Else–if ladder in Go - Practice Problems & Coding Challenges

Challenge - 5 Problems

❓ Predict Output

intermediate

Output of else-if ladder with multiple conditions

What is the output of the following Go program?

Go

package main
import "fmt"
func main() {
    x := 15
    if x < 10 {
        fmt.Println("Less than 10")
    } else if x < 20 {
        fmt.Println("Between 10 and 19")
    } else if x < 30 {
        fmt.Println("Between 20 and 29")
    } else {
        fmt.Println("30 or more")
    }
}

A Less than 10

B Between 20 and 29

C 30 or more

D Between 10 and 19

💡 Hint

Check which condition matches the value of x first.

The variable x is 15, which is not less than 10, but it is less than 20. So the second condition is true and prints "Between 10 and 19".

❓ Predict Output

intermediate

Output when all else-if conditions fail

What will this Go program print?

Go

package main
import "fmt"
func main() {
    score := 85
    if score > 90 {
        fmt.Println("Grade A")
    } else if score > 80 {
        fmt.Println("Grade B")
    } else if score > 70 {
        fmt.Println("Grade C")
    } else {
        fmt.Println("Grade F")
    }
}

A Grade B

B Grade A

C Grade C

D Grade F

💡 Hint

Check the first condition that is true for score 85.

85 is not greater than 90, but it is greater than 80, so it prints "Grade B".

🔧 Debug

advanced

Identify the error in else-if ladder syntax

Which option contains a syntax error in the else-if ladder?

Go

package main
import "fmt"
func main() {
    n := 5
    if n > 10 {
        fmt.Println("Greater than 10")
    } else if n > 5 {
        fmt.Println("Greater than 5")
    } else if n > 0 {
        fmt.Println("Greater than 0")
    } else {
        fmt.Println("Zero or negative")
    }
}

A

if n > 10 {
    fmt.Println("Greater than 10")
} else if n > 5 {
    fmt.Println("Greater than 5")
} else if n > 0 {
    fmt.Println("Greater than 0")
} else {
    fmt.Println("Zero or negative")
}

B

if n > 10 {
    fmt.Println("Greater than 10")
} else if n > 5 
    fmt.Println("Greater than 5")
} else if n > 0 {
    fmt.Println("Greater than 0")
} else {
    fmt.Println("Zero or negative")
}

C

}
)"evitagen ro oreZ"(nltnirP.tmf    
{ esle }
)"0 naht retaerG"(nltnirP.tmf    
{ 0 > n fi esle }
)"5 naht retaerG"(nltnirP.tmf    
{ 5 > n fi esle }
)"01 naht retaerG"(nltnirP.tmf    
{ 01 > n fi

D

f n > 10 {
    fmt.Println("Greater than 10")
} else if n > 5 {
    fmt.Println("Greater than 5")
} else if n > 0 {
    fmt.Println("Greater than 0")
} else {
    fmt.Println("Zero or negative")
}

💡 Hint

Check the placement of braces {} in else-if blocks.

Option B is missing the opening brace '{' after else if n > 5, causing a syntax error.

🧠 Conceptual

advanced

Understanding else-if ladder execution flow

Given the following Go code, what will be the value of variable result after execution?

Go

package main
func main() {
    var result string
    x := 7
    if x > 10 {
        result = "A"
    } else if x > 5 {
        result = "B"
    } else if x > 0 {
        result = "C"
    } else {
        result = "D"
    }
}

A "C"

B "D"

C "B"

D "A"

💡 Hint

Check which condition matches x = 7 first.

x is 7, which is not greater than 10 but is greater than 5, so result is set to "B".

🚀 Application

expert

Determine output with nested else-if ladder

What will this Go program print when run?

Go

package main
import "fmt"
func main() {
    a := 3
    b := 7
    if a > b {
        fmt.Println("a is greater")
    } else if a == b {
        fmt.Println("a equals b")
    } else {
        if b > 10 {
            fmt.Println("b is large")
        } else if b > 5 {
            fmt.Println("b is medium")
        } else {
            fmt.Println("b is small")
        }
    }
}

A b is medium

B a is greater

C b is large

D a equals b

💡 Hint

Check the outer else block and then the inner else-if ladder for b.

a is 3 and b is 7, so a > b is false and a == b is false. The else block runs. Inside it, b is 7 which is greater than 5 but not greater than 10, so it prints "b is medium".