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C Sharp (C#)programming~10 mins

Object instantiation with new in C Sharp (C#) - Interactive Code Practice

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Practice - 5 Tasks
Answer the questions below
1fill in blank
easy

Complete the code to create a new instance of the class Car.

C Sharp (C#)
Car myCar = [1] Car();
Drag options to blanks, or click blank then click option'
Anew
Bcreate
Cmake
Dinit
Attempts:
3 left
💡 Hint
Common Mistakes
Using 'create' or 'make' instead of 'new' causes a syntax error.
Forgetting the 'new' keyword leads to a compile-time error.
2fill in blank
medium

Complete the code to instantiate a Person object with the default constructor.

C Sharp (C#)
Person person = [1] Person();
Drag options to blanks, or click blank then click option'
Anew
Binit
Ccreate
Dmake
Attempts:
3 left
💡 Hint
Common Mistakes
Using 'init' or 'create' instead of 'new' causes errors.
Omitting the keyword entirely results in a compile error.
3fill in blank
hard

Fix the error in the code to correctly instantiate a Book object.

C Sharp (C#)
Book myBook = [1]Book();
Drag options to blanks, or click blank then click option'
Amake
Bcreate
Cinit
Dnew
Attempts:
3 left
💡 Hint
Common Mistakes
Leaving out the space after the keyword causes syntax errors.
Using incorrect keywords like 'create' or 'make' leads to errors.
4fill in blank
hard

Fill both blanks to instantiate a Student object and assign it to a variable.

C Sharp (C#)
[1] [2] = new Student();
Drag options to blanks, or click blank then click option'
AStudent
Bvar
Cstudent
Dnew
Attempts:
3 left
💡 Hint
Common Mistakes
Using the class name twice causes syntax errors.
Using 'new' as a variable name is invalid.
5fill in blank
hard

Fill all three blanks to instantiate a Rectangle object with width and height parameters.

C Sharp (C#)
Rectangle [1] = new Rectangle([2], [3]);
Drag options to blanks, or click blank then click option'
Arect
B5
C10
Drectangle
Attempts:
3 left
💡 Hint
Common Mistakes
Using the class name as a variable name causes confusion.
Swapping the width and height values changes the rectangle size.

Practice

(1/5)
1. What does the new keyword do in C# when used like new MyClass()?
easy
A. It calls a static method of MyClass.
B. It deletes an existing object of MyClass.
C. It converts MyClass to a string.
D. It creates a new object instance of the class MyClass.

Solution

  1. Step 1: Understand the role of new

    The new keyword in C# is used to create a fresh object from a class blueprint.
  2. Step 2: Apply to the example new MyClass()

    This expression creates a new instance of the class MyClass by calling its constructor.
  3. Final Answer:

    It creates a new object instance of the class MyClass. -> Option D
  4. Quick Check:

    new creates object = C [OK]
Hint: Remember: new means create a fresh object [OK]
Common Mistakes:
  • Thinking new deletes or modifies existing objects
  • Confusing new with method calls
  • Forgetting parentheses after class name
2. Which of the following is the correct syntax to create a new object of class Person?
easy
A. Person p = new Person;
B. Person p = Person.new();
C. Person p = new Person();
D. Person p = Person();

Solution

  1. Step 1: Check correct use of new keyword and parentheses

    In C#, to create a new object, you must use new ClassName() with parentheses.
  2. Step 2: Analyze each option

    Person p = new Person(); uses new Person(); correctly. Person p = Person.new(); uses wrong syntax with dot notation. Person p = new Person; misses parentheses. Person p = Person(); misses new.
  3. Final Answer:

    Person p = new Person(); -> Option C
  4. Quick Check:

    Correct syntax = A [OK]
Hint: Always use new ClassName() with parentheses [OK]
Common Mistakes:
  • Omitting parentheses after class name
  • Using dot notation with new
  • Forgetting the new keyword
3. What will be the output of this code?
class Box {
  public int size;
  public Box(int s) { size = s; }
}

var b = new Box(5);
Console.WriteLine(b.size);
medium
A. 5
B. 0
C. null
D. Compilation error

Solution

  1. Step 1: Understand the constructor call

    The constructor Box(int s) sets the field size to the passed value s. Here, new Box(5) sets size = 5.
  2. Step 2: Check the output of Console.WriteLine(b.size)

    This prints the value of b.size, which was set to 5 by the constructor.
  3. Final Answer:

    5 -> Option A
  4. Quick Check:

    Constructor sets size = 5 [OK]
Hint: Constructor sets values; output shows assigned value [OK]
Common Mistakes:
  • Assuming default 0 instead of constructor value
  • Confusing null with int fields
  • Thinking code won't compile
4. Identify the error in this code snippet:
class Car {
  public string model;
  public Car(string m) { model = m; }
}

Car c = new Car;
medium
A. Class Car has no constructor defined.
B. Missing parentheses after Car in object creation.
C. model field is not initialized.
D. Cannot assign new Car to variable c.

Solution

  1. Step 1: Check object instantiation syntax

    In C#, when creating a new object, parentheses must follow the class name even if no arguments are passed.
  2. Step 2: Analyze the code snippet

    The code uses new Car; without parentheses, which causes a syntax error.
  3. Final Answer:

    Missing parentheses after Car in object creation. -> Option B
  4. Quick Check:

    new requires parentheses () [OK]
Hint: Always add () after new ClassName [OK]
Common Mistakes:
  • Omitting parentheses after new keyword
  • Assuming default constructor exists without parentheses
  • Ignoring compiler error messages
5. You want to create two independent objects of class Student with different names. Which code correctly does this?
hard
A. Student s1 = new Student("Alice"); Student s2 = new Student("Bob");
B. Student s1 = Student("Alice"); Student s2 = Student("Bob");
C. Student s1, s2 = new Student("Alice"), new Student("Bob");
D. Student s1 = new Student; Student s2 = new Student;

Solution

  1. Step 1: Understand object creation with parameters

    To create objects with different names, call the constructor with the name string for each object separately using new Student(name).
  2. Step 2: Analyze each option

    Student s1 = new Student("Alice"); Student s2 = new Student("Bob"); correctly creates two objects with different names. Student s1 = Student("Alice"); Student s2 = Student("Bob"); misses new. Student s1, s2 = new Student("Alice"), new Student("Bob"); has invalid syntax for multiple declarations. Student s1 = new Student; Student s2 = new Student; misses parentheses and parameters.
  3. Final Answer:

    Student s1 = new Student("Alice"); Student s2 = new Student("Bob"); -> Option A
  4. Quick Check:

    Use new with constructor for each object [OK]
Hint: Create each object with new and constructor call [OK]
Common Mistakes:
  • Forgetting new keyword
  • Trying to create multiple objects in one line incorrectly
  • Omitting constructor parameters