Radix Sort Algorithm in DSA Javascript - Time & Space Complexity

Time Complexity: Radix Sort Algorithm

O(d x n)

Understanding Time Complexity

Radix Sort sorts numbers by processing digits one at a time. Understanding its time complexity helps us see how it handles larger lists efficiently.

We want to know how the number of steps grows as the list and number size increase.

Scenario Under Consideration

Analyze the time complexity of the following Radix Sort code snippet.

function radixSort(arr) {
  const maxNum = Math.max(...arr);
  let digitPlace = 1;
  while (digitPlace <= maxNum) {
    const buckets = Array.from({ length: 10 }, () => []);
    for (const num of arr) {
      const digit = Math.floor((num / digitPlace) % 10);
      buckets[digit].push(num);
    }
    arr = [].concat(...buckets);
    digitPlace *= 10;
  }
  return arr;
}
    

This code sorts an array of numbers by grouping them digit by digit from least to most significant.

Identify Repeating Operations

Identify the loops, recursion, array traversals that repeat.

• Primary operation: Loop over all numbers for each digit place.
• How many times: Once per digit place, which depends on the maximum number's length.

How Execution Grows With Input

Each digit place requires scanning all numbers once. More numbers mean more work per digit. More digits mean more passes.

Input Size (n)	Approx. Operations
10 (digits = 2)	~20 (10 numbers x 2 digits)
100 (digits = 3)	~300 (100 numbers x 3 digits)
1000 (digits = 4)	~4000 (1000 numbers x 4 digits)

Pattern observation: Operations grow linearly with number count and digit length combined.

Final Time Complexity

Time Complexity: O(d x n)

This means the time grows linearly with the number of items and the number of digits in the largest number.

Common Mistake

[X] Wrong: "Radix Sort is always faster than comparison sorts like Quick Sort."

[OK] Correct: Radix Sort depends on digit count and works best on fixed-length numbers. For large digit counts or non-integer data, comparison sorts may be faster.

Interview Connect

Understanding Radix Sort's time complexity shows you can analyze algorithms beyond simple loops. This skill helps you explain and choose sorting methods wisely.

Self-Check

"What if we changed the base from 10 to 2 (binary digits)? How would the time complexity change?"

Practice

1. What is the main idea behind the Radix Sort Algorithm?

easy

A. Sort numbers by swapping adjacent elements repeatedly

B. Sort numbers by comparing each pair directly

C. Sort numbers by dividing them into two halves recursively

D. Sort numbers digit by digit starting from the least significant digit

Solution

1. Step 1: Understand Radix Sort approach

   Radix Sort sorts numbers by processing each digit separately, starting from the least significant digit (rightmost).

2. Step 2: Compare with other sorting methods

   Unlike comparison-based sorts, Radix Sort groups numbers by digits without direct comparisons between whole numbers.

3. Final Answer:

   Sort numbers digit by digit starting from the least significant digit -> Option D

4. Quick Check:

   Radix Sort = Digit by digit sorting [OK]

Hint: Radix Sort processes digits from right to left [OK]

Common Mistakes:

• Thinking Radix Sort compares whole numbers directly
• Confusing Radix Sort with quicksort or mergesort
• Assuming it sorts from most significant digit first

2. Which of the following is the correct way to initialize a bucket array for Radix Sort in JavaScript?

easy

A. const buckets = [].map(() => []);

B. const buckets = new Array(10).fill([]);

C. const buckets = Array.from({ length: 10 }, () => []);

D. const buckets = Array(10).fill(null);

Solution

1. Step 1: Understand bucket initialization

   We need 10 separate arrays (buckets) for digits 0-9. Using Array.from with a function creates independent arrays.

2. Step 2: Why other options fail

   const buckets = new Array(10).fill([]); fills with the same array reference, causing all buckets to share one array. const buckets = [].map(() => []); fails because map on empty array does nothing. const buckets = Array(10).fill(null); fills with null, not arrays.

