What if you could see exactly which parts of a tree hide others from below without guessing?
Why Bottom View of Binary Tree in DSA Python?
Imagine you have a tall tree in your backyard and you want to see which branches are visible if you look at it from the bottom. You try to write down all the branches you see from below by guessing their positions.
Manually figuring out which branches are visible from the bottom is confusing and slow. You might miss some branches or write down the wrong ones because you can't easily tell which branch hides another from your viewpoint.
The bottom view of a binary tree helps you find exactly which nodes (branches) are visible when looking from the bottom. It uses a smart way to track positions and heights of nodes, so you get the correct visible nodes without guessing.
def bottom_view_manual(tree): # Guess visible nodes by checking levels visible = [] max_level = max(node.level for node in tree) for node in tree: if node.level == max_level: visible.append(node.value) return visible
def bottom_view(tree): hd_node_map = {} def traverse(node, hd, level): if node: if hd not in hd_node_map or level >= hd_node_map[hd][1]: hd_node_map[hd] = (node.value, level) traverse(node.left, hd - 1, level + 1) traverse(node.right, hd + 1, level + 1) traverse(tree.root, 0, 0) return [hd_node_map[hd][0] for hd in sorted(hd_node_map)]
This concept lets you clearly see the exact nodes visible from the bottom of a tree, helping in visualization and solving problems related to tree views.
In city planning, when designing underground pipelines beneath roads (tree branches), engineers need to know which pipes are visible from below to avoid clashes. Bottom view helps visualize this clearly.
Manual guessing of visible nodes is confusing and error-prone.
Bottom view uses horizontal distance and level to find visible nodes from below.
This helps in clear visualization and solving tree-related problems.
Practice
bottom view of a binary tree represent?Solution
Step 1: Understand the bottom view concept
The bottom view shows nodes visible when looking at the tree from below, meaning the lowest nodes at each horizontal distance.Step 2: Compare with other views
Top view shows nodes from above, left and right views show nodes from sides, so bottom view is unique for bottom perspective.Final Answer:
Nodes visible when the tree is viewed from the bottom -> Option DQuick Check:
Bottom view = visible nodes from below [OK]
- Confusing bottom view with top view
- Thinking bottom view shows all leaf nodes
- Mixing bottom view with side views
Solution
Step 1: Identify the need for horizontal distance mapping
We need to map horizontal distances to nodes to know which node is visible at each position.Step 2: Choose the data structure
A hash map (dictionary) stores horizontal distance as key and node value as value, updating with the bottom-most node.Final Answer:
Hash Map (Dictionary) -> Option AQuick Check:
Use dictionary to map horizontal distance to node [OK]
- Using stack which is LIFO and not suitable here
- Using queue alone without mapping distances
- Using linked list which is inefficient for key-value mapping
20
/ \
8 22
/ \ \
5 3 25
/ \
10 14
Solution
Step 1: Assign horizontal distances and find bottom nodes
Horizontal distances: 20(0), 8(-1), 22(1), 5(-2), 3(0), 25(2), 10(-1), 14(1). Bottom nodes at each distance: -2:5, -1:10, 0:3, 1:14, 2:25.Step 2: List bottom view nodes in order of horizontal distance
From left to right: 5, 10, 3, 14, 25.Final Answer:
[5, 10, 3, 14, 25] -> Option AQuick Check:
Bottom view nodes by horizontal distance = [5,10,3,14,25] [OK]
- Not updating bottom node when a lower node appears
- Mixing horizontal distances order
- Including nodes not visible from bottom
def bottom_view(root):
if not root:
return []
queue = [(root, 0)]
hd_node = {}
while queue:
node, hd = queue.pop()
hd_node[hd] = node.val
if node.left:
queue.append((node.left, hd - 1))
if node.right:
queue.append((node.right, hd + 1))
return [hd_node[hd] for hd in sorted(hd_node)]
What is the main error in this code?Solution
Step 1: Analyze queue usage and traversal order
The code uses queue.pop() which removes last element (LIFO), making it behave like a stack, causing depth-first traversal instead of breadth-first.Step 2: Understand impact on bottom view calculation
Breadth-first traversal is needed to process nodes level by level to correctly update bottom nodes. Using pop() breaks this order.Final Answer:
Using pop() removes last element, causing wrong traversal order -> Option BQuick Check:
Use pop(0) or deque.popleft() for BFS [OK]
- Using pop() instead of pop(0) for queue
- Ignoring empty root check
- Incorrect horizontal distance updates
Solution
Step 1: Understand the need to track depth
To show the bottom-most node at each horizontal distance, we must know which node is deepest (greatest depth).Step 2: Modify dictionary to store value and depth
Store a tuple (node value, depth) for each horizontal distance. Update only if new node's depth is greater than stored depth.Final Answer:
Store both node value and depth in the dictionary, update only if new node depth is greater -> Option CQuick Check:
Track depth to update bottom view nodes correctly [OK]
- Ignoring depth and overwriting nodes incorrectly
- Storing all nodes without filtering by depth
- Picking first or last node without depth check
Ready to prove it?
Pass the test and this pattern moves unknown
