
Because it automatically adds spaces between values and a new line at the end, making output formatting simple.
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What does fmt.Println add automatically after printing the values?
ANo extra characters
BA new line
CA tab space
DA comma
How do you print the values 5 and 10 separated by a space using fmt.Println?
Afmt.Println(5, 10)
Bfmt.Println("5 10")
Cfmt.Println(5 + 10)
Dfmt.Println(5.10)
Which package must you import to use fmt.Println?
Afmt
Bio
Cos
Dprint
What will fmt.Println() print if called with no arguments?
AA zero
BNothing
CAn error
DJust a new line
Which of these is a correct way to print "Go is fun" using fmt.Println?
Afmt.Println(Go is fun)
Bfmt.Println('Go is fun')
Cfmt.Println("Go is fun")
Dfmt.Println(Go + is + fun)
Explain how fmt.Println works and why it is useful for output in Go.
Think about what happens when you print multiple things and how the output looks.
You got /4 concepts.
    Write a short Go program that prints your name using fmt.Println.
    Remember the basic structure of a Go program and how to print text.
    You got /4 concepts.

      Practice

      (1/5)
      1. What does the fmt.Println function do in Go?
      easy
      A. Creates a new package
      B. Reads input from the user
      C. Declares a new variable
      D. Prints text or values to the screen with a new line

      Solution

      1. Step 1: Understand the purpose of fmt.Println

        The function fmt.Println is used to display output on the screen, automatically adding a new line after the output.
      2. Step 2: Differentiate from other functions

        It does not read input, declare variables, or create packages; it only prints output.
      3. Final Answer:

        Prints text or values to the screen with a new line -> Option D
      4. Quick Check:

        fmt.Println prints output with newline [OK]
      Hint: Remember: println means print with a new line [OK]
      Common Mistakes:
      • Confusing fmt.Println with input functions
      • Thinking it declares variables
      • Assuming it creates packages
      2. Which of the following is the correct way to print "Hello, Go!" using fmt.Println?
      easy
      A. fmt.Println("Hello, Go!")
      B. fmt.Println('Hello, Go!')
      C. fmt.Println(Hello, Go!)
      D. fmt.Println(Hello Go)

      Solution

      1. Step 1: Check string syntax in Go

        Strings must be enclosed in double quotes " ". Single quotes ' ' are for single characters.
      2. Step 2: Validate the options

        fmt.Println("Hello, Go!") uses double quotes correctly. Options A, B, and C either use single quotes or no quotes, which causes errors.
      3. Final Answer:

        fmt.Println("Hello, Go!") -> Option A
      4. Quick Check:

        Strings need double quotes in fmt.Println [OK]
      Hint: Use double quotes for strings in fmt.Println [OK]
      Common Mistakes:
      • Using single quotes for strings
      • Omitting quotes around text
      • Forgetting commas inside print
      3. What will be the output of this Go code?
      package main
      import "fmt"
      func main() {
          fmt.Println("Go", "is", "fun")
      }
      medium
      A. Go is fun
      B. Goisfun
      C. "Go is fun"
      D. Go, is, fun

      Solution

      1. Step 1: Understand fmt.Println with multiple arguments

        When multiple values are separated by commas, fmt.Println prints them separated by spaces automatically.
      2. Step 2: Analyze the output

        The output will be the words separated by spaces: Go is fun, followed by a new line.
      3. Final Answer:

        Go is fun -> Option A
      4. Quick Check:

        fmt.Println adds spaces between arguments [OK]
      Hint: Multiple arguments print with spaces automatically [OK]
      Common Mistakes:
      • Expecting no spaces between words
      • Thinking commas print literally
      • Confusing output with quotes
      4. Find the error in this Go code snippet:
      package main
      import "fmt"
      func main() {
          fmt.Println("Hello" + "World")
      }
      medium
      A. Syntax error due to missing comma
      B. Runtime error because + can't join strings
      C. No error, it prints HelloWorld
      D. fmt.Println requires parentheses

      Solution

      1. Step 1: Check string concatenation in Go

        Using + between strings concatenates them without spaces.
      2. Step 2: Verify fmt.Println usage

        fmt.Println can print the concatenated string without error.
      3. Final Answer:

        No error, it prints HelloWorld -> Option C
      4. Quick Check:

        String + concatenates; fmt.Println prints result [OK]
      Hint: String + joins text; no comma needed inside fmt.Println [OK]
      Common Mistakes:
      • Thinking + causes syntax error in print
      • Expecting space between Hello and World
      • Confusing + with comma separator
      5. You want to print the numbers 1, 2, and 3 on the same line separated by spaces using fmt.Println. Which code snippet achieves this correctly?
      hard
      A. fmt.Println(1 2 3)
      B. fmt.Println("1", "2", "3")
      C. fmt.Println("1" "2" "3")
      D. fmt.Println(1 + 2 + 3)

      Solution

      1. Step 1: Understand printing multiple values

        Using commas in fmt.Println prints each argument separated by spaces automatically.
      2. Step 2: Analyze each option

        fmt.Println(1 2 3) causes syntax error (missing commas or operators).
        fmt.Println("1" "2" "3") concatenates adjacent strings to "123" without spaces.
        fmt.Println("1", "2", "3") prints 1 2 3 with spaces.
        fmt.Println(1 + 2 + 3) prints 6.
      3. Step 3: Choose the best for printing numbers as strings separated by spaces

        fmt.Println("1", "2", "3") prints the numbers as strings separated by spaces, exactly as requested.
      4. Final Answer:

        fmt.Println("1", "2", "3") -> Option B
      5. Quick Check:

        Separate strings with commas to print spaced values [OK]
      Hint: Use commas to separate values for spaced output [OK]
      Common Mistakes:
      • Using + to join numbers (adds them instead)
      • Printing a single string instead of separate values
      • Confusing string and integer printing
      Recommended

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      10 questions~5 mineasy hard