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DSA Pythonprogramming~10 mins

Bottom View of Binary Tree in DSA Python - Interactive Practice

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Practice - 5 Tasks
Answer the questions below
1fill in blank
easy

Complete the code to create a new node in the binary tree.

DSA Python
class Node:
    def __init__(self, data):
        self.data = data
        self.left = None
        self.right = None

root = Node([1])
Drag options to blanks, or click blank then click option'
ANone
B10
C0
Droot
Attempts:
3 left
💡 Hint
Common Mistakes
Using None instead of a number for the node's data.
Using a variable name instead of a value.
2fill in blank
medium

Complete the code to assign the left child of the root node.

DSA Python
root.left = Node([1])
Drag options to blanks, or click blank then click option'
A20
B5
CNone
Droot
Attempts:
3 left
💡 Hint
Common Mistakes
Assigning None instead of a node.
Using the root variable instead of a value.
3fill in blank
hard

Fix the error in the function to print the bottom view of the binary tree.

DSA Python
def bottom_view(root):
    if root is None:
        return
    hd_node = dict()
    queue = [(root, 0)]
    while queue:
        node, hd = queue.pop(0)
        hd_node[[1]] = node.data
        if node.left:
            queue.append((node.left, hd - 1))
        if node.right:
            queue.append((node.right, hd + 1))
    for key in sorted(hd_node):
        print(hd_node[key], end=' ')
Drag options to blanks, or click blank then click option'
Ahd
Broot
Cnode
Dqueue
Attempts:
3 left
💡 Hint
Common Mistakes
Using the node object as a key instead of horizontal distance.
Using the root or queue variables incorrectly.
4fill in blank
hard

Fill both blanks to update the queue with child nodes and their horizontal distances.

DSA Python
if node.left:
    queue.append((node.left, hd [1] 1))
if node.right:
    queue.append((node.right, hd [2] 1))
Drag options to blanks, or click blank then click option'
A-
B+
C*
D//
Attempts:
3 left
💡 Hint
Common Mistakes
Adding 1 to left child horizontal distance.
Subtracting 1 from right child horizontal distance.
5fill in blank
hard

Fill all three blanks to create a dictionary comprehension for bottom view filtering.

DSA Python
bottom_view_map = [1]: [2] for [3], [2] in hd_node.items()}
Drag options to blanks, or click blank then click option'
Ahd
Bvalue
Ckey
Dhd_node
Attempts:
3 left
💡 Hint
Common Mistakes
Using hd instead of key for dictionary keys.
Using hd_node instead of key, value in the loop.

Practice

(1/5)
1. What does the bottom view of a binary tree represent?
easy
A. Nodes visible when the tree is viewed from the right side
B. Nodes visible when the tree is viewed from the top
C. Nodes visible when the tree is viewed from the left side
D. Nodes visible when the tree is viewed from the bottom

Solution

  1. Step 1: Understand the bottom view concept

    The bottom view shows nodes visible when looking at the tree from below, meaning the lowest nodes at each horizontal distance.
  2. Step 2: Compare with other views

    Top view shows nodes from above, left and right views show nodes from sides, so bottom view is unique for bottom perspective.
  3. Final Answer:

    Nodes visible when the tree is viewed from the bottom -> Option D
  4. Quick Check:

    Bottom view = visible nodes from below [OK]
Hint: Bottom view shows lowest nodes at each horizontal distance [OK]
Common Mistakes:
  • Confusing bottom view with top view
  • Thinking bottom view shows all leaf nodes
  • Mixing bottom view with side views
2. Which data structure is commonly used to track nodes and their horizontal distances when computing the bottom view of a binary tree?
easy
A. Hash Map (Dictionary)
B. Queue
C. Stack
D. Linked List

Solution

  1. Step 1: Identify the need for horizontal distance mapping

    We need to map horizontal distances to nodes to know which node is visible at each position.
  2. Step 2: Choose the data structure

    A hash map (dictionary) stores horizontal distance as key and node value as value, updating with the bottom-most node.
  3. Final Answer:

