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C Sharp (C#)programming~5 mins

Multiple interface implementation in C Sharp (C#)

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Introduction

Sometimes a class needs to do many different jobs. Multiple interface implementation lets a class promise to do several different sets of tasks.

When a class needs to follow rules from more than one interface.
When you want to organize different behaviors separately and combine them in one class.
When you want to make sure a class can be used in different ways depending on the interface.
When you want to add new features to a class without changing its main code.
When you want to write flexible and reusable code.
Syntax
C Sharp (C#)
class ClassName : Interface1, Interface2, Interface3
{
    // Implement all interface members here
}

You separate multiple interfaces with commas.

The class must provide code for all methods and properties from all interfaces.

Examples
This class Person promises to do both Walk and Talk by implementing two interfaces.
C Sharp (C#)
interface IWalk
{
    void Walk();
}

interface ITalk
{
    void Talk();
}

class Person : IWalk, ITalk
{
    public void Walk()
    {
        Console.WriteLine("Walking...");
    }

    public void Talk()
    {
        Console.WriteLine("Talking...");
    }
}
The MultiFunctionDevice can both print and scan because it implements two interfaces.
C Sharp (C#)
interface IPrinter
{
    void Print();
}

interface IScanner
{
    void Scan();
}

class MultiFunctionDevice : IPrinter, IScanner
{
    public void Print()
    {
        Console.WriteLine("Printing document");
    }

    public void Scan()
    {
        Console.WriteLine("Scanning document");
    }
}
Sample Program

This program shows a MediaDevice that can both play and record media by implementing two interfaces. When run, it calls both methods.

C Sharp (C#)
using System;

interface IPlayable
{
    void Play();
}

interface IRecordable
{
    void Record();
}

class MediaDevice : IPlayable, IRecordable
{
    public void Play()
    {
        Console.WriteLine("Playing media");
    }

    public void Record()
    {
        Console.WriteLine("Recording media");
    }
}

class Program
{
    static void Main()
    {
        MediaDevice device = new MediaDevice();
        device.Play();
        device.Record();
    }
}
OutputSuccess
Important Notes

All interface methods must be implemented in the class, or the class must be marked abstract.

Interfaces only have method signatures, no code inside them.

Multiple interface implementation helps keep code organized and flexible.

Summary

Multiple interface implementation lets a class follow many sets of rules.

Use commas to list interfaces after the class name.

The class must write code for all interface methods.

Practice

(1/5)
1.

What does it mean when a C# class implements multiple interfaces?

easy
A. The class inherits code from multiple classes.
B. The class agrees to provide code for all methods defined in those interfaces.
C. The class can only use one interface at a time.
D. The class automatically gets all properties from the interfaces without coding.

Solution

  1. Step 1: Understand interface implementation

    Interfaces define method signatures but no code. A class implementing them must provide the code.
  2. Step 2: Multiple interfaces require all methods

    When a class implements several interfaces, it must write code for every method in all interfaces.
  3. Final Answer:

    The class agrees to provide code for all methods defined in those interfaces. -> Option B
  4. Quick Check:

    Multiple interface implementation = implement all methods [OK]
Hint: Interfaces are contracts; class must fulfill all method contracts [OK]
Common Mistakes:
  • Thinking interfaces provide code to inherit
  • Believing class can skip some interface methods
  • Confusing interfaces with classes
2.

Which of the following is the correct syntax to declare a class Car implementing interfaces IMovable and IEngine?

?
easy
A. public class Car : IMovable, IEngine { }
B. public class Car implements IMovable, IEngine { }
C. public class Car inherits IMovable, IEngine { }
D. public class Car : IMovable & IEngine { }

Solution

  1. Step 1: Recall C# interface syntax

    In C#, a class uses a colon ':' followed by interface names separated by commas.
  2. Step 2: Check each option

    public class Car : IMovable, IEngine { } uses ':' and commas correctly. Options B and C use wrong keywords. public class Car : IMovable & IEngine { } uses '&' which is invalid.
  3. Final Answer:

    public class Car : IMovable, IEngine { } -> Option A
  4. Quick Check:

    Interfaces listed after ':' separated by commas [OK]
Hint: Use ':' and commas to list interfaces after class name [OK]
Common Mistakes:
  • Using 'implements' keyword (Java style)
  • Using '&' instead of commas
  • Using 'inherits' keyword incorrectly
3.

What will be the output of the following C# code?

interface IA { void Show(); }
interface IB { void Show(); }
class Demo : IA, IB {
    public void Show() { Console.WriteLine("Hello"); }
}
class Program {
    static void Main() {
        Demo d = new Demo();
        d.Show();
    }
}
medium
A. Hello
B. Compilation error due to ambiguous Show method
C. Runtime error
D. No output

Solution

  1. Step 1: Understand method implementation for multiple interfaces

    Both interfaces have Show method. The class Demo implements one Show method that satisfies both.
  2. Step 2: Check program output

    Main creates Demo and calls Show, which prints "Hello".
  3. Final Answer:

    Hello -> Option A
  4. Quick Check:

    Single method implements both interfaces' Show [OK]
Hint: One method can implement same method from multiple interfaces [OK]
Common Mistakes:
  • Expecting compile error for same method name
  • Thinking separate methods needed for each interface
  • Confusing interface method calls
4.

Identify the error in this code snippet:

interface IA { void Run(); }
interface IB { void Jump(); }
class Player : IA, IB {
    public void Run() { Console.WriteLine("Running"); }
}
medium
A. Run method should be private.
B. Class Player cannot implement two interfaces.
C. Interfaces cannot have methods.
D. Class Player must implement Jump method from IB interface.

Solution

  1. Step 1: Check interface methods

    IA requires Run(), IB requires Jump().
  2. Step 2: Verify class implementation

    Player implements Run() but misses Jump(), so it is incomplete.
  3. Final Answer:

    Class Player must implement Jump method from IB interface. -> Option D
  4. Quick Check:

    All interface methods must be implemented [OK]
Hint: Implement all interface methods to avoid errors [OK]
Common Mistakes:
  • Forgetting to implement all interface methods
  • Thinking interfaces can't have methods
  • Assuming methods can be private
5.

Given these interfaces and class:

interface IAlpha { void Action(); }
interface IBeta { void Action(); }
class Combined : IAlpha, IBeta {
    void IAlpha.Action() { Console.WriteLine("Alpha Action"); }
    void IBeta.Action() { Console.WriteLine("Beta Action"); }
}
class Program {
    static void Main() {
        Combined c = new Combined();
        // Which calls are valid?
    }
}

Which of the following calls will compile and print output?

hard
A. ((IBeta)c).Action(); // prints 'Beta Action'
B. c.Action(); // prints 'Alpha Action'
C. ((IAlpha)c).Action(); // prints 'Alpha Action'
D. c.Action(); // prints 'Beta Action'

Solution

  1. Step 1: Understand explicit interface implementation

    Combined class implements IAlpha.Action and IBeta.Action explicitly, so these methods are not accessible via class instance directly.
  2. Step 2: Check method calls

    Only calls through interface references like (IAlpha)c or (IBeta)c are valid. c.Action() is invalid and causes compile error.
  3. Final Answer:

    ((IAlpha)c).Action(); // prints 'Alpha Action' -> Option C
  4. Quick Check:

    Explicit interface methods need interface cast to call [OK]
Hint: Explicit interface methods require casting to interface type [OK]
Common Mistakes:
  • Calling explicit interface methods directly on class instance
  • Confusing explicit and implicit implementation
  • Assuming c.Action() works without cast