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DSA Javaprogramming~5 mins

Vertical Order Traversal of Binary Tree in DSA Java - Cheat Sheet & Quick Revision

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Recall & Review
beginner
What is Vertical Order Traversal of a Binary Tree?
It is a way to print the nodes of a binary tree column by column, from left to right. Nodes in the same vertical line are grouped together.
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beginner
How do we assign horizontal distances (HD) to nodes in Vertical Order Traversal?
The root node is assigned HD = 0. For any node, its left child has HD = parent's HD - 1, and its right child has HD = parent's HD + 1.
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intermediate
Which data structure is commonly used to store nodes by their horizontal distance during Vertical Order Traversal?
A map (like TreeMap in Java) is used where keys are horizontal distances and values are lists of nodes at that distance.
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intermediate
Why do we use level order traversal (BFS) in Vertical Order Traversal?
Level order traversal ensures nodes are processed top to bottom within the same vertical line, preserving the correct order.
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beginner
What is the output of Vertical Order Traversal for this tree? 1 / \ 2 3 \ \ 4 5
The vertical order is: - HD -1: [2] - HD 0: [1, 4] - HD 1: [3] - HD 2: [5]
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In Vertical Order Traversal, what horizontal distance is assigned to the root node?
A-1
B1
C0
DDepends on tree height
Which traversal method is best suited to maintain top-to-bottom order in Vertical Order Traversal?
ALevel order (BFS)
BInorder
CPreorder
DPostorder
If a node has horizontal distance HD, what is the HD of its right child?
AHD - 1
BHD * 2
CHD
DHD + 1
Which data structure helps to keep vertical lines sorted from left to right?
AHashMap
BTreeMap
CStack
DQueue
What is the vertical order output for a tree with only root node 10?
A[10]
B[]
C[null]
D[10, 10]
Explain how to perform Vertical Order Traversal of a binary tree step-by-step.
Think about horizontal distances and level order traversal.
You got /5 concepts.
    Describe why level order traversal is important in Vertical Order Traversal compared to other traversals.
    Consider node order within the same vertical line.
    You got /4 concepts.

      Practice

      (1/5)
      1. What does Vertical Order Traversal of a binary tree mean?
      easy
      A. Nodes are grouped by their vertical columns from left to right
      B. Nodes are visited in preorder (root, left, right)
      C. Nodes are visited level by level from top to bottom
      D. Nodes are grouped by their horizontal rows from top to bottom

      Solution

      1. Step 1: Understand vertical columns in a tree

        Vertical order groups nodes by their horizontal distance from the root, called columns.
      2. Step 2: Define vertical order traversal

        Nodes in the same vertical column are collected and output from leftmost to rightmost column.
      3. Final Answer:

        Nodes are grouped by their vertical columns from left to right -> Option A
      4. Quick Check:

        Vertical order = group by columns [OK]
      Hint: Think columns from left to right, not rows or preorder [OK]
      Common Mistakes:
      • Confusing vertical order with level order traversal
      • Thinking vertical order is preorder or inorder traversal
      • Mixing horizontal rows with vertical columns
      2. Which Java data structure is best to store nodes grouped by their vertical column during vertical order traversal?
      easy
      A. ArrayList<Integer>
      B. HashMap
      C. Stack<Integer>
      D. Queue<Integer>

      Solution

      1. Step 1: Identify need to map columns to nodes

        We need to group nodes by their vertical column index, so a map from column to list of nodes is needed.
      2. Step 2: Choose suitable Java data structure

        A HashMap with key as column index (Integer) and value as list of nodes (List<Integer>) fits perfectly.
      3. Final Answer:

        HashMap -> Option B
      4. Quick Check:

        Map column to nodes = HashMap [OK]
      Hint: Use map from column index to list of nodes [OK]
      Common Mistakes:
      • Using ArrayList alone without mapping columns
      • Using Stack or Queue which don't map keys to lists
      • Confusing data structures for traversal order
      3. What is the vertical order traversal output of this binary tree?
      
          1
         / \
        2   3
       / \   \
      4   5   6
      
      medium
      A. [4, 2, 1, 3, 5, 6]
      B. [1, 2, 3, 4, 5, 6]
      C. [4, 2, 1, 5, 3, 6]
      D. [4, 5, 2, 1, 3, 6]

      Solution

      1. Step 1: Assign column indices to nodes

        Root 1 is at column 0. Left child 2 at -1, right child 3 at +1. 4 at -2, 5 at 0, 6 at +2.
      2. Step 2: Collect nodes column-wise from left to right

        Columns: -2: [4], -1: [2], 0: [1,5], 1: [3], 2: [6]. Combine: [4, 2, 1, 5, 3, 6]
      3. Final Answer:

        [4, 2, 1, 5, 3, 6] -> Option C
      4. Quick Check:

        Columns left to right = [4,2,1,5,3,6] [OK]
      Hint: Label columns from root 0, left -1, right +1, then read left to right [OK]
      Common Mistakes:
      • Ignoring multiple nodes in same column order
      • Mixing preorder or inorder output with vertical order
      • Not assigning correct column indices
      4. Given this Java snippet for vertical order traversal, what is the error?
      
      Map map = new HashMap<>();
      Queue> queue = new LinkedList<>();
      queue.add(new Pair(root, 0));
      while (!queue.isEmpty()) {
        Pair p = queue.poll();
        TreeNode node = p.getKey();
        int col = p.getValue();
        map.putIfAbsent(col, new ArrayList<>());
        map.get(col).add(node.val);
        if (node.left != null) queue.add(new Pair(node.left, col - 1));
        if (node.right != null) queue.add(new Pair(node.right, col + 1));
      }
      
      medium
      A. Pair class is not imported or defined
      B. Queue should be a Stack for correct traversal
      C. map.putIfAbsent should be replaced with map.put
      D. col should be incremented for left child, not decremented

      Solution

      1. Step 1: Check usage of Pair class

        The code uses Pair but Java does not have Pair by default; it must be imported or defined.
      2. Step 2: Identify missing import or definition

        Without importing javafx.util.Pair or defining a custom Pair class, this code will not compile.
      3. Final Answer:

        Pair class is not imported or defined -> Option A
      4. Quick Check:

        Missing Pair class causes compile error [OK]
      Hint: Check if all classes like Pair are imported or defined [OK]
      Common Mistakes:
      • Assuming Pair is built-in in Java standard library
      • Using Stack instead of Queue for BFS traversal
      • Incorrect column increment direction for left child
      5. How would you modify vertical order traversal to output nodes sorted by row and then value within each vertical column? Choose the best approach.
      hard
      A. Use a Queue and print nodes as they are visited
      B. Use a HashMap and sort each list after traversal
      C. Use a Stack to store nodes and pop in sorted order
      D. Use a TreeMap> to map column -> row -> sorted nodes

      Solution

      1. Step 1: Understand sorting by row and value in vertical columns

        We need to group nodes by column, then by row, and sort nodes with same row by value.
      2. Step 2: Choose data structure supporting nested sorting

        TreeMap for columns and rows keeps keys sorted. PriorityQueue stores nodes sorted by value. So TreeMap> fits.
      3. Final Answer:

        Use a TreeMap> to map column -> row -> sorted nodes -> Option D
      4. Quick Check:

        Nested TreeMaps + PriorityQueue = sorted vertical order [OK]
      Hint: Use nested TreeMaps and PriorityQueue for sorted vertical order [OK]
      Common Mistakes:
      • Sorting lists after traversal loses row info
      • Using Stack or Queue which don't sort nodes
      • Ignoring row sorting within columns
      Recommended

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      10 questions~5 mineasy hard