Common array operations in C++ - Interactive Code Practice

Practice - 5 Tasks

1fill in blank

easy

Complete the code to declare an array of 5 integers.

C++

int numbers[[1]];

Drag options to blanks, or click blank then click option'

A5

B10

C0

D1

Attempts:

3 left

💡 Hint

Common Mistakes

Using 0 or 1 as array size will not allocate enough space.

The array size must be specified as 5 to hold five integers.

2fill in blank

medium

Complete the code to access the third element of the array.

C++

int third = numbers[[1]];

Drag options to blanks, or click blank then click option'

A3

B0

C2

D1

Attempts:

3 left

💡 Hint

Common Mistakes

Using 3 will cause out-of-bounds access.

Array indexing starts at 0, so the third element is at index 2.

3fill in blank

hard

Fix the error in the code to correctly initialize the array with values 1 to 5.

C++

int numbers[5] = {1, 2, 3, 4, [1];

Drag options to blanks, or click blank then click option'

A6

B5

C0

D7

Attempts:

3 left

💡 Hint

Common Mistakes

Using 6 or 7 adds incorrect values.

The last element should be 5 to complete the sequence from 1 to 5.

4fill in blank

hard

Fill both blanks to create a loop that sums all elements in the array.

C++

int sum = 0;
for (int i = [1]; i [2] 5; i++) {
    sum += numbers[i];
}

Drag options to blanks, or click blank then click option'

A0

B<

C<=

D1

Attempts:

3 left

💡 Hint

Common Mistakes

Starting at 1 skips the first element.

Using '<=' causes out-of-bounds access.

The loop starts at 0 and runs while i is less than 5 to cover all elements.

5fill in blank

hard

Fill all three blanks to create a loop that finds the maximum value in the array.

C++

int maxVal = numbers[[1]];
for (int i = [2]; i [3] 5; i++) {
    if (numbers[i] > maxVal) {
        maxVal = numbers[i];
    }
}

Drag options to blanks, or click blank then click option'

A0

B1

C<=

D<

Attempts:

3 left

💡 Hint

Common Mistakes

Starting loop at 0 compares first element to itself unnecessarily.

Using '<=' causes out-of-bounds.

Start maxVal with the first element at index 0, loop from index 1 while i is less than 5 (index 4 is last).