Discover how sorting by digits can make your number sorting lightning fast!
Why Radix Sort Algorithm in DSA Javascript?
Imagine you have a huge stack of mail envelopes with different zip codes. You want to sort them by zip code manually, looking at each digit one by one from left to right.
Sorting by looking at each digit manually is slow and confusing. You might mix up envelopes or miss some digits, making the whole process error-prone and tiring.
Radix Sort sorts numbers digit by digit, starting from the least important digit to the most important. It groups numbers by each digit quickly and repeats until fully sorted, making the process fast and reliable.
function manualSort(numbers) {
// Compare whole numbers repeatedly
for (let i = 0; i < numbers.length; i++) {
for (let j = i + 1; j < numbers.length; j++) {
if (numbers[i] > numbers[j]) {
let temp = numbers[i];
numbers[i] = numbers[j];
numbers[j] = temp;
}
}
}
return numbers;
}function radixSort(numbers) {
let maxNumber = Math.max(...numbers);
let digitPosition = 1;
while (Math.floor(maxNumber / digitPosition) > 0) {
numbers = countingSortByDigit(numbers, digitPosition);
digitPosition *= 10;
}
return numbers;
}Radix Sort enables fast and efficient sorting of large lists of numbers by processing digits step-by-step.
Sorting phone numbers or zip codes quickly in a postal system to deliver mail faster.
Manual sorting digit by digit is slow and error-prone.
Radix Sort processes digits from least to most significant for speed.
This method is great for sorting large lists of numbers efficiently.
Practice
Radix Sort Algorithm?Solution
Step 1: Understand Radix Sort approach
Radix Sort sorts numbers by processing each digit separately, starting from the least significant digit (rightmost).Step 2: Compare with other sorting methods
Unlike comparison-based sorts, Radix Sort groups numbers by digits without direct comparisons between whole numbers.Final Answer:
Sort numbers digit by digit starting from the least significant digit -> Option DQuick Check:
Radix Sort = Digit by digit sorting [OK]
- Thinking Radix Sort compares whole numbers directly
- Confusing Radix Sort with quicksort or mergesort
- Assuming it sorts from most significant digit first
Solution
Step 1: Understand bucket initialization
We need 10 separate arrays (buckets) for digits 0-9. UsingArray.fromwith a function creates independent arrays.Step 2: Why other options fail
const buckets = new Array(10).fill([]); fills with the same array reference, causing all buckets to share one array. const buckets = [].map(() => []); fails becausemapon empty array does nothing. const buckets = Array(10).fill(null); fills with null, not arrays.Final Answer:
const buckets = Array.from({ length: 10 }, () => []); -> Option CQuick Check:
Use Array.from with function for separate buckets [OK]
- Using fill([]) creates shared references
- Using map on uninitialized array returns empty
- Filling buckets with null instead of arrays
[170, 45, 75, 90, 802, 24, 2, 66]?
function getDigit(num, place) {
return Math.floor(Math.abs(num) / Math.pow(10, place)) % 10;
}
function radixSort(arr) {
let maxDigit = Math.floor(Math.log10(Math.max(...arr))) + 1;
for (let k = 0; k < maxDigit; k++) {
let buckets = Array.from({ length: 10 }, () => []);
for (let num of arr) {
buckets[getDigit(num, k)].push(num);
}
arr = [].concat(...buckets);
}
return arr;
}
console.log(radixSort([170, 45, 75, 90, 802, 24, 2, 66]));Solution
Step 1: Understand digit extraction and sorting
The code sorts numbers by each digit from least significant (units) to most significant. After each pass, numbers are grouped by that digit.Step 2: Trace sorting passes
After sorting by units digit, then tens, then hundreds, the array becomes fully sorted ascending: [2, 24, 45, 66, 75, 90, 170, 802].Final Answer:
[2, 24, 45, 66, 75, 90, 170, 802] -> Option BQuick Check:
Radix Sort output = Sorted ascending array [OK]
- Confusing original array with sorted output
- Misunderstanding digit extraction order
- Assuming sorting is descending
function radixSort(arr) {
let maxDigit = Math.floor(Math.log10(Math.max(...arr))) + 1;
for (let k = 0; k <= maxDigit; k++) {
let buckets = Array.from({ length: 10 }, () => []);
for (let num of arr) {
buckets[Math.floor(num / Math.pow(10, k)) % 10].push(num);
}
arr = [].concat(...buckets);
}
return arr;
}Solution
Step 1: Analyze loop range for digit passes
The loop runs from 0 to maxDigit inclusive, causing one extra pass beyond needed digits.Step 2: Fix loop condition
Changingk <= maxDigittok < maxDigitensures exactly maxDigit passes, avoiding unnecessary iteration.Final Answer:
Change loop condition to k < maxDigit instead of <= maxDigit -> Option AQuick Check:
Loop runs maxDigit times, not maxDigit+1 [OK]
- Using <= causes extra unnecessary pass
- Initializing buckets incorrectly with shared arrays
- Changing floor to ceil breaks digit count
[170, -45, 75, -90, 802, 24, -2, 66]. Which approach correctly adapts Radix Sort for this case?Solution
Step 1: Understand Radix Sort limitation
Radix Sort works only on non-negative integers because it sorts digits from least significant to most significant.Step 2: Adapt for negatives
Separate negatives and positives. Sort positives normally. For negatives, sort their absolute values, then reverse the result to get correct order. Finally, combine negatives (in reversed order) before positives.Final Answer:
Separate negative and positive numbers, sort positives with Radix Sort, sort negatives by absolute value then reverse, then combine -> Option AQuick Check:
Separate negatives and positives, sort separately [OK]
- Trying to sort negatives directly with Radix Sort
- Ignoring negative numbers in sorting
- Sorting numbers as strings causing wrong order
Ready to prove it?
Pass the test and this pattern moves unknown
