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C Sharp (C#)programming~15 mins

List generic collection in C Sharp (C#) - Mini Project: Build & Apply

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Working with List Generic Collection in C#
📖 Scenario: You are building a simple contact list application to store names of friends. You will use a List<string> to keep track of the names.
🎯 Goal: Create and manage a List<string> to add, check, and display friend names.
📋 What You'll Learn
Create a List of strings called friends with initial names
Add a new friend name to the list
Check if a specific friend name exists in the list
Display the total number of friends in the list
💡 Why This Matters
🌍 Real World
Lists are used in many applications to store collections of items like contacts, tasks, or products.
💼 Career
Understanding List collections is essential for software development jobs that involve data management and user data handling.
Progress0 / 4 steps
1
Create the initial List of friends
Create a List<string> called friends and initialize it with these exact names: "Alice", "Bob", "Charlie".
C Sharp (C#)
Hint

Use the List<string> constructor with curly braces to add initial names.

2
Add a new friend to the list
Add the friend name "Diana" to the existing friends list using the Add method.
C Sharp (C#)
Hint

Use friends.Add("Diana") to add the new name.

3
Check if a friend exists in the list
Create a boolean variable called hasBob that checks if the name "Bob" exists in the friends list using the Contains method.
C Sharp (C#)
Hint

Use bool hasBob = friends.Contains("Bob") to check presence.

4
Get the total number of friends
Create an integer variable called totalFriends and set it to the number of items in the friends list using the Count property.
C Sharp (C#)
Hint

Use friends.Count to get the number of items.

Practice

(1/5)
1. What is the main feature of a List<T> in C#?
easy
A. It can only hold a fixed number of items.
B. It stores only unique items and does not allow duplicates.
C. It automatically sorts items when added.
D. It stores items in order and allows easy access by position.

Solution

  1. Step 1: Understand List<T> behavior

    A List<T> stores items in the order they are added and allows access by index.
  2. Step 2: Compare options with List<T> features

    Only It stores items in order and allows easy access by position. correctly describes this behavior; others describe different collection types or incorrect features.
  3. Final Answer:

    It stores items in order and allows easy access by position. -> Option D
  4. Quick Check:

    List<T> = ordered, indexed collection [OK]
Hint: Remember List<T> keeps order and supports indexing [OK]
Common Mistakes:
  • Thinking List<T> enforces uniqueness
  • Assuming List<T> auto-sorts items
  • Believing List<T> has fixed size
2. Which of the following is the correct way to declare a List of integers in C#?
easy
A. List<int> numbers = new List<int>();
B. List numbers = new List<int>();
C. List<int> numbers = List<int>();
D. List<int> numbers = new List();

Solution

  1. Step 1: Recall correct List<T> syntax

    In C#, to declare a generic List, you must specify the type and use the new keyword with constructor.
  2. Step 2: Check each option for syntax correctness

    List<int> numbers = new List<int>(); correctly declares and initializes a List of int. Others miss type, constructor, or use wrong syntax.
  3. Final Answer:

    List<int> numbers = new List<int>(); -> Option A
  4. Quick Check:

    Generic List declaration = new List<T>() [OK]
Hint: Use new List<T>() with type specified [OK]
Common Mistakes:
  • Omitting new keyword
  • Not specifying generic type in constructor
  • Using non-generic List without type
3. What will be the output of this C# code?
var fruits = new List<string> { "apple", "banana", "cherry" };
fruits.RemoveAt(1);
Console.WriteLine(fruits[1]);
medium
A. banana
B. IndexOutOfRangeException
C. cherry
D. apple

Solution

  1. Step 1: Understand RemoveAt effect on list

    RemoveAt(1) removes the item at index 1, which is "banana". The list becomes ["apple", "cherry"].
  2. Step 2: Access the item at index 1 after removal

    After removal, fruits[1] is "cherry" because the list shifted left.
  3. Final Answer:

    cherry -> Option C
  4. Quick Check:

    RemoveAt shifts items left, fruits[1] = cherry [OK]
Hint: RemoveAt shifts list left; index 1 now points to next item [OK]
Common Mistakes:
  • Assuming removed item still exists
  • Expecting original index items unchanged
  • Confusing RemoveAt with Remove
4. Identify the error in this C# code snippet using List<string>:
List<string> colors = new List<string>();
colors.Add("red");
colors[1] = "blue";
Console.WriteLine(colors[1]);
medium
A. IndexOutOfRangeException because index 1 does not exist yet.
B. Syntax error in Add method usage.
C. Cannot assign string to List<string> element.
D. No error; code runs and prints 'blue'.

Solution

  1. Step 1: Analyze list content after Add

    After colors.Add("red"), list has one element at index 0 only.
  2. Step 2: Check assignment to colors[1]

    colors[1] does not exist yet, so assigning to it causes IndexOutOfRangeException.
  3. Final Answer:

    IndexOutOfRangeException because index 1 does not exist yet. -> Option A
  4. Quick Check:

    Assigning to non-existing index throws exception [OK]
Hint: List index must exist before assignment; use Add to add items [OK]
Common Mistakes:
  • Trying to assign to index without adding
  • Confusing Add and index assignment
  • Expecting automatic list expansion
5. Given a List<int> named numbers containing {1, 2, 3, 4, 5}, which code snippet correctly doubles each number in the list?
hard
A. numbers = numbers.Select(n => n * 2).ToList();
B. for (int i = 0; i < numbers.Count; i++) { numbers[i] = numbers[i] * 2; }
C. foreach (int n in numbers) { n = n * 2; }
D. numbers.ForEach(n => n = n * 2);

Solution

  1. Step 1: Understand how to modify List elements

    Using a for loop with index allows modifying elements directly by assignment.
  2. Step 2: Evaluate each option's effect

    for (int i = 0; i < numbers.Count; i++) { numbers[i] = numbers[i] * 2; } modifies elements in place. foreach (int n in numbers) { n = n * 2; } modifies copy of elements (no effect). numbers = numbers.Select(n => n * 2).ToList(); creates a new list but requires LINQ and ToList(). numbers.ForEach(n => n = n * 2); modifies copies in ForEach (no effect).
  3. Final Answer:

    for (int i = 0; i < numbers.Count; i++) { numbers[i] = numbers[i] * 2; } -> Option B
  4. Quick Check:

    Use for loop with index to update List elements [OK]
Hint: Use for loop with index to update List items directly [OK]
Common Mistakes:
  • Using foreach expecting to modify list items
  • Using ForEach with lambda that doesn't assign back
  • Not creating new list when using LINQ Select