    Hash Map (Dictionary) -> Option A
  4. Quick Check:

    Use dictionary to map horizontal distance to node [OK]
Hint: Use dictionary to map horizontal distance to node [OK]
Common Mistakes:
  • Using stack which is LIFO and not suitable here
  • Using queue alone without mapping distances
  • Using linked list which is inefficient for key-value mapping
3. What is the bottom view output of the following binary tree?
        20
       /  \
     8     22
    / \      \
   5   3      25
      / \     
     10  14
medium
A. [5, 10, 3, 14, 25]
B. [5, 8, 10, 14, 25]
C. [5, 10, 3, 22, 25]
D. [8, 10, 3, 14, 22]

Solution

  1. Step 1: Assign horizontal distances and find bottom nodes

    Horizontal distances: 20(0), 8(-1), 22(1), 5(-2), 3(0), 25(2), 10(-1), 14(1). Bottom nodes at each distance: -2:5, -1:10, 0:3, 1:14, 2:25.
  2. Step 2: List bottom view nodes in order of horizontal distance

    From left to right: 5, 10, 3, 14, 25.
  3. Final Answer:

    [5, 10, 3, 14, 25] -> Option A
  4. Quick Check:

    Bottom view nodes by horizontal distance = [5,10,3,14,25] [OK]
Hint: Track horizontal distances and update bottom nodes [OK]
Common Mistakes:
  • Not updating bottom node when a lower node appears
  • Mixing horizontal distances order
  • Including nodes not visible from bottom
4. Consider this code snippet to compute bottom view of a binary tree:
def bottom_view(root):
    if not root:
        return []
    queue = [(root, 0)]
    hd_node = {}
    while queue:
        node, hd = queue.pop()
        hd_node[hd] = node.val
        if node.left:
            queue.append((node.left, hd - 1))
        if node.right:
            queue.append((node.right, hd + 1))
    return [hd_node[hd] for hd in sorted(hd_node)]
What is the main error in this code?
medium
A. Not checking if root is None
B. Using pop() removes last element, causing wrong traversal order
C. Not updating hd_node dictionary
D. Incorrect horizontal distance calculation

Solution

  1. Step 1: Analyze queue usage and traversal order

    The code uses queue.pop() which removes last element (LIFO), making it behave like a stack, causing depth-first traversal instead of breadth-first.
  2. Step 2: Understand impact on bottom view calculation

    Breadth-first traversal is needed to process nodes level by level to correctly update bottom nodes. Using pop() breaks this order.
  3. Final Answer:

    Using pop() removes last element, causing wrong traversal order -> Option B
  4. Quick Check:

    Use pop(0) or deque.popleft() for BFS [OK]
Hint: Use pop(0) for queue to maintain BFS order [OK]
Common Mistakes:
  • Using pop() instead of pop(0) for queue
  • Ignoring empty root check
  • Incorrect horizontal distance updates
5. You have a binary tree where multiple nodes share the same horizontal distance and depth. How should you modify the bottom view algorithm to always show the node with the greatest depth at each horizontal distance?
hard
A. Store nodes in a list for each horizontal distance and pick the smallest value
B. Store only the first node encountered at each horizontal distance
C. Store both node value and depth in the dictionary, update only if new node depth is greater
D. Ignore depth and update dictionary with last visited node

Solution

  1. Step 1: Understand the need to track depth

    To show the bottom-most node at each horizontal distance, we must know which node is deepest (greatest depth).
  2. Step 2: Modify dictionary to store value and depth

    Store a tuple (node value, depth) for each horizontal distance. Update only if new node's depth is greater than stored depth.
  3. Final Answer:

    Store both node value and depth in the dictionary, update only if new node depth is greater -> Option C
  4. Quick Check:

    Track depth to update bottom view nodes correctly [OK]
Hint: Track depth with node to update bottom view correctly [OK]
Common Mistakes:
  • Ignoring depth and overwriting nodes incorrectly
  • Storing all nodes without filtering by depth
  • Picking first or last node without depth check
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10 questions~5 mineasy hard