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DSA C++programming~5 mins

Tree Traversal Inorder Left Root Right in DSA C++ - Cheat Sheet & Quick Revision

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Recall & Review
beginner
What is the order of nodes visited in an inorder tree traversal?
In inorder traversal, nodes are visited in the order: Left subtree, then Root node, and finally Right subtree.
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beginner
Why is inorder traversal useful for binary search trees (BST)?
Inorder traversal of a BST visits nodes in ascending sorted order because it visits left (smaller), root, then right (larger) nodes.
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beginner
What is the base case in a recursive inorder traversal function?
The base case is when the current node is null (no node), then the function returns without doing anything.
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beginner
Show the inorder traversal output for this tree:<br>Root=2, Left=1, Right=3
The inorder traversal visits nodes in order: 1 (left), 2 (root), 3 (right). So output is: 1 -> 2 -> 3
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beginner
What is the time complexity of inorder traversal on a binary tree with n nodes?
The time complexity is O(n) because each node is visited exactly once.
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In inorder traversal, which node is visited first?
ALeft child
BRoot node
CRight child
DNone
What is the output of inorder traversal on a BST with nodes 5, 3, 7?
A5 -> 3 -> 7
B3 -> 5 -> 7
C7 -> 5 -> 3
D3 -> 7 -> 5
What happens when the inorder traversal function reaches a null node?
AIt visits the null node
BIt throws an error
CIt stops and returns
DIt skips to the right subtree
Which traversal order is correct for inorder?
ARoot, Left, Right
BRoot, Right, Left
CRight, Root, Left
DLeft, Root, Right
How many times is each node visited in inorder traversal?
AOnce
BTwice
CThree times
DDepends on tree height
Explain the steps of inorder traversal on a binary tree.
Think about visiting left first, then root, then right.
You got /4 concepts.
    Describe why inorder traversal outputs sorted nodes in a binary search tree.
    Connect BST ordering with traversal order.
    You got /3 concepts.