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C Sharp (C#)programming~5 mins

LinkedList usage in C Sharp (C#) - Cheat Sheet & Quick Revision

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Recall & Review
beginner
What is a LinkedList in C#?
A LinkedList is a collection that stores elements in nodes, where each node points to the next and previous nodes, allowing efficient insertions and deletions anywhere in the list.
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beginner
How do you add an element at the start of a LinkedList in C#?
Use the AddFirst() method. For example: linkedList.AddFirst(value); adds a new node with the given value at the beginning.
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beginner
What method removes the last element from a LinkedList in C#?
The RemoveLast() method removes the last node from the LinkedList.
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beginner
How can you find a specific value in a LinkedList?
Use the Find(value) method. It returns the first node containing the value or null if not found.
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intermediate
Why might you choose a LinkedList over a List in C#?
LinkedList allows faster insertions and deletions in the middle of the list because it doesn't require shifting elements like a List does.
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Which method adds a new node at the end of a LinkedList in C#?
AInsert()
BAddFirst()
CAddLast()
DAppend()
What does the Find(value) method return if the value is not found in the LinkedList?
AReturns an empty node
BThrows an exception
CReturns -1
DReturns null
Which of these is NOT a benefit of using LinkedList over List?
AFaster random access by index
BFaster deletions in the middle
CEfficient memory usage for frequent insertions
DFaster insertions in the middle
How do you remove the first node from a LinkedList in C#?
ARemoveFirst()
BRemoveAt(0)
CDeleteFirst()
DRemove()
What type of data structure is a LinkedList?
AArray-based
BNode-based
CTree-based
DHash-based
Explain how to add and remove elements in a LinkedList in C#.
Think about methods that add or remove nodes at the start or end.
You got /5 concepts.
    Describe when and why you would use a LinkedList instead of a List in C#.
    Consider performance differences for different operations.
    You got /4 concepts.

      Practice

      (1/5)
      1. What is a key characteristic of a LinkedList in C#?
      easy
      A. It stores elements in nodes linked by references.
      B. It stores elements in a fixed-size array.
      C. It only allows adding elements at the end.
      D. It cannot remove elements once added.

      Solution

      1. Step 1: Understand LinkedList structure

        A LinkedList stores elements in nodes, where each node points to the next (and possibly previous) node.
      2. Step 2: Compare options with LinkedList behavior

        Only It stores elements in nodes linked by references. correctly describes this linked node structure; others describe arrays or incorrect behaviors.
      3. Final Answer:

        It stores elements in nodes linked by references. -> Option A
      4. Quick Check:

        LinkedList = nodes linked by references [OK]
      Hint: LinkedList uses nodes connected by links, not arrays. [OK]
      Common Mistakes:
      • Thinking LinkedList uses arrays internally
      • Assuming LinkedList only adds at the end
      • Believing LinkedList cannot remove elements
      2. Which of the following is the correct way to add an element at the start of a LinkedList<int> named list?
      easy
      A. list.AddStart(10);
      B. list.AddFirst(10);
      C. list.InsertAt(0, 10);
      D. list.PushFront(10);

      Solution

      1. Step 1: Recall LinkedList method names

        The method to add an element at the start is AddFirst.
      2. Step 2: Check each option's validity

        Only AddFirst is a valid LinkedList method; others are invalid or do not exist.
      3. Final Answer:

        list.AddFirst(10); -> Option B
      4. Quick Check:

        AddFirst adds at start [OK]
      Hint: Use AddFirst to add at the start of LinkedList. [OK]
      Common Mistakes:
      • Using non-existent methods like AddStart or PushFront
      • Confusing LinkedList with List methods
      • Trying to use InsertAt which LinkedList does not have
      3. What will be the output of this C# code?
      var list = new LinkedList<string>();
      list.AddLast("apple");
      list.AddFirst("banana");
      list.AddLast("cherry");
      foreach(var item in list) Console.Write(item + " ");
      medium
      A. banana apple cherry
      B. apple banana cherry
      C. cherry apple banana
      D. banana cherry apple

      Solution

      1. Step 1: Track insertion order

        First, "apple" is added last, so list: apple. Then "banana" added first, so list: banana, apple. Then "cherry" added last, so list: banana, apple, cherry.
      2. Step 2: Understand foreach iteration order

        Foreach iterates from first to last node, so output is "banana apple cherry ".
      3. Final Answer:

        banana apple cherry -> Option A
      4. Quick Check:

        First = banana, last = cherry [OK]
      Hint: AddFirst puts item at start; AddLast at end. [OK]
      Common Mistakes:
      • Assuming AddLast adds at start
      • Confusing order of AddFirst and AddLast
      • Expecting output in reverse order
      4. Identify the error in this code snippet:
      var list = new LinkedList<int>();
      list.AddFirst(1);
      list.AddLast(2);
      list.Remove(3);
      Console.WriteLine(list.Count);
      medium
      A. Remove(3) throws an exception because 3 is not in the list.
      B. Count property does not exist on LinkedList.
      C. AddFirst and AddLast methods are invalid for LinkedList.
      D. Remove(3) does nothing since 3 is not found; Count remains 2.

      Solution

      1. Step 1: Understand Remove behavior

        Remove(value) tries to remove the first node with that value. If not found, it does nothing and returns false; no exception is thrown.
      2. Step 2: Check Count after removal attempt

        Since 3 is not in the list, list remains with 2 elements; Count is 2.
      3. Final Answer:

        Remove(3) does nothing since 3 is not found; Count remains 2. -> Option D
      4. Quick Check:

        Remove missing value = no error, Count unchanged [OK]
      Hint: Remove missing item does not throw error, just returns false. [OK]
      Common Mistakes:
      • Expecting Remove to throw exception if item missing
      • Thinking AddFirst/AddLast are invalid
      • Assuming Count is not a property
      5. Given a LinkedList<int> with values 1, 2, 3, 4, 5, which code snippet correctly removes all even numbers from the list?
      hard
      A. foreach(var node in list) { if(node % 2 == 0) list.Remove(node); }
      B. for(int i = 0; i < list.Count; i++) { if(list.ElementAt(i) % 2 == 0) list.Remove(list.ElementAt(i)); }
      C. var current = list.First; while(current != null) { var next = current.Next; if(current.Value % 2 == 0) list.Remove(current); current = next; }
      D. list.RemoveAll(x => x % 2 == 0);

      Solution

      1. Step 1: Understand safe removal during iteration

        Removing nodes while iterating requires storing next node before removal to avoid invalid references.
      2. Step 2: Analyze each option

        foreach(var node in list) { if(node % 2 == 0) list.Remove(node); } uses foreach which throws error on modification during iteration. var current = list.First; while(current != null) { var next = current.Next; if(current.Value % 2 == 0) list.Remove(current); current = next; } correctly uses a while loop with next node saved. for(int i = 0; i < list.Count; i++) { if(list.ElementAt(i) % 2 == 0) list.Remove(list.ElementAt(i)); } uses ElementAt which is inefficient and unsafe. list.RemoveAll(x => x % 2 == 0); is invalid as LinkedList has no RemoveAll method.
      3. Final Answer:

        var current = list.First; while(current != null) { var next = current.Next; if(current.Value % 2 == 0) list.Remove(current); current = next; } -> Option C
      4. Quick Check:

        Use while loop with next saved to remove nodes safely [OK]
      Hint: Save next node before removal to avoid iteration errors. [OK]
      Common Mistakes:
      • Modifying list inside foreach causes runtime error
      • Using RemoveAll which LinkedList does not have
      • Using ElementAt which is inefficient and unsafe