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DSA C++programming~10 mins

BST Delete Operation in DSA C++ - Execution Trace

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Concept Flow - BST Delete Operation
Start at root
Find node to delete
Node found?
NoStop: Node not found
Yes
Check children count
Delete
Replace node data
Delete inorder successor
Done
The delete operation in a BST first finds the node, then deletes it based on its children count: no child, one child, or two children with inorder successor replacement.
Execution Sample
DSA C++
DeleteNode(root, 20);

// Deletes node with value 20 from BST
This code deletes the node with value 20 from the BST, adjusting pointers to maintain BST properties.
Execution Table
StepOperationNode VisitedPointer ChangesVisual State
1Start at root50None┌────────┐ ┌────────┐ ┌────────┐ ┌────────┐ ┌────────┐ │ data:50│ │ data:30│ │ data:70│ │ data:20│ │ data:40│ │ nextL:─┼──→ │ nextL:─┼──→ │ nextL:∅ │ │ nextL:∅ │ │ nextL:∅ │ │ nextR:─┼──→ │ nextR:─┼──→ │ nextR:─┼──→ │ nextR:∅ │ │ nextR:∅ │ └────────┘ └────────┘ └────────┘ └────────┘ └────────┘ head
2Traverse left (20 < 50)30NoneSame as step 1
3Traverse left (20 < 30)20NoneSame as step 1
4Node found (20)20NoneSame as step 1
5Check children count (0 children)20NoneSame as step 1
6Delete node 20 (leaf)20Parent(30).nextL = null┌────────┐ ┌────────┐ ┌────────┐ ┌────────┐ │ data:50│ │ data:30│ │ data:70│ │ data:40│ │ nextL:─┼──→ │ nextL:∅ │ │ nextL:∅ │ │ nextL:∅ │ │ nextR:─┼──→ │ nextR:─┼──→ │ nextR:∅ │ │ nextR:∅ │ └────────┘ └────────┘ └────────┘ └────────┘ head
7DonenullNoneFinal tree without node 20
💡 Node 20 deleted as leaf node, parent pointer updated to null
Variable Tracker
VariableStartAfter Step 2After Step 3After Step 6Final
current503020nullnull
parentnull50303030
root5050505050
Key Moments - 3 Insights
Why do we update parent.nextL to null when deleting node 20?
Because node 20 is a leaf with no children, we remove it by setting its parent's left pointer to null, as shown in step 6 of the execution_table.
What if the node to delete had one child?
We would replace the node with its single child by updating the parent's pointer to skip the node, similar to step 6 but pointing to the child instead of null.
Why do we traverse left when 20 < 50 and then 20 < 30?
Because in BST, smaller values go to the left subtree. The traversal steps 2 and 3 show moving left to find the node 20.
Visual Quiz - 3 Questions
Test your understanding
Look at the execution_table, what is the 'current' node at step 3?
A50
B30
C20
Dnull
💡 Hint
Check the 'Node Visited' column at step 3 in execution_table
At which step does the parent's pointer get updated to remove the node?
AStep 4
BStep 5
CStep 6
DStep 7
💡 Hint
Look at 'Pointer Changes' column for when parent.nextL changes in execution_table
If node 20 had a right child, how would the pointer change in step 6?
Aparent.nextL = null
Bparent.nextL = node 20's right child
Cparent.nextR = node 20's right child
DNo pointer change
💡 Hint
Refer to key_moments about one child replacement and pointer updates
Concept Snapshot
BST Delete Operation:
- Find node to delete by BST property
- If leaf: remove by setting parent's pointer to null
- If one child: replace node with child
- If two children: replace with inorder successor
- Update pointers carefully to maintain BST
- Traversal follows left/right based on value
Full Transcript
The BST delete operation starts at the root and traverses left or right to find the node to delete. Once found, it checks the number of children. If the node is a leaf (no children), it is simply removed by setting the parent's pointer to null. If the node has one child, the parent's pointer is updated to point to that child, effectively removing the node. If the node has two children, the inorder successor is found, its value replaces the node's value, and then the successor node is deleted. This process maintains the BST properties. The execution table shows step-by-step traversal and pointer updates, especially how the parent's next pointer changes when deleting a leaf node. The variable tracker follows the current node and parent pointers during traversal and deletion.