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DSA Goprogramming~10 mins

Trie Node Design and Initialization in DSA Go - Interactive Practice

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Practice - 5 Tasks
Answer the questions below
1fill in blank
easy

Complete the code to declare a TrieNode struct with a children map.

DSA Go
type TrieNode struct {
    children map[rune]*[1]
    isEnd bool
}
Drag options to blanks, or click blank then click option'
ANode
BTrieNode
CTreeNode
DTrie
Attempts:
3 left
💡 Hint
Common Mistakes
Using a different struct name for children map values.
Not using pointers for child nodes.
2fill in blank
medium

Complete the code to initialize a new TrieNode with an empty children map.

DSA Go
func NewTrieNode() *TrieNode {
    return &TrieNode{
        children: make(map[rune]*[1]),
        isEnd: false,
    }
}
Drag options to blanks, or click blank then click option'
ATrie
BNode
CTreeNode
DTrieNode
Attempts:
3 left
💡 Hint
Common Mistakes
Using make with wrong type.
Not initializing the map, causing nil map errors.
3fill in blank
hard

Fix the error in the code to add a child node for a character key.

DSA Go
func (node *TrieNode) AddChild(ch rune) {
    if node.children == nil {
        node.children = make(map[rune]*[1])
    }
    node.children[ch] = NewTrieNode()
}
Drag options to blanks, or click blank then click option'
ATrieNode
BNode
CTreeNode
DTrie
Attempts:
3 left
💡 Hint
Common Mistakes
Using incorrect struct name in map initialization.
Not initializing the map before adding children.
4fill in blank
hard

Fill both blanks to check if a child node exists and return it.

DSA Go
func (node *TrieNode) GetChild(ch rune) (*TrieNode, bool) {
    child, [1] := node.children[ch]
    return child, [2]
}
Drag options to blanks, or click blank then click option'
Aok
Bexists
Cfound
Dpresent
Attempts:
3 left
💡 Hint
Common Mistakes
Using variable names other than 'ok' for the comma-ok idiom.
Returning the wrong variable for existence check.
5fill in blank
hard

Fill all three blanks to insert a word into the trie.

DSA Go
func (node *TrieNode) Insert(word string) {
    current := node
    for _, ch := range word {
        child, [1] := current.children[ch]
        if ![2] {
            child = NewTrieNode()
            current.children[ch] = [3]
        }
        current = child
    }
    current.isEnd = true
}
Drag options to blanks, or click blank then click option'
Aok
Bexists
Cchild
Dpresent
Attempts:
3 left
💡 Hint
Common Mistakes
Using wrong variable names for existence check.
Not assigning the new node to the children map.

Practice

(1/5)
1. What is the primary purpose of a Trie node in a Trie data structure?
easy
A. To store characters and links to child nodes for prefix-based search
B. To store integer values for sorting
C. To hold a single string value only
D. To act as a queue for BFS traversal

Solution

  1. Step 1: Understand Trie node role

    A Trie node stores characters and links to child nodes to represent prefixes of words.
  2. Step 2: Compare options

    Only To store characters and links to child nodes for prefix-based search correctly describes storing characters and child links for prefix search.
  3. Final Answer:

    To store characters and links to child nodes for prefix-based search -> Option A
  4. Quick Check:

    Trie node = prefix storage [OK]
Hint: Trie nodes hold characters and children for prefix search [OK]
Common Mistakes:
  • Thinking Trie nodes store whole words only
  • Confusing Trie nodes with array or queue structures
  • Assuming Trie nodes store integer values
2. Which of the following is the correct way to declare a Trie node struct in Go with children for 26 lowercase letters and a boolean to mark end of word?
easy
A. type TrieNode struct { children [26]*TrieNode; isEnd bool }
B. type TrieNode struct { children []*TrieNode; isEnd int }
C. type TrieNode struct { children map[int]TrieNode; isEnd bool }
D. type TrieNode struct { children [26]TrieNode; isEnd string }

