LAMBDA for custom functions in Excel - Interactive Code Practice

Practice - 5 Tasks

1fill in blank

easy

Complete the formula to create a simple LAMBDA that adds 5 to a number.

Excel

=LAMBDA(x, x [1] 5)

Drag options to blanks, or click blank then click option'

A+

B-

C*

D/

Attempts:

3 left

💡 Hint

Common Mistakes

Using minus (-) instead of plus (+)

Using multiplication (*) or division (/)

The plus sign (+) adds 5 to the input x.

2fill in blank

medium

Complete the formula to create a LAMBDA that multiplies two numbers a and b.

Excel

=LAMBDA(a, b, a [1] b)

Drag options to blanks, or click blank then click option'

A*

B+

C-

D/

Attempts:

3 left

💡 Hint

Common Mistakes

Using plus (+) or minus (-) instead of multiplication

Using division (/) by mistake

The asterisk (*) multiplies a and b in Excel formulas.

3fill in blank

hard

Fix the error in the LAMBDA formula that should subtract b from a.

Excel

=LAMBDA(a, b, a [1] b)

Drag options to blanks, or click blank then click option'

A/

B+

C*

D-

Attempts:

3 left

💡 Hint

Common Mistakes

Using plus (+) instead of minus (-)

Using multiplication (*) or division (/)

The minus sign (-) subtracts b from a.

4fill in blank

hard

Fill the blank to create a LAMBDA that returns TRUE if x is greater than y.

Excel

=LAMBDA(x, y, x [1] y)

Drag options to blanks, or click blank then click option'

A=

B<

C>

D<>

Attempts:

3 left

💡 Hint

Common Mistakes

Using less than (<) or equals (=) instead of greater than (>)

Using not equal (<>) by mistake

The greater than symbol (>) checks if x is greater than y.

5fill in blank

hard

Fill the blank to create a LAMBDA that returns the maximum of two numbers a and b.

Excel

=LAMBDA(a, b, IF(a [1] b, a, b))

Drag options to blanks, or click blank then click option'

A=

B>

C<

D<>

Attempts:

3 left

💡 Hint

Common Mistakes

Using less than (<) instead of greater than (>)

Using equals (=) or not equal (<>) incorrectly

The IF function checks if a is greater than b using >. If true, it returns a; otherwise, b.

Practice

1. What does the LAMBDA function in Excel allow you to do?

easy

A. Convert text to numbers

B. Create your own custom formulas with parameters

C. Automatically sort data in a column

D. Create charts from data ranges

Solution

1. Step 1: Understand the purpose of LAMBDA

   LAMBDA lets you create custom formulas that can take inputs and return results, like your own mini-functions.

2. Step 2: Compare with other options

   Sorting, converting text, and creating charts are done by other Excel features, not LAMBDA.

3. Final Answer:

   Create your own custom formulas with parameters -> Option B

4. Quick Check:

   LAMBDA = custom formulas [OK]

Hint: LAMBDA = your own formula with inputs [OK]

Common Mistakes:

• Thinking LAMBDA sorts or formats data
• Confusing LAMBDA with built-in functions like SORT
• Assuming LAMBDA creates charts

2. Which of these is the correct syntax to define a LAMBDA function that adds two numbers x and y?

easy

A. =LAMBDA(x, y, x + y)

B. =LAMBDA(x + y)

C. =LAMBDA(x, y; x + y)

D. =LAMBDA(x, y, x - y)

Solution

1. Step 1: Check LAMBDA syntax

   LAMBDA syntax is =LAMBDA(parameter1, parameter2, ..., calculation). So =LAMBDA(x, y, x + y) is correct.

2. Step 2: Identify errors in other options

   =LAMBDA(x + y) misses parameters, C uses wrong separator (;), D subtracts instead of adding.

3. Final Answer:

   =LAMBDA(x, y, x + y) -> Option A

4. Quick Check:

   Correct LAMBDA syntax uses commas and parameters [OK]

Hint: LAMBDA needs parameters, commas, and a formula [OK]

Common Mistakes:

• Using semicolons instead of commas
• Omitting parameters
• Mixing up addition and subtraction

3. Given the formula =LAMBDA(x, y, x * y)(3, 4), what is the result shown in the cell?

medium

A. 7

B. 34

C. 12

D. Error

Solution

1. Step 1: Understand the LAMBDA call

   The LAMBDA takes two inputs x and y, then returns x * y. Here, x=3 and y=4.

2. Step 2: Calculate the multiplication

   3 multiplied by 4 equals 12.

3. Final Answer:

   12 -> Option C

4. Quick Check:

   3 * 4 = 12 [OK]

Hint: Multiply inputs inside LAMBDA to get result [OK]

Common Mistakes:

• Adding instead of multiplying
• Concatenating numbers as text
• Expecting an error from correct syntax

4. What is wrong with this LAMBDA formula? =LAMBDA(x, y, x + y(2, 3))

medium

A. Incorrect function call syntax inside LAMBDA

B. Missing closing parenthesis

C. Parameters x and y are not defined

D. LAMBDA cannot add numbers

Solution

1. Step 1: Analyze the formula structure

   The formula tries to add x + y(2, 3), but y is a parameter, not a function, so y(2, 3) is invalid.

2. Step 2: Identify the syntax error

   You cannot call parameters like functions inside LAMBDA. The correct call is outside the LAMBDA definition.

3. Final Answer:

   Incorrect function call syntax inside LAMBDA -> Option A

4. Quick Check:

   Parameters are values, not callable functions [OK]

Hint: Don't call parameters like functions inside LAMBDA [OK]

Common Mistakes:

• Trying to call parameters as functions
• Confusing LAMBDA parameters with named functions
• Ignoring parentheses placement

5. You want to create a reusable LAMBDA function named DOUBLE that doubles any number input. Which steps correctly create and use this function?

hard

A. Write =DOUBLE(5) without defining DOUBLE anywhere.

B. Write =LAMBDA(x, x*2)(5) directly in a cell without naming it.

C. Define DOUBLE as =LAMBDA(x, x+2) in Name Manager, then use =DOUBLE(5).

D. Define DOUBLE as =LAMBDA(x, x*2) in Name Manager, then use =DOUBLE(5) in a cell.

Solution

1. Step 1: Define the LAMBDA function correctly

   In Name Manager, create a name DOUBLE with formula =LAMBDA(x, x*2) to double input x.

2. Step 2: Use the named function in cells

   After defining, use =DOUBLE(5) in any cell to get 10.

3. Final Answer:

   Define DOUBLE as LAMBDA(x, x*2) and call DOUBLE(5) -> Option D

4. Quick Check:

   Named LAMBDA + call = reusable function [OK]

Hint: Name LAMBDA in Name Manager, then call by name [OK]

Common Mistakes:

• Using wrong formula (x+2 instead of x*2)
• Calling named function without defining it
• Trying to use LAMBDA without naming for reuse