Else–if ladder in Go - Interactive Code Practice

Practice - 5 Tasks

1fill in blank

easy

Complete the code to print "Positive" if the number is greater than zero.

Go

if num [1] 0 {
    fmt.Println("Positive")
}

Drag options to blanks, or click blank then click option'

A!=

B>

C==

D<

Attempts:

3 left

💡 Hint

Common Mistakes

Using '<' instead of '>' will check for negative numbers.

Using '==' checks for equality, not greater than.

The condition num > 0 checks if the number is positive.

2fill in blank

medium

Complete the else-if condition to check if the number is zero.

Go

if num > 0 {
    fmt.Println("Positive")
} else if num [1] 0 {
    fmt.Println("Zero")
}

Drag options to blanks, or click blank then click option'

A==

B<

C!=

D>

Attempts:

3 left

💡 Hint

Common Mistakes

Using '!=' checks for not equal, which is incorrect here.

Using '<' or '>' checks for less or greater, not equality.

The condition num == 0 checks if the number is exactly zero.

3fill in blank

hard

Fix the error in the else-if condition to check if the number is negative.

Go

if num > 0 {
    fmt.Println("Positive")
} else if num [1] 0 {
    fmt.Println("Negative")
}

Drag options to blanks, or click blank then click option'

A==

B>

C!=

D<

Attempts:

3 left

💡 Hint

Common Mistakes

Using '>' checks for positive numbers, not negative.

Using '==' checks for equality, not less than.

The condition num < 0 correctly checks if the number is negative.

4fill in blank

hard

Fill both blanks to complete the else-if ladder that prints "Positive", "Zero", or "Negative".

Go

if num [1] 0 {
    fmt.Println("Positive")
} else if num [2] 0 {
    fmt.Println("Zero")
} else {
    fmt.Println("Negative")
}

Drag options to blanks, or click blank then click option'

A>

B<

C==

D!=

Attempts:

3 left

💡 Hint

Common Mistakes

Mixing up '<' and '>' in conditions.

Using '!=' instead of '==' for zero check.

The first condition checks if num > 0 (positive), the second checks if num == 0 (zero), else it's negative.

5fill in blank

hard

Fill all three blanks to complete the else-if ladder that prints the correct message based on num.

Go

if num [1] 0 {
    fmt.Println("Positive")
} else if num [2] 0 {
    fmt.Println("Zero")
} else if num [3] 0 {
    fmt.Println("Negative")
}

Drag options to blanks, or click blank then click option'

A>

B==

C<

D!=

Attempts:

3 left

💡 Hint

Common Mistakes

Using '!=' instead of '==' for zero.

Swapping '<' and '>' in conditions.

The conditions check if num > 0 (positive), num == 0 (zero), and num < 0 (negative).