3. Final Answer:

   const buckets = Array.from({ length: 10 }, () => []); -> Option C

4. Quick Check:

   Use Array.from with function for separate buckets [OK]

Hint: Use Array.from with arrow function for unique buckets [OK]

Common Mistakes:

• Using fill([]) creates shared references
• Using map on uninitialized array returns empty
• Filling buckets with null instead of arrays

3. What will be the output of the following JavaScript code snippet using Radix Sort on the array [170, 45, 75, 90, 802, 24, 2, 66]?

function getDigit(num, place) {
  return Math.floor(Math.abs(num) / Math.pow(10, place)) % 10;
}

function radixSort(arr) {
  let maxDigit = Math.floor(Math.log10(Math.max(...arr))) + 1;
  for (let k = 0; k < maxDigit; k++) {
    let buckets = Array.from({ length: 10 }, () => []);
    for (let num of arr) {
      buckets[getDigit(num, k)].push(num);
    }
    arr = [].concat(...buckets);
  }
  return arr;
}

console.log(radixSort([170, 45, 75, 90, 802, 24, 2, 66]));

medium

A. [170, 45, 75, 90, 802, 24, 2, 66]

B. [2, 24, 45, 66, 75, 90, 170, 802]

C. [802, 170, 90, 75, 66, 45, 24, 2]

D. [2, 24, 45, 66, 75, 170, 90, 802]

Solution

1. Step 1: Understand digit extraction and sorting

   The code sorts numbers by each digit from least significant (units) to most significant. After each pass, numbers are grouped by that digit.

2. Step 2: Trace sorting passes

   After sorting by units digit, then tens, then hundreds, the array becomes fully sorted ascending: [2, 24, 45, 66, 75, 90, 170, 802].

3. Final Answer:

   [2, 24, 45, 66, 75, 90, 170, 802] -> Option B

4. Quick Check:

   Radix Sort output = Sorted ascending array [OK]

Hint: Radix Sort outputs sorted array ascending [OK]

Common Mistakes:

• Confusing original array with sorted output
• Misunderstanding digit extraction order
• Assuming sorting is descending

4. Identify the bug in this Radix Sort snippet and choose the correct fix:

function radixSort(arr) {
  let maxDigit = Math.floor(Math.log10(Math.max(...arr))) + 1;
  for (let k = 0; k <= maxDigit; k++) {
    let buckets = Array.from({ length: 10 }, () => []);
    for (let num of arr) {
      buckets[Math.floor(num / Math.pow(10, k)) % 10].push(num);
    }
    arr = [].concat(...buckets);
  }
  return arr;
}

medium

A. Change loop condition to k < maxDigit instead of <= maxDigit

B. Initialize buckets with new Array(10).fill([])

C. Use Math.ceil instead of Math.floor for maxDigit

D. Remove Math.abs from digit calculation

Solution

1. Step 1: Analyze loop range for digit passes

   The loop runs from 0 to maxDigit inclusive, causing one extra pass beyond needed digits.

2. Step 2: Fix loop condition

   Changing k <= maxDigit to k < maxDigit ensures exactly maxDigit passes, avoiding unnecessary iteration.

3. Final Answer:

   Change loop condition to k < maxDigit instead of <= maxDigit -> Option A

4. Quick Check:

   Loop runs maxDigit times, not maxDigit+1 [OK]

Hint: Loop digits from 0 to less than maxDigit [OK]

Common Mistakes:

• Using <= causes extra unnecessary pass
• Initializing buckets incorrectly with shared arrays
• Changing floor to ceil breaks digit count

5. You want to use Radix Sort to sort an array containing both positive and negative integers, like [170, -45, 75, -90, 802, 24, -2, 66]. Which approach correctly adapts Radix Sort for this case?

hard

A. Separate negative and positive numbers, sort positives with Radix Sort, sort negatives by absolute value then reverse, then combine

B. Apply Radix Sort directly on all numbers including negatives without changes

C. Convert all numbers to strings and sort lexicographically

D. Use Radix Sort only on positive numbers and ignore negatives

Solution

1. Step 1: Understand Radix Sort limitation

   Radix Sort works only on non-negative integers because it sorts digits from least significant to most significant.

2. Step 2: Adapt for negatives

   Separate negatives and positives. Sort positives normally. For negatives, sort their absolute values, then reverse the result to get correct order. Finally, combine negatives (in reversed order) before positives.

3. Final Answer:

   Separate negative and positive numbers, sort positives with Radix Sort, sort negatives by absolute value then reverse, then combine -> Option A

4. Quick Check:

   Separate negatives and positives, sort separately [OK]

Hint: Sort negatives by absolute then reverse, positives normally [OK]

Common Mistakes:

• Trying to sort negatives directly with Radix Sort
• Ignoring negative numbers in sorting
• Sorting numbers as strings causing wrong order