Output using fmt.Println in Go - Practice Problems & Coding Challenges

Challenge - 5 Problems

❓ Predict Output

intermediate

Output of fmt.Println with multiple arguments

What is the output of this Go code snippet?

Go

package main
import "fmt"
func main() {
    fmt.Println("Hello", "World", 2024)
}

A HelloWorld2024

B Hello World 2024

C "Hello World 2024"

D Hello, World, 2024

💡 Hint

fmt.Println separates arguments with spaces by default.

fmt.Println prints each argument separated by a space and adds a newline at the end.

❓ Predict Output

intermediate

Output of fmt.Println with newline characters

What will this Go program print?

Go

package main
import "fmt"
func main() {
    fmt.Println("Line1\nLine2")
}

A

Line1
Line2

B Line1\nLine2

C Line1 Line2

D Line1\n Line2

💡 Hint

The string contains an escape sequence for newline.

The \n inside the string creates a new line when printed by fmt.Println.

❓ Predict Output

advanced

Output of fmt.Println with slice argument

What is the output of this Go code?

Go

package main
import "fmt"
func main() {
    nums := []int{1, 2, 3}
    fmt.Println(nums)
}

A 1,2,3

B 1 2 3

C [1 2 3]

D []int{1, 2, 3}

💡 Hint

fmt.Println prints slices with brackets and spaces.

fmt.Println prints slices in a format with square brackets and spaces between elements.

❓ Predict Output

advanced

Output of fmt.Println with pointer variable

What will this Go program print?

Go

package main
import "fmt"
func main() {
    x := 10
    p := &x
    fmt.Println(p)
}

A &10

B 10

C p

D 0xc0000140b0

💡 Hint

Printing a pointer shows its memory address.

fmt.Println prints the memory address stored in the pointer variable.

❓ Predict Output

expert

Output of fmt.Println with interface and type assertion

What is the output of this Go code?

Go

package main
import "fmt"
func main() {
    var i interface{} = 42
    fmt.Println(i)
    if v, ok := i.(int); ok {
        fmt.Println(v * 2)
    }
}

A

42
84

B

42
42

C

interface value
84

D

42
<nil>

💡 Hint

Type assertion extracts the int value from interface{}.

The interface holds 42, printing it shows 42, then doubling prints 84.

Practice

1. What does the fmt.Println function do in Go?

easy

A. Creates a new package

B. Reads input from the user

C. Declares a new variable

D. Prints text or values to the screen with a new line

Solution

1. Step 1: Understand the purpose of fmt.Println

   The function fmt.Println is used to display output on the screen, automatically adding a new line after the output.

2. Step 2: Differentiate from other functions

   It does not read input, declare variables, or create packages; it only prints output.

3. Final Answer:

   Prints text or values to the screen with a new line -> Option D

4. Quick Check:

   fmt.Println prints output with newline [OK]

Hint: Remember: println means print with a new line [OK]

Common Mistakes:

• Confusing fmt.Println with input functions
• Thinking it declares variables
• Assuming it creates packages

2. Which of the following is the correct way to print "Hello, Go!" using fmt.Println?

easy

A. fmt.Println("Hello, Go!")

B. fmt.Println('Hello, Go!')

C. fmt.Println(Hello, Go!)

D. fmt.Println(Hello Go)

Solution

1. Step 1: Check string syntax in Go

   Strings must be enclosed in double quotes " ". Single quotes ' ' are for single characters.

2. Step 2: Validate the options

   fmt.Println("Hello, Go!") uses double quotes correctly. Options A, B, and C either use single quotes or no quotes, which causes errors.

3. Final Answer:

   fmt.Println("Hello, Go!") -> Option A

4. Quick Check:

   Strings need double quotes in fmt.Println [OK]

Hint: Use double quotes for strings in fmt.Println [OK]

Common Mistakes:

• Using single quotes for strings
• Omitting quotes around text
• Forgetting commas inside print

3. What will be the output of this Go code?

package main
import "fmt"
func main() {
    fmt.Println("Go", "is", "fun")
}

medium

A. Go is fun

B. Goisfun

C. "Go is fun"

D. Go, is, fun

Solution

1. Step 1: Understand fmt.Println with multiple arguments

   When multiple values are separated by commas, fmt.Println prints them separated by spaces automatically.

2. Step 2: Analyze the output

   The output will be the words separated by spaces: Go is fun, followed by a new line.

3. Final Answer:

   Go is fun -> Option A

4. Quick Check:

   fmt.Println adds spaces between arguments [OK]

Hint: Multiple arguments print with spaces automatically [OK]

Common Mistakes:

• Expecting no spaces between words
• Thinking commas print literally
• Confusing output with quotes

4. Find the error in this Go code snippet:

package main
import "fmt"
func main() {
    fmt.Println("Hello" + "World")
}

medium

A. Syntax error due to missing comma

B. Runtime error because + can't join strings

C. No error, it prints HelloWorld

D. fmt.Println requires parentheses

Solution

1. Step 1: Check string concatenation in Go

   Using + between strings concatenates them without spaces.

2. Step 2: Verify fmt.Println usage

   fmt.Println can print the concatenated string without error.

3. Final Answer:

   No error, it prints HelloWorld -> Option C

4. Quick Check:

   String + concatenates; fmt.Println prints result [OK]

Hint: String + joins text; no comma needed inside fmt.Println [OK]

Common Mistakes:

• Thinking + causes syntax error in print
• Expecting space between Hello and World
• Confusing + with comma separator

5. You want to print the numbers 1, 2, and 3 on the same line separated by spaces using fmt.Println. Which code snippet achieves this correctly?

hard

A. fmt.Println(1 2 3)

B. fmt.Println("1", "2", "3")

C. fmt.Println("1" "2" "3")

D. fmt.Println(1 + 2 + 3)

Solution

1. Step 1: Understand printing multiple values

   Using commas in fmt.Println prints each argument separated by spaces automatically.

2. Step 2: Analyze each option

   fmt.Println(1 2 3) causes syntax error (missing commas or operators).
   fmt.Println("1" "2" "3") concatenates adjacent strings to "123" without spaces.
   fmt.Println("1", "2", "3") prints 1 2 3 with spaces.
   fmt.Println(1 + 2 + 3) prints 6.

3. Step 3: Choose the best for printing numbers as strings separated by spaces

   fmt.Println("1", "2", "3") prints the numbers as strings separated by spaces, exactly as requested.

4. Final Answer:

   fmt.Println("1", "2", "3") -> Option B

5. Quick Check:

   Separate strings with commas to print spaced values [OK]

Hint: Use commas to separate values for spaced output [OK]

Common Mistakes:

• Using + to join numbers (adds them instead)
• Printing a single string instead of separate values
• Confusing string and integer printing