What if you could sort thousands of numbers without comparing them directly, just by looking at their digits?
Why Radix Sort Algorithm in DSA Java?
Imagine you have a huge stack of mail envelopes with different zip codes, and you need to sort them by zip code to deliver them efficiently.
Doing this by looking at each zip code digit by digit manually would take forever and be very confusing.
Sorting these envelopes by comparing whole zip codes one by one is slow and tiring.
It's easy to make mistakes, especially when zip codes are long or many.
Manual sorting also wastes time because you have to compare every pair repeatedly.
Radix Sort solves this by sorting the zip codes digit by digit, starting from the least important digit to the most important.
This way, it groups envelopes quickly without comparing whole numbers directly.
It's like sorting mail by the last digit first, then the second last, and so on, making the process fast and organized.
for (int i = 0; i < array.length; i++) { for (int j = i + 1; j < array.length; j++) { if (array[i] > array[j]) { int temp = array[i]; array[i] = array[j]; array[j] = temp; } } }
for (int digit = 1; max / digit > 0; digit *= 10) { countingSortByDigit(array, digit); }
Radix Sort enables fast sorting of large lists of numbers by breaking the problem into simple digit-based steps.
Sorting phone numbers in a contact list quickly so you can find any number without delay.
Manual sorting by full numbers is slow and error-prone.
Radix Sort sorts numbers digit by digit for speed and simplicity.
This method is great for sorting large sets of numbers like zip codes or phone numbers.
Practice
Radix Sort algorithm?Solution
Step 1: Understand Radix Sort approach
Radix Sort sorts numbers by processing individual digits starting from the least significant digit (rightmost) to the most significant digit (leftmost).Step 2: Compare with other sorting methods
Other options describe Bubble Sort, Merge Sort, and Quick Sort, which are different algorithms.Final Answer:
Sort numbers digit by digit starting from the least significant digit -> Option AQuick Check:
Radix Sort = Digit by digit sorting [OK]
- Confusing Radix Sort with comparison-based sorts
- Thinking it sorts from most significant digit first
- Assuming it uses pivot or divide and conquer
pos (starting from 0 for least significant digit) of a number num in Java?Solution
Step 1: Understand digit extraction logic
To get the digit at position pos, divide num by 10^pos to shift digits right, then take modulo 10 to get the last digit.Step 2: Check each option
(num / (int) Math.pow(10, pos)) % 10 correctly divides num by 10^pos and then modulo 10. Others do incorrect operations.Final Answer:
(num / (int) Math.pow(10, pos)) % 10 -> Option BQuick Check:
Digit extraction = divide then modulo [OK]
- Using modulo before division
- Multiplying instead of dividing
- Incorrect order of operations
[170, 45, 75, 90, 802] sorting by the least significant digit (units place)?Solution
Step 1: Extract least significant digit of each number
170 -> 0, 45 -> 5, 75 -> 5, 90 -> 0, 802 -> 2Step 2: Sort array by these digits
Order by digits: 0s first (170, 90), then 2 (802), then 5s (45, 75). So array becomes [170, 90, 802, 45, 75]Final Answer:
[170, 90, 802, 45, 75] -> Option CQuick Check:
Sort by units digit = [170, 90, 802, 45, 75] [OK]
- Sorting entire numbers instead of digits
- Mixing digit positions
- Ignoring stable sorting requirement
int digit = (num % (int) Math.pow(10, pos)) / (int) Math.pow(10, pos - 1);What is the error in this code?
Solution
Step 1: Analyze division when pos = 0
When pos = 0, expression divides by Math.pow(10, -1), which is 10^-1 = 0.1, but casting to int makes it 0, causing division by zero error.Step 2: Check other options
Modulo and division order is correct for digit extraction, casting is intentional, so no other errors.Final Answer:
Division by zero when pos = 0 -> Option DQuick Check:
pos=0 causes division by zero [OK]
- Ignoring pos=0 edge case
- Assuming casting fixes division issues
- Thinking modulo order is wrong
[329, 457, 657, 839, 436, 720, 355], how many passes (iterations over digits) will Radix Sort perform to fully sort this array?Solution
Step 1: Find the maximum number of digits in the array
The largest number is 839, which has 3 digits.Step 2: Determine passes needed
Radix Sort performs one pass per digit, so 3 passes are needed (units, tens, hundreds).Final Answer:
3 passes -> Option AQuick Check:
Max digits = 3, passes = 3 [OK]
- Counting array length instead of digit count
- Assuming fixed number of passes
- Ignoring leading zeros in numbers
Ready to prove it?
Pass the test and this pattern moves unknown
