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C++programming~30 mins

Runtime polymorphism in C++ - Mini Project: Build & Apply

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Runtime Polymorphism in C++
๐Ÿ“– Scenario: You are creating a simple program to demonstrate how different animals make different sounds. Each animal has a method to make a sound, but the exact sound depends on the animal type.
๐ŸŽฏ Goal: Build a C++ program that uses runtime polymorphism to call the correct makeSound() method for different animal objects.
๐Ÿ“‹ What You'll Learn
Create a base class called Animal with a virtual method makeSound().
Create two derived classes Dog and Cat that override makeSound().
Use a pointer of type Animal* to call makeSound() on objects of Dog and Cat.
Print the sounds made by the dog and cat.
๐Ÿ’ก Why This Matters
๐ŸŒ Real World
Runtime polymorphism helps programs decide which method to run while the program is running, like choosing the right animal sound depending on the animal.
๐Ÿ’ผ Career
Understanding runtime polymorphism is essential for writing flexible and maintainable object-oriented code used in software development jobs.
Progress0 / 4 steps
1
Create the base class Animal
Write a class called Animal with a public virtual method makeSound() that prints "Some generic animal sound".
C++
Hint

Use virtual keyword before makeSound() to allow overriding.

2
Create derived classes Dog and Cat
Add two classes Dog and Cat that inherit from Animal. Override makeSound() in Dog to print "Woof!" and in Cat to print "Meow!".
C++
Hint

Use override keyword to clearly show you are overriding the base class method.

3
Use Animal pointers to call makeSound()
Create two pointers of type Animal*, one pointing to a Dog object and the other to a Cat object. Use these pointers to call makeSound().
C++
Hint

Use new to create objects and call makeSound() through pointers.

4
Print the sounds made by Dog and Cat
Add cout statements to print the sounds made by the dog and cat when calling makeSound(). Run the program to see the output.
C++
Hint

Running the program should print Woof! and Meow! on separate lines.

Practice

(1/5)
1. What is the main purpose of virtual functions in C++ runtime polymorphism?
easy
A. To allocate memory for objects dynamically
B. To make functions run faster by avoiding function calls
C. To prevent any function from being overridden in derived classes
D. To allow derived classes to override base class methods and decide at runtime which method to call

Solution

  1. Step 1: Understand virtual functions role

    Virtual functions allow a base class to declare a function that derived classes can override.
  2. Step 2: Explain runtime decision

    At runtime, the program decides which overridden function to call based on the actual object type.
  3. Final Answer:

    To allow derived classes to override base class methods and decide at runtime which method to call -> Option D
  4. Quick Check:

    Virtual functions enable runtime method selection [OK]
Hint: Virtual means choose function at runtime, not compile time [OK]
Common Mistakes:
  • Thinking virtual speeds up function calls
  • Believing virtual prevents overriding
  • Confusing virtual with memory allocation
2. Which of the following is the correct syntax to declare a virtual function in a base class?
easy
A. void display() virtual;
B. void virtual display();
C. virtual void display();
D. virtual: void display();

Solution

  1. Step 1: Recall virtual function syntax

    The keyword virtual comes before the return type in the function declaration.
  2. Step 2: Match correct syntax

    virtual void display(); correctly places virtual before void display();
  3. Final Answer:

    virtual void display(); -> Option C
  4. Quick Check:

    Virtual keyword precedes return type [OK]
Hint: Virtual always goes before return type in declaration [OK]
Common Mistakes:
  • Placing virtual after function name
  • Using virtual as a label or modifier incorrectly
  • Missing semicolon after declaration
3. What will be the output of the following code?
class Base {
public:
    virtual void show() { std::cout << "Base"; }
};
class Derived : public Base {
public:
    void show() override { std::cout << "Derived"; }
};
int main() {
    Base* ptr = new Derived();
    ptr->show();
    delete ptr;
    return 0;
}
medium
A. Derived
B. Base
C. Compilation error
D. Runtime error

Solution

  1. Step 1: Identify virtual function usage

    The show() function in Base is virtual and overridden in Derived.
  2. Step 2: Understand pointer type and object type

    The pointer is of type Base* but points to a Derived object, so the overridden show() in Derived is called at runtime.
  3. Final Answer:

    Derived -> Option A
  4. Quick Check:

    Virtual function calls derived version [OK]
Hint: Virtual functions call derived method via base pointer [OK]
Common Mistakes:
  • Expecting base class method output
  • Confusing pointer type with object type
  • Ignoring virtual keyword effect
4. Identify the error in the following code snippet related to runtime polymorphism:
class Animal {
public:
    void sound() { std::cout << "Animal sound"; }
};
class Dog : public Animal {
public:
    void sound() { std::cout << "Bark"; }
};
int main() {
    Animal* a = new Dog();
    a->sound();
    delete a;
    return 0;
}
medium
A. Incorrect pointer type declaration
B. Missing virtual keyword in base class function
C. Derived class function should be static
D. Memory leak due to missing delete

Solution

  1. Step 1: Check base class function declaration

    The base class function sound() is not declared virtual, so no runtime polymorphism occurs.
  2. Step 2: Effect on function call

    Because sound() is not virtual, calling a->sound() calls the base class version, not the derived one.
  3. Final Answer:

    Missing virtual keyword in base class function -> Option B
  4. Quick Check:

    Virtual needed for runtime polymorphism [OK]
Hint: Base function must be virtual for polymorphism [OK]
Common Mistakes:
  • Assuming override works without virtual
  • Thinking pointer type causes error
  • Ignoring virtual keyword importance
5. Given the classes below, what will be the output when ptr->identify() is called?
class Shape {
public:
    virtual void identify() { std::cout << "Shape"; }
};
class Circle : public Shape {
public:
    void identify() override { std::cout << "Circle"; }
};
class ColoredCircle : public Circle {
public:
    void identify() override { std::cout << "Colored Circle"; }
};
int main() {
    Shape* ptr = new ColoredCircle();
    ptr->identify();
    delete ptr;
    return 0;
}
hard
A. Colored Circle
B. Circle
C. Shape
D. Compilation error due to multiple overrides

Solution

  1. Step 1: Trace virtual function overrides

    identify() is virtual in Shape, overridden in Circle, and again in ColoredCircle.
  2. Step 2: Determine actual object type at runtime

    The pointer ptr is of type Shape* but points to a ColoredCircle object, so the most derived override runs.
  3. Final Answer:

    Colored Circle -> Option A
  4. Quick Check:

    Most derived override called at runtime [OK]
Hint: Runtime calls most derived override in inheritance chain [OK]
Common Mistakes:
  • Expecting base or intermediate class output
  • Thinking multiple overrides cause errors
  • Ignoring virtual override chain
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10 questions~5 mineasy hard