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Goprogramming~5 mins

Return inside loops in Go

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Introduction

Using return inside loops lets you stop the function and give back a result as soon as you find what you need.

When searching for a specific item in a list and you want to stop once found.
When checking conditions in a loop and want to exit early if a condition is met.
When processing data and you want to return a result immediately without finishing the whole loop.
Syntax
Go
for condition {
    if someCheck {
        return value
    }
}

The return statement immediately ends the function, even if inside a loop.

Code after return inside the loop will not run once return is executed.

Examples
This function returns the first even number it finds in the list. It stops looping once it finds one.
Go
func findFirstEven(numbers []int) int {
    for _, num := range numbers {
        if num%2 == 0 {
            return num
        }
    }
    return -1 // if no even number found
}
This function checks if there is any negative number. It returns true immediately when it finds one.
Go
func containsNegative(nums []int) bool {
    for _, n := range nums {
        if n < 0 {
            return true
        }
    }
    return false
}
Sample Program

This program looks for the first positive number in the list. It returns and prints it as soon as it finds it.

Go
package main

import "fmt"

func findFirstPositive(nums []int) int {
    for _, n := range nums {
        if n > 0 {
            return n
        }
    }
    return 0
}

func main() {
    numbers := []int{-3, -2, 0, 4, 5}
    result := findFirstPositive(numbers)
    fmt.Println("First positive number:", result)
}
OutputSuccess
Important Notes

Remember, return ends the whole function, not just the loop.

If you want to skip to the next loop cycle without returning, use continue instead.

Summary

Use return inside loops to stop the function early when you find what you need.

This helps make your code faster by not doing extra work.

Be careful: return ends the whole function, not just the loop.

Practice

(1/5)
1.

What happens when you use return inside a for loop in Go?

easy
A. The function stops immediately and returns the value.
B. Only the current loop iteration stops, and the loop continues.
C. The loop skips the current iteration and moves to the next.
D. The loop runs forever without stopping.

Solution

  1. Step 1: Understand the role of return in functions

    In Go, return immediately ends the function and sends back a value.
  2. Step 2: Effect of return inside a loop

    When return is inside a loop, it stops the whole function, not just the loop.
  3. Final Answer:

    The function stops immediately and returns the value. -> Option A
  4. Quick Check:

    Return ends function, not just loop [OK]
Hint: Return inside loop ends function immediately [OK]
Common Mistakes:
  • Thinking return only stops the loop
  • Confusing return with break
  • Assuming loop continues after return
2.

Which of the following Go code snippets correctly uses return inside a for loop to return the first even number from a slice?

func firstEven(nums []int) int {
    for _, n := range nums {
        if n % 2 == 0 {
            // What goes here?
        }
    }
    return -1
}
easy
A. return n
B. break
C. continue
D. return nums

Solution

  1. Step 1: Identify what to return inside the loop

    The function should return the first even number found, which is n.
  2. Step 2: Use return to stop function and send back the number

    Using return n immediately ends the function and returns the even number.
  3. Final Answer:

    return n -> Option A
  4. Quick Check:

    Return value inside loop to stop function [OK]
Hint: Use return with value to exit function inside loop [OK]
Common Mistakes:
  • Using break instead of return
  • Using continue which skips iteration
  • Returning the whole slice instead of a number
3.

What is the output of this Go program?

package main
import "fmt"
func findFirstPositive(nums []int) int {
    for _, n := range nums {
        if n > 0 {
            return n
        }
    }
    return 0
}
func main() {
    fmt.Println(findFirstPositive([]int{-3, -2, 0, 5, 10}))
}
medium
A. 10
B. -3
C. 0
D. 5

Solution

  1. Step 1: Trace the loop over the slice

    The loop checks each number: -3 (not >0), -2 (not >0), 0 (not >0), 5 (>0).
  2. Step 2: Return the first positive number found

    When it reaches 5, it returns 5 immediately, ending the function.
  3. Final Answer:

    5 -> Option D
  4. Quick Check:

    Return stops at first positive number 5 [OK]
Hint: Return inside loop returns first matching value [OK]
Common Mistakes:
  • Assuming loop continues after return
  • Returning 0 instead of first positive
  • Confusing index with value
4.

Find the error in this Go function that tries to return the first negative number from a slice:

func firstNegative(nums []int) int {
    for _, n := range nums {
        if n < 0 {
            break
        }
    }
    return 0
}
medium
A. Returning 0 instead of -1 when no negative found
B. Missing else statement after if
C. Using break instead of return inside the loop
D. Loop variable should be index, not value

Solution

  1. Step 1: Understand break vs return inside loop

    Using break only stops the loop, but the function continues and returns 0.
  2. Step 2: Correct usage is return to stop function and return value

    To return the first negative number, use return n inside the if block.
  3. Final Answer:

    Using break instead of return inside the loop -> Option C
  4. Quick Check:

    Return ends function; break only stops loop [OK]
Hint: Use return, not break, to exit function inside loop [OK]
Common Mistakes:
  • Using break instead of return
  • Expecting break to return value
  • Not returning value inside loop
5.

You want to write a Go function that returns the first string in a slice that starts with the letter 'A'. If none is found, return "Not found". Which code correctly uses return inside the loop?

func findA(words []string) string {
    for _, w := range words {
        if len(w) > 0 && w[0] == 'A' {
            // What goes here?
        }
    }
    return "Not found"
}
hard
A. break
B. return w
C. continue
D. return words[0]

Solution

  1. Step 1: Identify the correct return value inside the loop

    The function should return the first word starting with 'A', which is w.
  2. Step 2: Use return to immediately end the function and return the word

    Using return w stops the function and returns the found word.
  3. Final Answer:

    return w -> Option B
  4. Quick Check:

    Return found word inside loop to stop function [OK]
Hint: Return matching item inside loop to stop function early [OK]
Common Mistakes:
  • Using break which only stops loop
  • Using continue which skips iteration
  • Returning wrong element like words[0]
Recommended

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