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DSA C++programming~5 mins

Check if Binary Tree is Balanced in DSA C++ - Cheat Sheet & Quick Revision

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Recall & Review
beginner
What does it mean for a binary tree to be balanced?
A binary tree is balanced if for every node, the height difference between its left and right subtrees is at most 1.
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beginner
Why is checking balance important in binary trees?
Balanced trees ensure operations like search, insert, and delete run efficiently, typically in O(log n) time.
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intermediate
What is the main idea behind the efficient algorithm to check if a binary tree is balanced?
Use a bottom-up approach that returns the height of subtrees and checks balance at the same time to avoid repeated height calculations.
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intermediate
What does the function return if the subtree is not balanced in the efficient approach?
It returns -1 to indicate the subtree is not balanced, which helps stop further unnecessary checks.
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beginner
In the context of checking if a binary tree is balanced, what is the height of a null node?
The height of a null node is defined as 0, meaning it contributes no height to the tree.
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What is the maximum allowed height difference between left and right subtrees for a node to be balanced?
A0
B2
C1
D3
Which approach is more efficient to check if a binary tree is balanced?
ALevel order traversal only
BTop-down approach calculating height repeatedly
CInorder traversal only
DBottom-up approach returning height and balance status
What does a height function return when it detects an unbalanced subtree?
A0
B-1
C1
DHeight of the subtree
What is the height of an empty (null) subtree?
A0
B-1
C1
DUndefined
If a binary tree is balanced, what is the time complexity of checking it using the bottom-up approach?
AO(n)
BO(n^2)
CO(n log n)
DO(log n)
Explain how the bottom-up approach checks if a binary tree is balanced.
Think about how you can combine height calculation and balance checking in one function.
You got /4 concepts.
    Describe why the top-down approach to check balance is less efficient than the bottom-up approach.
    Consider how many times each node is processed in both approaches.
    You got /4 concepts.