The bottom view of a binary tree is the set of nodes visible when the tree is seen from the bottom. It includes the lowest nodes at each horizontal distance from the root.
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beginner
How do we assign horizontal distances to nodes in a binary tree for bottom view?
We assign 0 to the root. For the left child, horizontal distance is parent's distance minus 1. For the right child, it is parent's distance plus 1.
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intermediate
Which data structure is commonly used to track nodes and their horizontal distances during bottom view traversal?
A queue is used for level order traversal, and a dictionary (or map) stores the latest node at each horizontal distance.
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intermediate
Why does the bottom view update the node at a horizontal distance when a new node is found at the same distance?
Because the bottom view shows the lowest node at each horizontal distance, nodes found later in level order traversal (lower levels) replace earlier ones.
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beginner
What is the time complexity of finding the bottom view of a binary tree?
The time complexity is O(n), where n is the number of nodes, because each node is visited once during level order traversal.
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What horizontal distance is assigned to the root node in bottom view calculation?
A0
B1
C-1
DDepends on tree height
✗ Incorrect
The root node is always assigned horizontal distance 0.
Which traversal method is best suited for computing the bottom view of a binary tree?
APreorder traversal
BInorder traversal
CPostorder traversal
DLevel order traversal
✗ Incorrect
Level order traversal visits nodes level by level, allowing us to update bottom view nodes correctly.
In bottom view, if two nodes share the same horizontal distance, which node is visible?
AThe node at the higher level
BThe node at the lower level
CThe leftmost node
DThe rightmost node
✗ Incorrect
The bottom view shows the lowest node at each horizontal distance.
What data structure helps keep track of the latest node at each horizontal distance?
AStack
BQueue
CDictionary or Map
DLinked List
✗ Incorrect
A dictionary or map stores the node for each horizontal distance.
What is the time complexity of the bottom view algorithm?
AO(n)
BO(n log n)
CO(log n)
DO(n^2)
✗ Incorrect
Each node is visited once, so the time complexity is O(n).
Explain how to find the bottom view of a binary tree step-by-step.
Think about horizontal distances and level order traversal.
You got /5 concepts.
Why does the bottom view of a binary tree show the lowest nodes at each horizontal distance?
Imagine looking up from the ground at the tree.
You got /4 concepts.
Practice
(1/5)
1. What does the bottom view of a binary tree represent?
easy
A. Nodes visible when the tree is viewed from the right side
B. Nodes visible when the tree is viewed from the top
C. Nodes visible when the tree is viewed from the left side
D. Nodes visible when the tree is viewed from the bottom
Solution
Step 1: Understand the bottom view concept
The bottom view shows nodes visible when looking at the tree from below, meaning the lowest nodes at each horizontal distance.
Step 2: Compare with other views
Top view shows nodes from above, left and right views show nodes from sides, so bottom view is unique for bottom perspective.
Final Answer:
Nodes visible when the tree is viewed from the bottom -> Option D
Quick Check:
Bottom view = visible nodes from below [OK]
Hint: Bottom view shows lowest nodes at each horizontal distance [OK]
Common Mistakes:
Confusing bottom view with top view
Thinking bottom view shows all leaf nodes
Mixing bottom view with side views
2. Which data structure is commonly used to track nodes and their horizontal distances when computing the bottom view of a binary tree?
easy
A. Hash Map (Dictionary)
B. Queue
C. Stack
D. Linked List
Solution
Step 1: Identify the need for horizontal distance mapping
We need to map horizontal distances to nodes to know which node is visible at each position.
Step 2: Choose the data structure
A hash map (dictionary) stores horizontal distance as key and node value as value, updating with the bottom-most node.
Final Answer:
Hash Map (Dictionary) -> Option A
Quick Check:
Use dictionary to map horizontal distance to node [OK]
Hint: Use dictionary to map horizontal distance to node [OK]
Common Mistakes:
Using stack which is LIFO and not suitable here
Using queue alone without mapping distances
Using linked list which is inefficient for key-value mapping
3. What is the bottom view output of the following binary tree?
20
/ \
8 22
/ \ \
5 3 25
/ \
10 14
medium
A. [5, 10, 3, 14, 25]
B. [5, 8, 10, 14, 25]
C. [5, 10, 3, 22, 25]
D. [8, 10, 3, 14, 22]
Solution
Step 1: Assign horizontal distances and find bottom nodes
Horizontal distances: 20(0), 8(-1), 22(1), 5(-2), 3(0), 25(2), 10(-1), 14(1). Bottom nodes at each distance: -2:5, -1:10, 0:3, 1:14, 2:25.
Step 2: List bottom view nodes in order of horizontal distance
From left to right: 5, 10, 3, 14, 25.
Final Answer:
[5, 10, 3, 14, 25] -> Option A
Quick Check:
Bottom view nodes by horizontal distance = [5,10,3,14,25] [OK]
Hint: Track horizontal distances and update bottom nodes [OK]
Common Mistakes:
Not updating bottom node when a lower node appears
Mixing horizontal distances order
Including nodes not visible from bottom
4. Consider this code snippet to compute bottom view of a binary tree:
def bottom_view(root):
if not root:
return []
queue = [(root, 0)]
hd_node = {}
while queue:
node, hd = queue.pop()
hd_node[hd] = node.val
if node.left:
queue.append((node.left, hd - 1))
if node.right:
queue.append((node.right, hd + 1))
return [hd_node[hd] for hd in sorted(hd_node)]
What is the main error in this code?
medium
A. Not checking if root is None
B. Using pop() removes last element, causing wrong traversal order
C. Not updating hd_node dictionary
D. Incorrect horizontal distance calculation
Solution
Step 1: Analyze queue usage and traversal order
The code uses queue.pop() which removes last element (LIFO), making it behave like a stack, causing depth-first traversal instead of breadth-first.
Step 2: Understand impact on bottom view calculation
Breadth-first traversal is needed to process nodes level by level to correctly update bottom nodes. Using pop() breaks this order.
Final Answer:
Using pop() removes last element, causing wrong traversal order -> Option B
Quick Check:
Use pop(0) or deque.popleft() for BFS [OK]
Hint: Use pop(0) for queue to maintain BFS order [OK]
Common Mistakes:
Using pop() instead of pop(0) for queue
Ignoring empty root check
Incorrect horizontal distance updates
5. You have a binary tree where multiple nodes share the same horizontal distance and depth. How should you modify the bottom view algorithm to always show the node with the greatest depth at each horizontal distance?
hard
A. Store nodes in a list for each horizontal distance and pick the smallest value
B. Store only the first node encountered at each horizontal distance
C. Store both node value and depth in the dictionary, update only if new node depth is greater
D. Ignore depth and update dictionary with last visited node
Solution
Step 1: Understand the need to track depth
To show the bottom-most node at each horizontal distance, we must know which node is deepest (greatest depth).
Step 2: Modify dictionary to store value and depth
Store a tuple (node value, depth) for each horizontal distance. Update only if new node's depth is greater than stored depth.
Final Answer:
Store both node value and depth in the dictionary, update only if new node depth is greater -> Option C
Quick Check:
Track depth to update bottom view nodes correctly [OK]
Hint: Track depth with node to update bottom view correctly [OK]
Common Mistakes:
Ignoring depth and overwriting nodes incorrectly
Storing all nodes without filtering by depth
Picking first or last node without depth check
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