Solution

  1. Step 1: Check children type

    Children should be an array of pointers to TrieNode for 26 letters: [26]*TrieNode.
  2. Step 2: Check isEnd type

    isEnd should be boolean to mark word end.
  3. Final Answer:

    type TrieNode struct { children [26]*TrieNode; isEnd bool } -> Option A
  4. Quick Check:

    Children as pointer array + bool isEnd = type TrieNode struct { children [26]*TrieNode; isEnd bool } [OK]
Hint: Use array of pointers and bool for end marker [OK]
Common Mistakes:
  • Using slice instead of fixed array for children
  • Using int or string instead of bool for isEnd
  • Using map with wrong key type
3. What will be the output of the following Go code snippet?
type TrieNode struct {
  children [26]*TrieNode
  isEnd bool
}

func main() {
  root := &TrieNode{}
  if root.children[0] == nil {
    println("No child at index 0")
  } else {
    println("Child exists at index 0")
  }
}
medium
A. Compilation error
B. No child at index 0
C. Child exists at index 0
D. Runtime panic

Solution

  1. Step 1: Understand initialization of children array

    When root is created, children array elements are nil pointers by default.
  2. Step 2: Check condition in if statement

    root.children[0] is nil, so condition is true and prints "No child at index 0".
  3. Final Answer:

    No child at index 0 -> Option B
  4. Quick Check:

    Uninitialized children = nil pointers [OK]
Hint: Uninitialized pointer arrays have nil elements [OK]
Common Mistakes:
  • Assuming children are auto-initialized with nodes
  • Expecting compilation or runtime errors
  • Confusing zero values for pointers
4. Identify the error in this Go code snippet for initializing a Trie node:
type TrieNode struct {
  children [26]*TrieNode
  isEnd bool
}

func NewNode() *TrieNode {
  node := TrieNode{}
  node.isEnd = false
  return &node
}
medium
A. isEnd should be true by default
B. Children array is not initialized with pointers
C. Function returns a pointer to a local variable
D. Syntax error in struct declaration

Solution

  1. Step 1: Analyze the NewNode function

    The function creates a local struct variable node and returns its address &node.
  2. Step 2: Identify the problem

    Returning the pointer to a local variable risks a dangling pointer after the function exits, even though Go's escape analysis heap-allocates it; it's poor practice and should use &TrieNode{} instead.
  3. Final Answer:

    Function returns a pointer to a local variable -> Option C
  4. Quick Check:

    Return &local_var = bad practice [OK]
Hint: Avoid returning pointers to local variables [OK]
Common Mistakes:
  • Thinking children must be explicitly initialized
  • Confusing pointer nil with error
  • Assuming isEnd default must be true
5. You want to initialize a Trie node in Go that supports Unicode characters instead of just 26 lowercase letters. Which data structure change is best to support this efficiently?
hard
A. Keep children as [26]*TrieNode but convert Unicode to lowercase ASCII
B. Increase children array size to 65536 elements
C. Use slice []*TrieNode with fixed size 26
D. Change children from [26]*TrieNode array to map[rune]*TrieNode

Solution

  1. Step 1: Understand Unicode support needs

    Unicode has many characters beyond 26 letters, so fixed array is inefficient.
  2. Step 2: Evaluate data structure options

    Using map[rune]*TrieNode allows dynamic keys for any Unicode character efficiently.
  3. Step 3: Reject other options

    Array of 65536 is large and wasteful; slice with fixed size 26 is too small; converting Unicode to ASCII loses data.
  4. Final Answer:

    Change children from [26]*TrieNode array to map[rune]*TrieNode -> Option D
  5. Quick Check:

    Map with rune keys = Unicode support [OK]
Hint: Use map with rune keys for Unicode children [OK]
Common Mistakes:
  • Using large fixed arrays wasting memory
  • Ignoring Unicode complexity
  • Trying to fit Unicode into ASCII-only arrays
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