Bubble Sort Algorithm in DSA C++ - Build from Scratch

Bubble Sort Algorithm

📖 Scenario: You have a list of numbers that are not in order. You want to arrange them from smallest to largest, like sorting books by height on a shelf.

🎯 Goal: Build a program that uses the Bubble Sort Algorithm to sort a list of numbers in ascending order.

📋 What You'll Learn

Create an array called numbers with the exact values: 5, 3, 8, 4, 2

Create an integer variable called n that stores the size of the numbers array

Use nested for loops with variables i and j to implement the bubble sort logic

Swap adjacent elements if the left one is greater than the right one

Print the sorted array elements separated by spaces

💡 Why This Matters

🌍 Real World

Sorting is used in many places like organizing data, searching faster, and preparing lists for reports.

💼 Career

Understanding sorting algorithms like bubble sort helps in coding interviews and building efficient software.

1

Create the array of numbers

Create an integer array called numbers with these exact values: 5, 3, 8, 4, 2

DSA C++

// Create the array called numbers with values 5, 3, 8, 4, 2
// Your code here

Hint

Use the syntax int numbers[] = {value1, value2, ...}; to create the array.

2

Set the size of the array

Create an integer variable called n and set it to the size of the numbers array using sizeof(numbers) / sizeof(numbers[0])

DSA C++

int numbers[] = {5, 3, 8, 4, 2};
// Create the variable n to store the size of numbers
// Your code here

Hint

Use sizeof to find the total size of the array and divide by the size of one element.

3

Implement the bubble sort logic

Use nested for loops with variables i and j to compare and swap adjacent elements in numbers if the left element is greater than the right element

DSA C++

int numbers[] = {5, 3, 8, 4, 2};
int n = sizeof(numbers) / sizeof(numbers[0]);
// Use nested for loops with i and j to sort numbers using bubble sort
// Your code here

Hint

Use two loops: the outer loop with i and the inner loop with j. Swap elements if the left one is bigger.

4

Print the sorted array

Use a for loop with variable i to print each element of numbers separated by spaces

DSA C++

int numbers[] = {5, 3, 8, 4, 2};
int n = sizeof(numbers) / sizeof(numbers[0]);
for (int i = 0; i  numbers[j + 1]) {
            int temp = numbers[j];
            numbers[j] = numbers[j + 1];
            numbers[j + 1] = temp;
        }
    }
}
// Print the sorted array elements separated by spaces
// Your code here

Hint

Use std::cout inside a loop to print each number followed by a space.